NEET Physics — Chapter 2

Basic Mathematics & Vectors

The mathematical toolkit that powers every chapter of NEET Physics. This chapter covers trigonometric identities and standard angles, basic differential and integral calculus with physical interpretation, quadratic equations and binomial approximation, scalars versus vectors, the parallelogram and triangle laws of addition, resolution of vectors into components, dot and cross products with their physical applications, and the most common NEET traps in vector problems.

1. Trigonometry Essentials

Trigonometry is the backbone of NEET Physics. Vector resolution, projectile motion, circular motion, waves, and optics all depend on your ability to read and apply sine, cosine, and tangent ratios instantly.

Standard Angle Values

Anglesincostan
010
30°1/2√3/21/√3
45°1/√21/√21
60°√3/21/2√3
90°10

Memory trick for sin: sin 0°, 30°, 45°, 60°, 90° = 0/2,  1/2,  2/2,  3/2,  4/2\sqrt{0}/2,\; \sqrt{1}/2,\; \sqrt{2}/2,\; \sqrt{3}/2,\; \sqrt{4}/2. For cos, read the table backwards.

Key Identities

sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1
sin2θ=2sinθcosθ\sin 2\theta = 2\sin\theta\cos\theta
cos2θ=cos2θsin2θ=12sin2θ=2cos2θ1\cos 2\theta = \cos^2\theta - \sin^2\theta = 1 - 2\sin^2\theta = 2\cos^2\theta - 1
tanθ=sinθcosθ,1+tan2θ=sec2θ\tan\theta = \frac{\sin\theta}{\cos\theta}, \quad 1 + \tan^2\theta = \sec^2\theta

Small Angle Approximation

When θ\theta is very small (much less than 1 radian, roughly below 10°), the first-order Taylor expansion gives:

sinθθ,tanθθ,cosθ1(θ in radians)\sin\theta \approx \theta, \quad \tan\theta \approx \theta, \quad \cos\theta \approx 1 \quad (\theta \text{ in radians})
NEET tip: The small angle approximation is used in simple pendulum derivation (T=2πL/gT = 2\pi\sqrt{L/g} holds only for small θ\theta), in optics for paraxial rays, and in wave mechanics. Whenever a NEET question says "small oscillations" or "small displacement", this approximation is active.

2. Basic Calculus for Physics

NEET Physics requires calculus at the conceptual level — you need to recognise when a quantity is a derivative or an integral of another, and apply a small set of standard rules. You do not need to solve complex integrals; you need to understand what derivatives and integrals mean physically.

Standard Derivatives

ddx(xn)=nxn1\frac{d}{dx}(x^n) = nx^{n-1}
ddx(sinx)=cosx,ddx(cosx)=sinx\frac{d}{dx}(\sin x) = \cos x, \quad \frac{d}{dx}(\cos x) = -\sin x
ddx(ex)=ex,ddx(lnx)=1x\frac{d}{dx}(e^x) = e^x, \quad \frac{d}{dx}(\ln x) = \frac{1}{x}
ddx(c)=0(constant rule),ddx(cf(x))=cdfdx\frac{d}{dx}(c) = 0 \quad (\text{constant rule}), \quad \frac{d}{dx}(cf(x)) = c\frac{df}{dx}

Standard Integrals

xndx=xn+1n+1+C(n1)\int x^n\,dx = \frac{x^{n+1}}{n+1} + C \quad (n \neq -1)
sinxdx=cosx+C,cosxdx=sinx+C\int \sin x\,dx = -\cos x + C, \quad \int \cos x\,dx = \sin x + C
exdx=ex+C,1xdx=lnx+C\int e^x\,dx = e^x + C, \quad \int \frac{1}{x}\,dx = \ln|x| + C

Physical Meaning of Derivatives

  • Velocity =dsdt= \dfrac{ds}{dt} — rate of change of displacement with time
  • Acceleration =dvdt=d2sdt2= \dfrac{dv}{dt} = \dfrac{d^2s}{dt^2} — rate of change of velocity
  • The slope of a displacement–time graph gives instantaneous velocity.
  • The slope of a velocity–time graph gives instantaneous acceleration.

Physical Meaning of Integration

  • s=vdts = \int v\,dt — displacement is the area under the vvtt graph.
  • v=adtv = \int a\,dt — change in velocity is the area under the aatt graph.
  • Work done = Fds\int \vec{F} \cdot d\vec{s} — area under the FFss graph.
Pro tip: NEET MCQs often show a graph and ask you to find the displacement, velocity, or work done. The answer is always the area under the curve or the slope. Master these two interpretations and you will pick up 3–4 marks per year without any complex calculation.

