NEET Chemistry - Chapter 1

Some Basic Concepts of Chemistry

Original NEET chemistry notes on the mole concept, stoichiometry, concentration terms, empirical and molecular formulae, gas-volume relations, and redox-linked equivalent ideas.

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NEET Chemistry Mastery System

Study Some Basic Concepts of Chemistry Like a Topper

This chapter is not just for reading. Use it as a repeatable study workflow: concept map, formula conditions, easy examples, trap check, and mixed practice. That is the structure students need when moving from NCERT comfort to NEET-speed MCQs.

1. Build the Formula Map

Write every formula with units and conditions. Chemistry questions usually punish students who remember a formula but forget when it is valid.

2. Convert to the Core Quantity

For physical chemistry, convert mass, volume, concentration, or particles into moles first. For inorganic and organic chemistry, convert the question into trend, mechanism, exception, or named reaction.

3. Solve With Units Visible

Keep units beside every number. Unit tracking catches wrong molarity volume conversion, wrong gas constant, wrong oxidation number, and wrong equivalent factor.

4. Finish With the NEET Trap Check

Before selecting an option, check sign, units, approximation, limiting condition, exception, and whether the question asks atoms, molecules, moles, mass, or volume.

NCERT to MCQ Flow

1Definition
2Formula or trend
3Worked example
4NEET trap
5Timed practice

Easy Example Starters

Mole bridge

If a question gives mass, first write moles = given mass / molar mass. Most stoichiometry starts from that bridge.

Unit discipline

If volume is in mL for molarity, convert to litre before using M = n/V. A 250 mL solution is 0.25 L.

Trend questions

For periodic or inorganic trend MCQs, decide the direction first, then check exceptions instead of memorising isolated facts.

Organic logic

For reaction questions, identify the functional group, reagent role, attacking species, and major product stability.

Chemistry Mistake Clinic

Using atomic mass when the question needs molecular or formula mass.
Forgetting that molarity depends on solution volume, while molality depends on solvent mass.
Cancelling coefficients without converting the given data into moles.
Choosing a memorised exception before checking the basic trend.
Ignoring n-factor changes between acid-base, precipitation, and redox reactions.
Reading molecules as atoms in questions involving O2, N2, H2, P4, or S8.
Concept Block

1. Mole Concept, Avogadro Number, and Molar Mass

The mole is the chemist's counting unit. One mole of any substance contains exactly NA=6.022×1023N_A = 6.022\times10^{23} entities (atoms, molecules, ions, electrons — whatever the formula unit specifies). This number is called Avogadro's constant and it bridges the atomic world to the laboratory scale.

The Three-Way Mole Bridge

n=mM=NNA=V22.4 L  (at STP, ideal gas only)n=\frac{m}{M}=\frac{N}{N_A}=\frac{V}{22.4\text{ L}}\;(\text{at STP, ideal gas only})

nn = moles, mm = mass (g), MM = molar mass (g mol1^{-1}), NN = number of particles, VV = volume at STP.

Molar mass numerically equals the relative atomic/molecular mass but carries the unit g mol1^{-1}. Always add up the molar mass from atomic masses: M(H2SO4)=2(1)+32+4(16)=98M(\text{H}_2\text{SO}_4)=2(1)+32+4(16)=98 g mol1^{-1}.

QuantityFormulaUnit
Moles from massn=m/Mn = m/Mmol
Particles from molesN=n×NAN = n \times N_Adimensionless
Volume at STP (gas)V=n×22.4V = n \times 22.4L
NEET trap: 1 mol of O2_2 = 6.022×10236.022\times10^{23} molecules but 2×6.022×10232\times 6.022\times10^{23} atoms. 1 mol of P4_4 contains 4 mol of phosphorus atoms. Always clarify what entity is being counted.
Concept Block

2. Stoichiometry, Limiting Reagent, Yield, and Purity

A balanced chemical equation is a mole-ratio map. The coefficients directly give the molar ratios of reactants consumed and products formed.

