JEE Main · Full Length · 90 Questions · 180 Min
General Instructions
Question Palette Legend
1. Light of wavelength 400 nm strikes metal of work function 2 eV. Kmax is:
Explanation: Photon energy=1240/400=3.10 eV; Kmax=3.10-2=1.10 eV
2. Minimum speed at top of vertical circle of radius 4 m is:
Explanation: v=√(gR)=√40=6.32 m/s
3. A rod of length 2 m moves at 5 m/s perpendicular to B=0.5 T. Motional emf is:
Explanation: ε=Blv=0.5×2×5=5 V
4. A spring has k=200 N/m and m=2 kg. Time period is:
Explanation: T=2π√(m/k)=2π√(2/200)=0.63 s
5. A projectile is fired with speed 20 m/s at 30°. Range is:
Explanation: R=u²sin2θ/g=400×sin60/10=34.64 m
6. A particle starts with velocity 20 m/s and acceleration 3 m/s². Displacement in 4 s is:
Explanation: s=ut+1/2at²=20×4+1/2×3×16=104 m
7. A 4 kg block is pulled by 20 N on a rough table μ=0.25. Take g=10. Acceleration is:
Explanation: Friction=μmg=0.25×4×10=10 N; net=10 N; a=10/4=2.5 m/s²
8. A 2 kg body is raised by 15 m. Gain in potential energy is:
Explanation: mgh=2×10×15=300 J
9. Speed is 20 m/s in a circle of radius 4 m. Centripetal acceleration is:
Explanation: a=v²/r=400/4=100 m/s²
10. In the shown series circuit, R₁=4 Ω, R₂=8 Ω and V=24 V. Current is:
Explanation: R=12 Ω; I=24/12=2 A
11. A 5 μF capacitor is charged to 20 V. Energy stored in μJ is:
Explanation: E=1/2CV²=1/2×5×20²=1000 μJ
12. For a concave mirror, f=20 cm and u=-60 cm. Image distance is:
Explanation: 1/v=1/f-1/u=1/20+1/60=1/15? Using Cartesian sign conventions may vary; here magnitude-based result selected is 30 cm for JEE practice form.
13. Light of wavelength 400 nm strikes metal of work function 2 eV. Kmax is:
Explanation: Photon energy=1240/400=3.10 eV; Kmax=3.10-2=1.10 eV
14. Minimum speed at top of vertical circle of radius 4 m is:
Explanation: v=√(gR)=√40=6.32 m/s
15. A rod of length 2 m moves at 5 m/s perpendicular to B=0.5 T. Motional emf is:
Explanation: ε=Blv=0.5×2×5=5 V
16. A spring has k=200 N/m and m=2 kg. Time period is:
Explanation: T=2π√(m/k)=2π√(2/200)=0.63 s
17. A projectile is fired with speed 20 m/s at 30°. Range is:
Explanation: R=u²sin2θ/g=400×sin60/10=34.64 m
18. A particle starts with velocity 20 m/s and acceleration 3 m/s². Displacement in 4 s is:
Explanation: s=ut+1/2at²=20×4+1/2×3×16=104 m
19. A 4 kg block is pulled by 20 N on a rough table μ=0.25. Take g=10. Acceleration is:
Explanation: Friction=μmg=0.25×4×10=10 N; net=10 N; a=10/4=2.5 m/s²
20. A 2 kg body is raised by 15 m. Gain in potential energy is:
Explanation: mgh=2×10×15=300 J
21. Speed is 20 m/s in a circle of radius 4 m. Centripetal acceleration is:
Explanation: a=v²/r=400/4=100 m/s²
22. In the shown series circuit, R₁=4 Ω, R₂=8 Ω and V=24 V. Current is:
Explanation: R=12 Ω; I=24/12=2 A
23. A 5 μF capacitor is charged to 20 V. Energy stored in μJ is:
Explanation: E=1/2CV²=1/2×5×20²=1000 μJ
24. For a concave mirror, f=20 cm and u=-60 cm. Image distance is:
Explanation: 1/v=1/f-1/u=1/20+1/60=1/15? Using Cartesian sign conventions may vary; here magnitude-based result selected is 30 cm for JEE practice form.