3. Quadratic Equations & Binomial Approximation

Quadratic Formula

For the equation ax2+bx+c=0ax^2 + bx + c = 0, the roots are:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The discriminant D=b24acD = b^2 - 4ac tells you the nature of roots:

  • D>0D > 0 — two distinct real roots (two physically possible answers; discard unphysical ones, e.g., negative time)
  • D=0D = 0 — one repeated real root
  • D<0D < 0 — no real roots (the physical scenario is impossible with the given values)
Caution: Projectile motion and kinematics problems often yield two roots from the quadratic — one for the "going up" phase and one for the "coming down" phase. Always check both and select the one consistent with the problem context. Negative time roots must be rejected.

Binomial Approximation

When x1|x| \ll 1 (x is much smaller than 1), the binomial theorem simplifies to:

(1+x)n1+nxfor x1(1 + x)^n \approx 1 + nx \quad \text{for } |x| \ll 1

Common forms you should recognise instantly:

1+x1+x2,11+x1x2\sqrt{1+x} \approx 1 + \frac{x}{2}, \quad \frac{1}{\sqrt{1+x}} \approx 1 - \frac{x}{2}
11+x1x,(1+x)212x\frac{1}{1+x} \approx 1 - x, \quad (1+x)^{-2} \approx 1 - 2x
ex1+x,ln(1+x)x(for small x)e^x \approx 1 + x, \quad \ln(1+x) \approx x \quad \text{(for small } x\text{)}

Physics example — gravity at height h:

g=GM(R+h)2=GMR2(1+hR)2g(12hR)when hRg' = \frac{GM}{(R+h)^2} = \frac{GM}{R^2}\left(1 + \frac{h}{R}\right)^{-2} \approx g\left(1 - \frac{2h}{R}\right) \quad \text{when } h \ll R
NEET tip: Binomial approximation appears in gravitation (g at height h), elasticity (small strain), and capacitance with slightly shifted plates. The key skill is rewriting the expression in (1+x)n(1+x)^n form. Once you see that shape, the approximation follows immediately.

4. Scalars vs Vectors

Every physical quantity is either a scalar or a vector. Getting this distinction right prevents a large class of conceptual errors in NEET.

Scalars — fully described by magnitude alone. No direction needed.

Examples: mass, temperature, energy, work, power, time, speed, electric charge, pressure, density.

Vectors — require both magnitude and direction for complete description.

Examples: displacement, velocity, acceleration, force, momentum, electric field, magnetic field, torque, angular momentum, weight.

Representation: A vector A\vec{A} has magnitude A|\vec{A}| (always 0\geq 0) and a direction. Graphically, it is an arrow: length = magnitude, orientation = direction.

Unit Vectors

A unit vector has magnitude exactly 1. It specifies direction only.

A^=AA\hat{A} = \frac{\vec{A}}{|\vec{A}|}

The Cartesian unit vectors are i^\hat{i} (along +x), j^\hat{j} (along +y), k^\hat{k} (along +z). They are mutually perpendicular: i^=j^=k^=1|\hat{i}| = |\hat{j}| = |\hat{k}| = 1.

Special Vectors

  • Equal vectors — same magnitude and same direction (position doesn't matter).
  • Negative vector of A\vec{A} is A-\vec{A}: same magnitude, opposite direction.
  • Zero (null) vector 0\vec{0}: magnitude zero, direction undefined. Example: displacement after returning to starting point.
  • Position vector r\vec{r}: locates a point relative to the origin. In 2D: r=xi^+yj^\vec{r} = x\hat{i} + y\hat{j}.
Caution: Speed is a scalar (magnitude of velocity). Distance is a scalar (magnitude of displacement only when motion is along a straight line without reversal). NEET frequently tests whether a quantity is scalar or vector — memorise both lists.

5. Vector Addition & Subtraction

Triangle Law of Vector Addition

Place the tail of B\vec{B} at the tip of A\vec{A}. The resultant R=A+B\vec{R} = \vec{A} + \vec{B} is the vector from the tail of A\vec{A} to the tip of B\vec{B}. This works for any number of vectors placed head-to-tail.

Parallelogram Law

Place both A\vec{A} and B\vec{B} at the same origin. Complete the parallelogram. The diagonal from the origin is R\vec{R}.

R=A2+B2+2ABcosθ|\vec{R}| = \sqrt{A^2 + B^2 + 2AB\cos\theta}
tanφ=BsinθA+Bcosθ\tan\varphi = \frac{B\sin\theta}{A + B\cos\theta}

where θ\theta = angle between A\vec{A} and B\vec{B}; φ\varphi = angle of R\vec{R} with A\vec{A}.

A⃗ B⃗ R⃗ θ φ Parallelogram Law: R⃗ = A⃗ + B⃗

Special cases of resultant magnitude:

Angle θResultant R
0° (parallel, same direction)A+BA + B (maximum)
90° (perpendicular)A2+B2\sqrt{A^2 + B^2}
180° (antiparallel)AB|A - B| (minimum)

Vector Subtraction

AB=A+(B)\vec{A} - \vec{B} = \vec{A} + (-\vec{B}). Reverse the direction of B\vec{B} and then add. The magnitude of AB\vec{A} - \vec{B} is:

AB=A2+B22ABcosθ|\vec{A} - \vec{B}| = \sqrt{A^2 + B^2 - 2AB\cos\theta}
NEET tip: When A = B and θ = 120°, the resultant equals A (or B). This is a frequently tested NEET result. At θ = 60°, resultant = 3A\sqrt{3}\,A. Memorise these standard angles.

6. Resolution of Vectors

Any vector can be split into components along chosen directions — usually the x and y axes. This is called resolution or decomposition of a vector. It is the most-used skill in all of mechanics.

Cartesian Components

For a vector A\vec{A} of magnitude AA making angle θ\theta with the positive x-axis:

Ax=Acosθ,Ay=AsinθA_x = A\cos\theta, \quad A_y = A\sin\theta
A=Axi^+Ayj^\vec{A} = A_x\hat{i} + A_y\hat{j}
A=Ax2+Ay2,θ=tan1 ⁣(AyAx)|\vec{A}| = \sqrt{A_x^2 + A_y^2}, \quad \theta = \tan^{-1}\!\left(\frac{A_y}{A_x}\right)
x y A⃗ Aₓ = A cosθ Ay = A sinθ θ

Adding vectors by components

To add A\vec{A} and B\vec{B}: add their x-components and y-components separately.

R=A+B=(Ax+Bx)i^+(Ay+By)j^\vec{R} = \vec{A} + \vec{B} = (A_x + B_x)\hat{i} + (A_y + B_y)\hat{j}
R=(Ax+Bx)2+(Ay+By)2R = \sqrt{(A_x+B_x)^2 + (A_y+B_y)^2}

Three-dimensional vectors

A=Axi^+Ayj^+Azk^,A=Ax2+Ay2+Az2\vec{A} = A_x\hat{i} + A_y\hat{j} + A_z\hat{k}, \quad |\vec{A}| = \sqrt{A_x^2 + A_y^2 + A_z^2}
Pro tip: Component method is far more reliable than the parallelogram law when adding three or more vectors, or when vectors are given in component form. Always prefer components when A=ai^+bj^\vec{A} = a\hat{i} + b\hat{j} notation is used in the question.

7. Dot Product (Scalar Product)

The dot product (scalar product) of two vectors A\vec{A} and B\vec{B} is a scalar quantity defined as:

AB=ABcosθ\vec{A} \cdot \vec{B} = AB\cos\theta

where θ\theta is the angle between the two vectors when placed tail-to-tail.

Properties of Dot Product

  • Commutative: AB=BA\vec{A} \cdot \vec{B} = \vec{B} \cdot \vec{A}
  • Distributive: A(B+C)=AB+AC\vec{A} \cdot (\vec{B} + \vec{C}) = \vec{A}\cdot\vec{B} + \vec{A}\cdot\vec{C}
  • Self dot product: AA=A2\vec{A}\cdot\vec{A} = A^2

Cartesian unit vector results:

i^i^=j^j^=k^k^=1\hat{i}\cdot\hat{i} = \hat{j}\cdot\hat{j} = \hat{k}\cdot\hat{k} = 1
i^j^=j^k^=k^i^=0\hat{i}\cdot\hat{j} = \hat{j}\cdot\hat{k} = \hat{k}\cdot\hat{i} = 0

Component form:

AB=AxBx+AyBy+AzBz\vec{A}\cdot\vec{B} = A_xB_x + A_yB_y + A_zB_z

Finding angle between two vectors:

cosθ=ABAB=AxBx+AyBy+AzBzAB\cos\theta = \frac{\vec{A}\cdot\vec{B}}{|\vec{A}||\vec{B}|} = \frac{A_xB_x + A_yB_y + A_zB_z}{AB}