The limiting reagent is the reactant that is completely consumed first, fixing the maximum theoretical yield. Every stoichiometry problem has exactly one workflow:

Standard 4-Step Stoichiometry Workflow

  1. Convert given masses/volumes to moles using n=m/Mn = m/M.
  2. Divide each reactant's moles by its coefficient. The smallest ratio identifies the limiting reagent.
  3. Use mole ratio from balanced equation to find product moles.
  4. Convert product moles back to mass or volume as required.
Percent yield=actual yieldtheoretical yield×100%\text{Percent yield}=\frac{\text{actual yield}}{\text{theoretical yield}}\times100\%

Pure mass=% purity100×sample mass\text{Pure mass}=\frac{\%\text{ purity}}{100}\times\text{sample mass}
Worked example: N2+3H22NH3N_2+3H_2\to 2NH_3. If 28 g N2N_2 and 3 g H2H_2 react: moles N2=1N_2=1, moles H2=1.5H_2=1.5. Ratio check: N2N_2 needs 1/1=1.0, H2H_2 needs 1.5/3=0.5. H2H_2 gives the smaller ratio — it is the limiting reagent. Product = 1.5/3×2=11.5/3\times2=1 mol NH3=17NH_3=17 g.
NEET trap: Theoretical yield is always calculated from the limiting reagent, NOT from the excess reagent.
Concept Block

3. Concentration Terms: Molarity, Molality, Mole Fraction, Normality

Solutions are described by six major concentration terms in NEET chemistry. Understanding which denominator each uses is the fastest way to distinguish them.

TermFormulaDenominatorTemp. dependent?
Molarity (M)mol solute / L solutionSolution volumeYes
Molality (m)mol solute / kg solventSolvent massNo
Mole fraction (x)ni/(n1+n2+)n_i/(n_1+n_2+\ldots)Total molesNo
Normality (N)equiv / L solutionSolution volumeYes
Mass percent (w/w)mass solute/mass soln×100Solution massNo
ppmmass solute/mass soln×106^6Solution massNo
Dilution: M1V1=M2V2M_1V_1 = M_2V_2 (moles of solute are conserved). Also: N1V1=N2V2N_1V_1 = N_2V_2.

Normality and n-factor: Normality = Molarity × n-factor. The n-factor for an acid equals its basicity (replaceable H+^+), for a base equals its acidity, and for a redox agent equals the change in oxidation number per formula unit.

NEET trap: Molarity decreases when temperature rises (solution expands), but molality and mole fraction stay constant. Use molality for colligative property problems.
Concept Block

4. Empirical Formula, Molecular Formula, and Average Atomic Mass

The empirical formula gives the simplest whole-number ratio of atoms. The molecular formula gives the actual number of atoms in one molecule and is always a whole-number multiple of the empirical formula.

Empirical-to-Molecular Formula Steps

  1. Convert mass % of each element to moles (divide by atomic mass).
  2. Divide all mole values by the smallest to get the simplest ratio.
  3. Multiply through by any integer needed to make all ratios whole numbers — this gives the empirical formula.
  4. Find empirical formula mass, then n=Mmolecule/Mempiricaln = M_{molecule}/M_{empirical}.
  5. Molecular formula = (empirical formula) × nn.
A=i(xiAi)\overline{A} = \sum_i (x_i \cdot A_i)

Average atomic mass = weighted mean of isotopic masses, where xix_i is fractional abundance of each isotope.

Classic example: Glucose C6_6H12_{12}O6_6 has empirical formula CH2_2O. Empirical mass = 30. Molecular mass = 180. So n=180/30=6n = 180/30 = 6. Molecular formula = (CH2_2O)6_6 = C6_6H12_{12}O6_6.
NEET trap: Empirical formula and molecular formula can be the same — e.g., H2OH_2O, NH3NH_3, CO2CO_2 are their own empirical and molecular formulae.
Concept Block

5. Gas Volume Relations, n-Factor, and NEET Exam Traps

At STP (0°C, 1 atm), 1 mole of any ideal gas occupies 22.4 L. This is the standard gas-volume bridge. Note: IUPAC now defines STP as 0°C and 1 bar, giving 22.7 L, but NEET papers continue to use 22.4 L — stick with that.