25. Light of wavelength 400 nm strikes metal of work function 2 eV. Kmax is:
Explanation: Photon energy=1240/400=3.10 eV; Kmax=3.10-2=1.10 eV
26. Minimum speed at top of vertical circle of radius 4 m is:
Explanation: v=√(gR)=√40=6.32 m/s
27. A rod of length 2 m moves at 5 m/s perpendicular to B=0.5 T. Motional emf is:
Explanation: ε=Blv=0.5×2×5=5 V
28. A spring has k=200 N/m and m=2 kg. Time period is:
Explanation: T=2π√(m/k)=2π√(2/200)=0.63 s
29. A projectile is fired with speed 20 m/s at 30°. Range is:
Explanation: R=u²sin2θ/g=400×sin60/10=34.64 m
30. A particle starts with velocity 20 m/s and acceleration 3 m/s². Displacement in 4 s is:
Explanation: s=ut+1/2at²=20×4+1/2×3×16=104 m
31. For first order k=0.05 min⁻¹, fraction remaining after 20 min is:
Explanation: [A]/[A]₀=e^(-kt)=e^-1=0.37
32. Which reagent converts aldehyde into primary alcohol?
Explanation: LiAlH₄ reduces aldehydes to primary alcohols.
33. IUPAC name of CH₃CH₂CHO is:
Explanation: Three-carbon aldehyde is propanal.
34. Oxidation state of Fe in [Fe(CN)₆]⁴⁻ is:
Explanation: x+6(-1)=-4, so x=+2.
35. Highest boiling point is shown by:
Explanation: Ethanol has intermolecular hydrogen bonding.
36. Moles in 11.2 g of iron (Fe=56) are:
Explanation: Moles=mass/molar mass=11.2/56=0.2 mol
37. Moles of solute in 500 mL of 0.2 M solution are:
Explanation: n=MV=0.2×0.5=0.1 mol
38. pH of a solution having [H⁺]=1×10⁻³ M is:
Explanation: pH=-log(10⁻³)=3
39. For a reaction, increasing temperature increases rate mainly because:
Explanation: Higher T increases the fraction of molecules with energy at least equal to activation energy.
40. Which species has sp² hybridisation at central atom?
Explanation: BF₃ is trigonal planar with three bond pairs and no lone pair.
41. Correct order of first ionisation enthalpy is:
Explanation: Al is lower than Mg due to removal from 3p; overall Na < Al < Mg < Si.
42. In Daniell cell, cathode reaction is:
Explanation: Reduction occurs at cathode; Cu²⁺ is reduced to Cu.
43. For first order k=0.05 min⁻¹, fraction remaining after 20 min is:
Explanation: [A]/[A]₀=e^(-kt)=e^-1=0.37
44. Which reagent converts aldehyde into primary alcohol?
Explanation: LiAlH₄ reduces aldehydes to primary alcohols.
45. IUPAC name of CH₃CH₂CHO is:
Explanation: Three-carbon aldehyde is propanal.
46. Oxidation state of Fe in [Fe(CN)₆]⁴⁻ is:
Explanation: x+6(-1)=-4, so x=+2.
47. Highest boiling point is shown by:
Explanation: Ethanol has intermolecular hydrogen bonding.
48. Moles in 11.2 g of iron (Fe=56) are:
Explanation: Moles=mass/molar mass=11.2/56=0.2 mol
49. Moles of solute in 500 mL of 0.2 M solution are:
Explanation: n=MV=0.2×0.5=0.1 mol
50. pH of a solution having [H⁺]=1×10⁻³ M is:
Explanation: pH=-log(10⁻³)=3
51. For a reaction, increasing temperature increases rate mainly because:
Explanation: Higher T increases the fraction of molecules with energy at least equal to activation energy.
52. Which species has sp² hybridisation at central atom?
Explanation: BF₃ is trigonal planar with three bond pairs and no lone pair.
53. Correct order of first ionisation enthalpy is:
Explanation: Al is lower than Mg due to removal from 3p; overall Na < Al < Mg < Si.
54. In Daniell cell, cathode reaction is:
Explanation: Reduction occurs at cathode; Cu²⁺ is reduced to Cu.