Physical Applications

  • Work: W=Fd=FdcosθW = \vec{F}\cdot\vec{d} = Fd\cos\theta — zero when force is perpendicular to displacement
  • Power: P=Fv=FvcosθP = \vec{F}\cdot\vec{v} = Fv\cos\theta
  • Electric flux: ΦE=EA\Phi_E = \vec{E}\cdot\vec{A} (area vector)
  • Magnetic flux: ΦB=BA\Phi_B = \vec{B}\cdot\vec{A}
NEET tip: If AB=0\vec{A}\cdot\vec{B} = 0 and neither A\vec{A} nor B\vec{B} is a zero vector, then they must be perpendicular (θ=90°\theta = 90°). NEET uses this to test whether two given vectors are perpendicular — just compute the dot product.

8. Cross Product (Vector Product)

The cross product (vector product) of two vectors A\vec{A} and B\vec{B} is a vector quantity:

A×B=ABsinθ|\vec{A}\times\vec{B}| = AB\sin\theta

The direction is perpendicular to the plane of A\vec{A} and B\vec{B}, given by the right-hand rule.

Right-Hand Rule: Point fingers of the right hand along A\vec{A}, curl them towards B\vec{B}. The thumb points in the direction of A×B\vec{A}\times\vec{B}.

Properties

  • Anti-commutative: A×B=(B×A)\vec{A}\times\vec{B} = -(\vec{B}\times\vec{A})
  • Self cross product: A×A=0\vec{A}\times\vec{A} = \vec{0} (magnitude = A2sin0°=0A^2\sin 0° = 0)
  • Parallel or anti-parallel vectors: A×B=0\vec{A}\times\vec{B} = \vec{0}

Cartesian unit vector results (cyclic rule):

i^×j^=k^,j^×k^=i^,k^×i^=j^\hat{i}\times\hat{j} = \hat{k}, \quad \hat{j}\times\hat{k} = \hat{i}, \quad \hat{k}\times\hat{i} = \hat{j}
j^×i^=k^,k^×j^=i^,i^×k^=j^\hat{j}\times\hat{i} = -\hat{k}, \quad \hat{k}\times\hat{j} = -\hat{i}, \quad \hat{i}\times\hat{k} = -\hat{j}

Determinant formula:

A×B=i^j^k^AxAyAzBxByBz\vec{A}\times\vec{B} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \\ A_x & A_y & A_z \\ B_x & B_y & B_z\end{vmatrix}
=(AyBzAzBy)i^(AxBzAzBx)j^+(AxByAyBx)k^= (A_yB_z - A_zB_y)\hat{i} - (A_xB_z - A_zB_x)\hat{j} + (A_xB_y - A_yB_x)\hat{k}

Physical Applications

  • Torque: τ=r×F\vec{\tau} = \vec{r}\times\vec{F} — magnitude = rFsinθrF\sin\theta, direction by right-hand rule
  • Angular momentum: L=r×p=r×mv\vec{L} = \vec{r}\times\vec{p} = \vec{r}\times m\vec{v}
  • Magnetic force: F=q(v×B)\vec{F} = q(\vec{v}\times\vec{B}) — cross product gives the direction of the Lorentz force
  • Area of parallelogram formed by A\vec{A} and B\vec{B}: =A×B= |\vec{A}\times\vec{B}|
Caution: Cross product is not commutative — order matters. A×B\vec{A}\times\vec{B} points opposite to B×A\vec{B}\times\vec{A}. In torque and magnetic force problems, getting the direction wrong changes the sign of the answer. Always apply the right-hand rule explicitly.

9. NEET Exam Traps for Vectors

These are the most commonly tested vector concepts in NEET, along with the exact mistakes students make and how to avoid them.

Trap 1 — Maximum and minimum resultant

Rmax=A+B(θ=0°)R_{\max} = A + B \quad (\theta = 0°)
Rmin=AB(θ=180°)R_{\min} = |A - B| \quad (\theta = 180°)

Any resultant between AB|A-B| and A+BA+B is possible. NEET questions like "can the resultant be 7 if A=3 and B=5?" — answer: yes (35=278=3+5|3-5|=2 \leq 7 \leq 8=3+5). "Can it be 10?" — no.

Triangle inequality: For three vectors to form a closed triangle, each must be less than or equal to the sum of the other two.

Trap 2 — Dot product zero does not mean one vector is zero

AB=0\vec{A}\cdot\vec{B} = 0 means θ=90°\theta = 90° (perpendicular), not that either vector is zero. NEET options sometimes include "one of the vectors is a null vector" — this is wrong unless stated.

Trap 3 — Cross product of parallel vectors is zero

If A×B=0\vec{A}\times\vec{B} = \vec{0} and neither is a zero vector, the vectors are parallel or anti-parallel (θ=0°\theta = 0° or 180°180°). Example: a force parallel to displacement does zero torque.

Trap 4 — Null vector subtleties

  • A+(A)=0\vec{A} + (-\vec{A}) = \vec{0} — valid. But AA=0\vec{A} - \vec{A} = \vec{0} only when both are the same vector.
  • A null vector has zero magnitude but its direction is indeterminate — not "in all directions".
  • A×A=0\vec{A}\times\vec{A} = \vec{0} always (angle between a vector and itself is 0°, sin 0° = 0).

Trap 5 — Component confusion

  • The component of A\vec{A} along B\vec{B} is AcosθA\cos\theta (a scalar). The vector component is AcosθB^A\cos\theta\,\hat{B}.
  • A component can be larger than the vector if the angle is imaginary — impossible. Components are always \leq magnitude.
  • If Ax=AA_x = A, then Ay=0A_y = 0 (θ=0°\theta = 0°, vector along x-axis).
Pro tip: Before attempting a vector MCQ, identify: (a) is the answer a scalar or vector? (b) what is the angle between the vectors? (c) do I need the magnitude formula, or the component method? These three questions eliminate 80% of errors.

10. Quick Formula Sheet

Use this as a rapid revision reference before the exam. Every formula here has appeared in NEET at least once in the past five years.

Trigonometry

Identity / ApproximationExpression
Pythagorean identitysin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1
Double angle (sin)sin2θ=2sinθcosθ\sin 2\theta = 2\sin\theta\cos\theta
Double angle (cos)cos2θ=12sin2θ\cos 2\theta = 1 - 2\sin^2\theta
Small anglesinθtanθθ,  cosθ1\sin\theta \approx \tan\theta \approx \theta,\; \cos\theta \approx 1
Binomial approx(1+x)n1+nx(1+x)^n \approx 1 + nx for x1|x|\ll 1

Calculus

DerivativeResultIntegralResult
d(xn)/dxd(x^n)/dxnxn1nx^{n-1}xndx\int x^n\,dxxn+1/(n+1)x^{n+1}/(n+1)
d(sinx)/dxd(\sin x)/dxcosx\cos xsinxdx\int \sin x\,dxcosx-\cos x
d(cosx)/dxd(\cos x)/dxsinx-\sin xcosxdx\int \cos x\,dxsinx\sin x
d(ex)/dxd(e^x)/dxexe^xexdx\int e^x\,dxexe^x
d(lnx)/dxd(\ln x)/dx1/x1/x1/xdx\int 1/x\,dxlnx\ln|x|

Vector Operations

OperationFormula
Resultant (parallelogram)R=A2+B2+2ABcosθR = \sqrt{A^2+B^2+2AB\cos\theta}
Direction of resultanttanφ=Bsinθ/(A+Bcosθ)\tan\varphi = B\sin\theta/(A+B\cos\theta)
ResolutionAx=Acosθ,  Ay=AsinθA_x = A\cos\theta,\; A_y = A\sin\theta
Magnitude from componentsA=Ax2+Ay2+Az2A = \sqrt{A_x^2+A_y^2+A_z^2}
Unit vectorA^=A/A\hat{A} = \vec{A}/|\vec{A}|
Dot productAB=ABcosθ=AxBx+AyBy+AzBz\vec{A}\cdot\vec{B} = AB\cos\theta = A_xB_x+A_yB_y+A_zB_z
Cross product magnitudeA×B=ABsinθ|\vec{A}\times\vec{B}| = AB\sin\theta
Angle between vectorscosθ=AB/(AB)\cos\theta = \vec{A}\cdot\vec{B}/(AB)
WorkW=Fd=FdcosθW = \vec{F}\cdot\vec{d} = Fd\cos\theta
Torqueτ=rFsinθ|\vec{\tau}| = rF\sin\theta
Final NEET tip: This chapter contributes to nearly every chapter of NEET Physics — kinematics, laws of motion, work-energy, rotational motion, electrostatics, and magnetism all use vectors and basic calculus. Time spent mastering this chapter compounds: each mark here saves time in five subsequent chapters.
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