Moles of gas at STP=Volume (L)22.4\text{Moles of gas at STP}=\frac{\text{Volume (L)}}{22.4}

The n-factor (valence factor) determines equivalents and makes acid-base and redox titration calculations faster than full mole algebra.

Substance / Reactionn-factor
HCl (acid-base)1 (monoprotic)
H2_2SO4_4 (acid-base)2 (diprotic)
KMnO4_4 in acidic medium5 (Mn: +7 → +2)
KMnO4_4 in neutral/basic3 (Mn: +7 → +4)
K2_2Cr2_2O7_7 (acidic)6 (two Cr: +6 → +3)
Na2_2S2_2O3_3 (vs I2_2)1
Equivalents=n×n-factor,Equivalent mass=Mn-factor\text{Equivalents} = n\times n\text{-factor},\qquad \text{Equivalent mass}=\frac{M}{n\text{-factor}}

N1V1=N2V2(at equivalence point of titration)N_1V_1 = N_2V_2 \quad (\text{at equivalence point of titration})
Top 3 NEET traps in this chapter:
  1. Confusing molecules and atoms: 1 mol O2O_2 ≠ 1 mol O atoms.
  2. Using 22.4 L for liquids or solids — it applies only to ideal gases at STP.
  3. Using the same n-factor for KMnO4KMnO_4 regardless of medium — n-factor is medium-dependent.
Practice Tests

5 Chapter Tests of 25 Questions Each

Each test is original, NEET-aligned, and answer-backed. Use them as sectional revision instead of a single long mock so your weak subtopics become easier to identify quickly.

Test 1: Mole Basics

Moles, molar mass, particles, STP volume, and concentration definitions.

Test 2: Stoichiometry and Yield

Limiting reagent, purity, dilution, equivalent mass, and percent yield.

Test 3: Formula and Isotope Logic

Empirical formulae, isotopes, average mass, oxidation number, and n-factor.

Test 4: Gas and State Relations

Ideal-gas connections, diffusion, density, partial pressure, and real-gas basics.

Test 5: Mixed NEET Drill

Redox-linked equivalents, solution calculations, practical mole conversions, and traps.

Open Practice Tests
Verified question bank

Some Basic Concepts of Chemistry questions with answers

Open any of these 124 quality-checked NEET questions to review all four options, the correct answer, and the worked explanation.