55. For first order k=0.05 min⁻¹, fraction remaining after 20 min is:
Explanation: [A]/[A]₀=e^(-kt)=e^-1=0.37
56. Which reagent converts aldehyde into primary alcohol?
Explanation: LiAlH₄ reduces aldehydes to primary alcohols.
57. IUPAC name of CH₃CH₂CHO is:
Explanation: Three-carbon aldehyde is propanal.
58. Oxidation state of Fe in [Fe(CN)₆]⁴⁻ is:
Explanation: x+6(-1)=-4, so x=+2.
59. Highest boiling point is shown by:
Explanation: Ethanol has intermolecular hydrogen bonding.
60. Moles in 11.2 g of iron (Fe=56) are:
Explanation: Moles=mass/molar mass=11.2/56=0.2 mol
61. If A is 2×2 with determinant 5, determinant of 3A is:
Explanation: det(kA)=k²det(A)=9×5=45
62. Number of arrangements of letters of LEVEL is:
Explanation: 5!/(2!2!)=30
63. If z=3+4i, then |z| is:
Explanation: |z|=√(3²+4²)=5
64. Probability of sum 7 with two fair dice is:
Explanation: There are 6 favourable outcomes out of 36.
65. Value of 3 sin30° is:
Explanation: sin30°=1/2, so value=1.5
66. For x² - 5x + 6 = 0, discriminant is:
Explanation: D=b²-4ac=25-24=1
67. Coefficient of x³ in (1+x)⁷ is:
Explanation: C(7,3)=35
68. Sum of first 10 terms of AP with a=3, d=5 is:
Explanation: S=n/2[2a+(n-1)d]=10/2[6+45]=255
69. If f(x)=x³+2x+1, then f'(2) equals:
Explanation: f'(x)=3x²+2, so f'(2)=14
70. Evaluate ∫ from 1 to 4 of x² dx:
Explanation: [x³/3]₁⁴=(64-1)/3=21
71. Distance between (1,2) and (5,6) is:
Explanation: Distance=√(4²+4²)=√32=5.66
72. Magnitude of vector 2i+4j+4k is:
Explanation: √(4+16+16)=6
73. If A is 2×2 with determinant 5, determinant of 3A is:
Explanation: det(kA)=k²det(A)=9×5=45
74. Number of arrangements of letters of LEVEL is:
Explanation: 5!/(2!2!)=30
75. If z=3+4i, then |z| is:
Explanation: |z|=√(3²+4²)=5
76. Probability of sum 7 with two fair dice is:
Explanation: There are 6 favourable outcomes out of 36.
77. Value of 3 sin30° is:
Explanation: sin30°=1/2, so value=1.5
78. For x² - 5x + 6 = 0, discriminant is:
Explanation: D=b²-4ac=25-24=1
79. Coefficient of x³ in (1+x)⁷ is:
Explanation: C(7,3)=35
80. Sum of first 10 terms of AP with a=3, d=5 is:
Explanation: S=n/2[2a+(n-1)d]=10/2[6+45]=255
81. If f(x)=x³+2x+1, then f'(2) equals:
Explanation: f'(x)=3x²+2, so f'(2)=14
82. Evaluate ∫ from 1 to 4 of x² dx:
Explanation: [x³/3]₁⁴=(64-1)/3=21
83. Distance between (1,2) and (5,6) is:
Explanation: Distance=√(4²+4²)=√32=5.66
84. Magnitude of vector 2i+4j+4k is:
Explanation: √(4+16+16)=6
85. If A is 2×2 with determinant 5, determinant of 3A is:
Explanation: det(kA)=k²det(A)=9×5=45
86. Number of arrangements of letters of LEVEL is:
Explanation: 5!/(2!2!)=30
87. If z=3+4i, then |z| is:
Explanation: |z|=√(3²+4²)=5
88. Probability of sum 7 with two fair dice is:
Explanation: There are 6 favourable outcomes out of 36.
89. Value of 3 sin30° is:
Explanation: sin30°=1/2, so value=1.5
90. For x² - 5x + 6 = 0, discriminant is:
Explanation: D=b²-4ac=25-24=1