Compound Interest Test 10
Bilingual timed test with proper DI visuals, clean Hindi and detailed solutions.
Compound Interest Test 10
25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.
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- Compound Interest — Variable rate CI
1. Kochi branch invests ₹21,000 for two years at variable compound rates 11% and 6%. Find total CI. / Kochi शाखा ने ₹21,000 को दो वर्षों के लिए 11% और 6% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹3,908.60
- B. ₹3,570
- C. ₹3,508.60
- D. ₹3,708.60 (Correct)
Explanation: Amount = P(1+11/100)(1+6/100). CI = ₹3,708.60. / राशि = P(1+11/100)(1+6/100)। CI = ₹3,708.60।
- Compound Interest — Excess CI
2. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹22,000. (Set 182) / ₹22,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 182)
- A. ₹266.80
- B. ₹316.80 (Correct)
- C. ₹366.80
- D. ₹5,280
Explanation: Excess = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80. / अधिकता = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80।
- Compound Interest — Quarterly compounding
3. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 183) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 183)
- A. ₹1,800
- B. ₹1,942.63
- C. ₹1,822.63
- D. ₹1,882.63 (Correct)
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
- Compound Interest — Three-year amount
4. The amount after 3 years on ₹10,000 at 10% annual compounding is: (Set 184) / ₹10,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 184)
- A. ₹13,000
- B. ₹13,210
- C. ₹13,310 (Correct)
- D. ₹13,410
Explanation: Amount = 10000×1.1^3 = ₹13,310. / राशि = 10000×1.1^3 = ₹13,310।
- Compound Interest — Principal from CI amount
5. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 185) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 185)
- A. ₹20,500
- B. ₹19,500
- C. ₹20,166.67
- D. ₹20,000 (Correct)
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
- Compound Interest — Net CI
6. A deposit earns CI at 15% for 2 years on ₹20,000. If ₹150 service charge is deducted from interest, what net interest remains? / ₹20,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹150 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹6,300 (Correct)
- B. ₹6,450
- C. ₹6,200
- D. ₹6,400
Explanation: CI = ₹6,450. Net interest = ₹6,450−₹150 = ₹6,300. / CI = ₹6,450। शुद्ध ब्याज = ₹6,450−₹150 = ₹6,300।
- Compound Interest — Compound amount vs SI amount
7. For ₹28,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 187) / ₹28,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 187)
- A. ₹294
- B. ₹280 (Correct)
- C. ₹380
- D. ₹180
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹280. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹280।
- Compound Interest — Half-yearly two years
8. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 188) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 188)
- A. ₹9,946.10
- B. ₹9,746.10 (Correct)
- C. ₹9,546.10
- D. ₹8,400
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
- Compound Interest — Growth model
9. A savings balance of ₹25,000 grows by 13% compound rate each year. What is the balance after 2 years? (Set 189) / ₹25,000 की बचत राशि प्रति वर्ष 13% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 189)
- A. ₹31,922.50 (Correct)
- B. ₹31,500
- C. ₹32,022.50
- D. ₹31,822.50
Explanation: Balance = 25000(1+13/100)^2 = ₹31,922.50. / शेष राशि = 25000(1+13/100)^2 = ₹31,922.50।
- Compound Interest — Three-year CI
10. Find the compound interest on ₹15,000 at 5% per annum for 3 years. / ₹15,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें।
- A. ₹2,514.38
- B. ₹2,250
- C. ₹2,214.38
- D. ₹2,364.38 (Correct)
Explanation: CI = P[(1+r/100)^3−1] = ₹2,364.38. / CI = P[(1+r/100)^3−1] = ₹2,364.38।
- Compound Interest — Variable rate CI
11. Lucknow branch invests ₹17,000 for two years at variable compound rates 12% and 8%. Find total CI. / Lucknow शाखा ने ₹17,000 को दो वर्षों के लिए 12% और 8% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹3,563.20 (Correct)
- B. ₹3,763.20
- C. ₹3,363.20
- D. ₹3,400
Explanation: Amount = P(1+12/100)(1+8/100). CI = ₹3,563.20. / राशि = P(1+12/100)(1+8/100)। CI = ₹3,563.20।
- Compound Interest — Excess CI
12. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹20,000. (Set 192) / ₹20,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 192)
- A. ₹4,800
- B. ₹288 (Correct)
- C. ₹338
- D. ₹238
Explanation: Excess = P(r/100)^2 = 20000×(12/100)^2 = ₹288. / अधिकता = P(r/100)^2 = 20000×(12/100)^2 = ₹288।
- Compound Interest — Quarterly compounding
13. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 193) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 193)
- A. ₹1,942.63
- B. ₹1,800
- C. ₹1,882.63 (Correct)
- D. ₹1,822.63
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
- Compound Interest — Three-year amount
14. The amount after 3 years on ₹12,000 at 10% annual compounding is: (Set 194) / ₹12,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 194)
- A. ₹15,600
- B. ₹15,872
- C. ₹16,072
- D. ₹15,972 (Correct)
Explanation: Amount = 12000×1.1^3 = ₹15,972. / राशि = 12000×1.1^3 = ₹15,972।
- Compound Interest — Principal from CI amount
15. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 195) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 195)
- A. ₹20,500
- B. ₹19,500
- C. ₹20,000 (Correct)
- D. ₹20,166.67
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
- Compound Interest — Net CI
16. A deposit earns CI at 15% for 2 years on ₹16,000. If ₹200 service charge is deducted from interest, what net interest remains? / ₹16,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹200 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹5,060
- B. ₹5,160
- C. ₹4,860
- D. ₹4,960 (Correct)
Explanation: CI = ₹5,160. Net interest = ₹5,160−₹200 = ₹4,960. / CI = ₹5,160। शुद्ध ब्याज = ₹5,160−₹200 = ₹4,960।
- Compound Interest — Compound amount vs SI amount
17. For ₹26,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 197) / ₹26,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 197)
- A. ₹360
- B. ₹160
- C. ₹273
- D. ₹260 (Correct)
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹260. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹260।
- Compound Interest — Half-yearly two years
18. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 198) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 198)
- A. ₹9,546.10
- B. ₹8,400
- C. ₹9,946.10
- D. ₹9,746.10 (Correct)
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
- Compound Interest — Growth model
19. A savings balance of ₹23,000 grows by 11% compound rate each year. What is the balance after 2 years? (Set 199) / ₹23,000 की बचत राशि प्रति वर्ष 11% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 199)
- A. ₹28,338.30 (Correct)
- B. ₹28,060
- C. ₹28,238.30
- D. ₹28,438.30
Explanation: Balance = 23000(1+11/100)^2 = ₹28,338.30. / शेष राशि = 23000(1+11/100)^2 = ₹28,338.30।
- Compound Interest — Three-year CI
20. Find the compound interest on ₹16,000 at 5% per annum for 3 years. / ₹16,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें।
- A. ₹2,400
- B. ₹2,672
- C. ₹2,372
- D. ₹2,522 (Correct)
Explanation: CI = P[(1+r/100)^3−1] = ₹2,522. / CI = P[(1+r/100)^3−1] = ₹2,522।
- Compound Interest — Percentage / प्रतिशत
21. 18% of 500 is: / 500 का 18% कितना है?
- A. 80
- B. 90 (Correct)
- C. 100
- D. 110
Explanation: 18% = 18/100, so answer = 90. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।
- Compound Interest — Profit-Loss / लाभ-हानि
22. An article bought for Rs 950 is sold at 20% profit. Find SP. / Rs 950 में खरीदी वस्तु 20% लाभ पर बेची गई। SP ज्ञात करें।
- A. Rs 1100
- B. Rs 1140 (Correct)
- C. Rs 1180
- D. Rs 1220
Explanation: SP = CP x (100 + profit%)/100 = 950 x 120/100 = Rs 1140. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।
- Compound Interest — Time & Work / समय और कार्य
23. A finishes a work in 24 days and B in 30 days. Together they finish in: / A 24 दिन और B 30 दिन में काम पूरा करते हैं। साथ में समय?
- A. 12.3 days
- B. 13.3 days (Correct)
- C. 14.3 days
- D. 15.3 days
Explanation: Combined time = ab/(a+b) = 24 x 30 / 54 = 13.3 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।
- Compound Interest — Speed Conversion / चाल परिवर्तन
24. 72 km/h equals: / 72 किमी/घंटा बराबर है:
- A. 17 m/s
- B. 20 m/s (Correct)
- C. 23 m/s
- D. 25 m/s
Explanation: km/h to m/s conversion uses x 5/18. 72 x 5/18 = 20. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।
- Compound Interest — Simplification / सरलीकरण
25. Simplify: 21 x 17 + 21 - 17. / सरल करें: 21 x 17 + 21 - 17.
- A. 353
- B. 361 (Correct)
- C. 369
- D. 377
Explanation: Apply BODMAS: 357 + 21 - 17 = 361. / पहले गुणा, फिर जोड़-घटाव करें।