  1. Question 1 · EasyMole idea
  2. Question 2 · EasyMole idea
  3. Question 3 · MediumMole idea
  4. Question 4 · EasyMolar mass
  5. Question 5 · MediumParticles
  6. Question 6 · MediumGas volume
  7. Question 7 · EasyComposition
  8. Question 8 · MediumEmpirical formula
  9. Question 9 · EasyStoichiometry basics
  10. Question 10 · MediumStoichiometry basics
  11. Question 11 · MediumMass relation
  12. Question 12 · EasyAtoms vs molecules
  13. Question 13 · EasyAtoms vs molecules
  14. Question 14 · MediumFormula mass
  15. Question 15 · HardGram-atom
  16. Question 16 · EasyConcentration
  17. Question 17 · MediumConcentration
  18. Question 18 · MediumStrength of solution
  19. Question 19 · HardEquivalent idea
  20. Question 20 · HardEquivalent idea
  21. Question 21 · EasyMole conversion
  22. Question 22 · MediumNEET trap
  23. Question 23 · MediumNEET trap
  24. Question 24 · HardVolume relation
  25. Question 25 · HardChapter logic
  26. Question 26 · EasyLimiting reagent
  27. Question 27 · MediumLimiting reagent
  28. Question 28 · MediumLimiting reagent
  29. Question 29 · EasyYield
  30. Question 30 · MediumExcess reagent
  31. Question 31 · MediumStoichiometry
  32. Question 32 · HardStoichiometry
  33. Question 33 · MediumPurity
  34. Question 34 · MediumPurity
  35. Question 35 · EasyProduct mass
  36. Question 36 · MediumProduct mass
  37. Question 37 · EasyMolarity
  38. Question 38 · MediumMolality
  39. Question 39 · MediumNormality
  40. Question 40 · EasyDilution
  41. Question 41 · MediumDilution
  42. Question 42 · HardEquivalent concept
  43. Question 43 · HardEquivalent concept
  44. Question 44 · EasyMixture logic
  45. Question 45 · MediumMass percent
  46. Question 46 · MediumAtomicity
  47. Question 47 · HardWater of crystallization
  48. Question 48 · HardPractical stoichiometry
  49. Question 49 · HardChapter logic
  50. Question 50 · EasyAtomic mass
  51. Question 51 · EasyIsotopes
  52. Question 52 · MediumIsobars
  53. Question 53 · MediumAverage mass
  54. Question 54 · HardAverage mass
  55. Question 55 · MediumEmpirical formula
  56. Question 56 · MediumEmpirical formula
  57. Question 57 · HardMolecular formula
  58. Question 58 · HardCombustion analysis
  59. Question 59 · HardCombustion analysis
  60. Question 60 · EasyOxidation state
  61. Question 61 · EasyOxidation state
  62. Question 62 · MediumOxidation state
  63. Question 63 · MediumOxidation state
  64. Question 64 · HardOxidation state
  65. Question 65 · EasyRedox basics
  66. Question 66 · EasyRedox basics
  67. Question 67 · MediumRedox agent
  68. Question 68 · MediumRedox agent
  69. Question 69 · Hardn-factor
  70. Question 70 · Hardn-factor
  71. Question 71 · HardEquivalent concept
  72. Question 72 · MediumIsotopic abundance
  73. Question 73 · MediumFormula determination
  74. Question 74 · HardChapter logic
  75. Question 75 · EasyGaseous laws
  76. Question 76 · EasyGaseous laws
  77. Question 77 · MediumGaseous laws
  78. Question 78 · EasyIdeal gas
  79. Question 79 · MediumGas constant
  80. Question 80 · HardDensity
  81. Question 81 · MediumVapour density
  82. Question 82 · EasyMixture of gases
  83. Question 83 · MediumPartial pressure
  84. Question 84 · MediumMole fraction
  85. Question 85 · EasyKinetic theory
  86. Question 86 · MediumKinetic theory
  87. Question 87 · MediumGraham law
  88. Question 88 · HardGraham law
  89. Question 89 · HardReal gases
  90. Question 90 · HardCompression factor
  91. Question 91 · MediumStoichiometric gas
  92. Question 92 · EasySTP use
  93. Question 93 · MediumTemperature scale
  94. Question 94 · HardGas mixture
  95. Question 95 · MediumEquation use
  96. Question 96 · HardState variables
  97. Question 97 · HardState variables
  98. Question 98 · MediumChapter logic
  99. Question 99 · HardNEET trap
  100. Question 100 · MediumRedox balance
  101. Question 101 · MediumRedox balance
  102. Question 102 · EasyOxidation number method
  103. Question 103 · HardOxidation number method
  104. Question 104 · MediumIonic equation
  105. Question 105 · MediumEquivalent relation
  106. Question 106 · MediumTitration
  107. Question 107 · Hardn-factor
  108. Question 108 · Hardn-factor
  109. Question 109 · EasyBalancing
  110. Question 110 · MediumOxidation number
  111. Question 111 · MediumOxidation number
  112. Question 112 · HardDisproportionation
  113. Question 113 · HardComproportionation
  114. Question 114 · MediumStoichiometric redox
  115. Question 115 · MediumStoichiometric redox
  116. Question 116 · MediumAcid-base vs redox
  117. Question 117 · HardData logic
  118. Question 118 · HardError trap
  119. Question 119 · MediumError trap
  120. Question 120 · MediumMass-volume link
  121. Question 121 · HardApplied stoichiometry
  122. Question 122 · HardApplied stoichiometry
  123. Question 123 · MediumApplied logic
  124. Question 124 · HardChapter integration
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