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Compound Interest Test 12
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Compound Interest Test 12

Bilingual timed test with proper DI visuals, clean Hindi and detailed solutions.

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Batch 3 | Visual DI

Compound Interest Test 12

25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.

Questions
25
Duration
25 min
Marking
+1 / -0.25
Sections
Compound Interest | 25 questions

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Preview all 25 questions in Compound Interest Test 12 (no login required)
  1. Compound Interest — Variable rate CI

    1. Indore branch invests ₹19,000 for two years at variable compound rates 12% and 6%. Find total CI. / Indore शाखा ने ₹19,000 को दो वर्षों के लिए 12% और 6% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।

    • A. ₹3,756.80
    • B. ₹3,556.80 (Correct)
    • C. ₹3,356.80
    • D. ₹3,420

    Explanation: Amount = P(1+12/100)(1+6/100). CI = ₹3,556.80. / राशि = P(1+12/100)(1+6/100)। CI = ₹3,556.80।

  2. Compound Interest — Excess CI

    2. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹20,000. (Set 222) / ₹20,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 222)

    • A. ₹238
    • B. ₹338
    • C. ₹4,800
    • D. ₹288 (Correct)

    Explanation: Excess = P(r/100)^2 = 20000×(12/100)^2 = ₹288. / अधिकता = P(r/100)^2 = 20000×(12/100)^2 = ₹288।

  3. Compound Interest — Quarterly compounding

    3. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 223) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 223)

    • A. ₹1,882.63 (Correct)
    • B. ₹1,822.63
    • C. ₹1,800
    • D. ₹1,942.63

    Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।

  4. Compound Interest — Three-year amount

    4. The amount after 3 years on ₹10,000 at 10% annual compounding is: (Set 224) / ₹10,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 224)

    • A. ₹13,410
    • B. ₹13,000
    • C. ₹13,210
    • D. ₹13,310 (Correct)

    Explanation: Amount = 10000×1.1^3 = ₹13,310. / राशि = 10000×1.1^3 = ₹13,310।

  5. Compound Interest — Principal from CI amount

    5. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 225) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 225)

    • A. ₹20,166.67
    • B. ₹19,500
    • C. ₹20,000 (Correct)
    • D. ₹20,500

    Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।

  6. Compound Interest — Net CI

    6. A deposit earns CI at 15% for 2 years on ₹18,000. If ₹150 service charge is deducted from interest, what net interest remains? / ₹18,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹150 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?

    • A. ₹5,805
    • B. ₹5,755
    • C. ₹5,655 (Correct)
    • D. ₹5,555

    Explanation: CI = ₹5,805. Net interest = ₹5,805−₹150 = ₹5,655. / CI = ₹5,805। शुद्ध ब्याज = ₹5,805−₹150 = ₹5,655।

  7. Compound Interest — Compound amount vs SI amount

    7. For ₹28,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 227) / ₹28,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 227)

    • A. ₹280 (Correct)
    • B. ₹380
    • C. ₹180
    • D. ₹294

    Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹280. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹280।

  8. Compound Interest — Half-yearly two years

    8. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 228) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 228)

    • A. ₹9,546.10
    • B. ₹9,746.10 (Correct)
    • C. ₹9,946.10
    • D. ₹8,400

    Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।

  9. Compound Interest — Growth model

    9. A savings balance of ