Compound Interest Test 11
Bilingual timed test with proper DI visuals, clean Hindi and detailed solutions.
Compound Interest Test 11
25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.
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- Compound Interest — Variable rate CI
1. Raipur branch invests ₹20,000 for two years at variable compound rates 10% and 6%. Find total CI. / Raipur शाखा ने ₹20,000 को दो वर्षों के लिए 10% और 6% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹3,120
- B. ₹3,200
- C. ₹3,520
- D. ₹3,320 (Correct)
Explanation: Amount = P(1+10/100)(1+6/100). CI = ₹3,320. / राशि = P(1+10/100)(1+6/100)। CI = ₹3,320।
- Compound Interest — Excess CI
2. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹24,000. (Set 202) / ₹24,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 202)
- A. ₹345.60 (Correct)
- B. ₹395.60
- C. ₹295.60
- D. ₹5,760
Explanation: Excess = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60. / अधिकता = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60।
- Compound Interest — Quarterly compounding
3. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 203) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 203)
- A. ₹1,942.63
- B. ₹1,800
- C. ₹1,822.63
- D. ₹1,882.63 (Correct)
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
- Compound Interest — Three-year amount
4. The amount after 3 years on ₹14,000 at 10% annual compounding is: (Set 204) / ₹14,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 204)
- A. ₹18,200
- B. ₹18,734
- C. ₹18,634 (Correct)
- D. ₹18,534
Explanation: Amount = 14000×1.1^3 = ₹18,634. / राशि = 14000×1.1^3 = ₹18,634।
- Compound Interest — Principal from CI amount
5. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 205) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 205)
- A. ₹19,500
- B. ₹20,000 (Correct)
- C. ₹20,500
- D. ₹20,166.67
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
- Compound Interest — Net CI
6. A deposit earns CI at 15% for 2 years on ₹19,000. If ₹250 service charge is deducted from interest, what net interest remains? / ₹19,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹250 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹5,977.50
- B. ₹6,127.50
- C. ₹5,777.50
- D. ₹5,877.50 (Correct)
Explanation: CI = ₹6,127.50. Net interest = ₹6,127.50−₹250 = ₹5,877.50. / CI = ₹6,127.50। शुद्ध ब्याज = ₹6,127.50−₹250 = ₹5,877.50।
- Compound Interest — Compound amount vs SI amount
7. For ₹28,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 207) / ₹28,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 207)
- A. ₹294
- B. ₹280 (Correct)
- C. ₹180
- D. ₹380
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹280. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹280।
- Compound Interest — Half-yearly two years
8. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 208) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 208)
- A. ₹8,400
- B. ₹9,746.10 (Correct)
- C. ₹9,546.10
- D. ₹9,946.10
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
- Compound Interest — Growth model
9. A savings balance of ₹27,000 grows by 15% compound rate each year. What is the balance after 2 years? (Set 209) / ₹27,000 की बचत राशि प्रति वर्ष 15% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 209)
- A. ₹35,807.50
- B. ₹35,100
- C. ₹35,607.50
- D. ₹35,707.50 (Correct)
Explanation: Balance = 27000(1+15/100)^2 = ₹35,707.50. / शेष राशि = 27000(1+15/100)^2 = ₹35,707.50।
- Compound Interest — Three-year CI
10. Find the compound interest on ₹17,000 at 5% per annum for 3 years. / ₹17,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें।
- A. ₹2,829.63
- B. ₹2,550
- C. ₹2,679.63 (Correct)
- D. ₹2,529.63
Explanation: CI = P[(1+r/100)^3−1] = ₹2,679.63. / CI = P[(1+r/100)^3−1] = ₹2,679.63।
- Compound Interest — Variable rate CI
11. Kanpur branch invests ₹16,000 for two years at variable compound rates 11% and 8%. Find total CI. / Kanpur शाखा ने ₹16,000 को दो वर्षों के लिए 11% और 8% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹3,040
- B. ₹3,180.80 (Correct)
- C. ₹2,980.80
- D. ₹3,380.80
Explanation: Amount = P(1+11/100)(1+8/100). CI = ₹3,180.80. / राशि = P(1+11/100)(1+8/100)। CI = ₹3,180.80।
- Compound Interest — Excess CI
12. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹22,000. (Set 212) / ₹22,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 212)
- A. ₹366.80
- B. ₹316.80 (Correct)
- C. ₹266.80
- D. ₹5,280
Explanation: Excess = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80. / अधिकता = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80।
- Compound Interest — Quarterly compounding
13. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 213) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 213)
- A. ₹1,942.63
- B. ₹1,882.63 (Correct)
- C. ₹1,822.63
- D. ₹1,800
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
- Compound Interest — Three-year amount
14. The amount after 3 years on ₹16,000 at 10% annual compounding is: (Set 214) / ₹16,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 214)
- A. ₹21,296 (Correct)
- B. ₹21,196
- C. ₹20,800
- D. ₹21,396
Explanation: Amount = 16000×1.1^3 = ₹21,296. / राशि = 16000×1.1^3 = ₹21,296।
- Compound Interest — Principal from CI amount
15. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 215) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 215)
- A. ₹20,166.67
- B. ₹20,500
- C. ₹19,500
- D. ₹20,000 (Correct)
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
- Compound Interest — Net CI
16. A deposit earns CI at 15% for 2 years on ₹22,000. If ₹100 service charge is deducted from interest, what net interest remains? / ₹22,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹100 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹7,344.75
- B. ₹6,995 (Correct)
- C. ₹6,895
- D. ₹7,095
Explanation: CI = ₹7,095. Net interest = ₹7,095−₹100 = ₹6,995. / CI = ₹7,095। शुद्ध ब्याज = ₹7,095−₹100 = ₹6,995।
- Compound Interest — Compound amount vs SI amount
17. For ₹26,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 217) / ₹26,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 217)
- A. ₹360
- B. ₹273
- C. ₹260 (Correct)
- D. ₹160
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹260. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹260।
- Compound Interest — Half-yearly two years
18. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 218) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 218)
- A. ₹8,400
- B. ₹9,546.10
- C. ₹9,746.10 (Correct)
- D. ₹9,946.10
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
- Compound Interest — Growth model
19. A savings balance of ₹25,000 grows by 13% compound rate each year. What is the balance after 2 years? (Set 219) / ₹25,000 की बचत राशि प्रति वर्ष 13% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 219)
- A. ₹31,500
- B. ₹31,922.50 (Correct)
- C. ₹31,822.50
- D. ₹32,022.50
Explanation: Balance = 25000(1+13/100)^2 = ₹31,922.50. / शेष राशि = 25000(1+13/100)^2 = ₹31,922.50।
- Compound Interest — Three-year CI
20. Find the compound interest on ₹18,000 at 5% per annum for 3 years. (Set 220) / ₹18,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें। (सेट 220)
- A. ₹2,687.25
- B. ₹2,837.25 (Correct)
- C. ₹2,987.25
- D. ₹2,700
Explanation: CI = P[(1+r/100)^3−1] = ₹2,837.25. / CI = P[(1+r/100)^3−1] = ₹2,837.25।
- Compound Interest — Percentage / प्रतिशत
21. 25% of 475 is: / 475 का 25% कितना है?
- A. 108.75
- B. 118.75 (Correct)
- C. 128.75
- D. 138.75
Explanation: 25% = 25/100, so answer = 118.75. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।
- Compound Interest — Profit-Loss / लाभ-हानि
22. An article bought for Rs 1000 is sold at 10% profit. Find SP. / Rs 1000 में खरीदी वस्तु 10% लाभ पर बेची गई। SP ज्ञात करें।
- A. Rs 1060
- B. Rs 1100 (Correct)
- C. Rs 1140
- D. Rs 1180
Explanation: SP = CP x (100 + profit%)/100 = 1000 x 110/100 = Rs 1100. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।
- Compound Interest — Time & Work / समय और कार्य
23. A finishes a work in 15 days and B in 21 days. Together they finish in: / A 15 दिन और B 21 दिन में काम पूरा करते हैं। साथ में समय?
- A. 7.800000000000001 days
- B. 8.8 days (Correct)
- C. 9.8 days
- D. 10.8 days
Explanation: Combined time = ab/(a+b) = 15 x 21 / 36 = 8.8 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।
- Compound Interest — Speed Conversion / चाल परिवर्तन
24. 90 km/h equals: / 90 किमी/घंटा बराबर है:
- A. 22 m/s
- B. 25 m/s (Correct)
- C. 28 m/s
- D. 30 m/s
Explanation: km/h to m/s conversion uses x 5/18. 90 x 5/18 = 25. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।
- Compound Interest — Simplification / सरलीकरण
25. Simplify: 20 x 13 + 20 - 13. / सरल करें: 20 x 13 + 20 - 13.
- A. 259
- B. 267 (Correct)
- C. 275
- D. 283
Explanation: Apply BODMAS: 260 + 20 - 13 = 267. / पहले गुणा, फिर जोड़-घटाव करें।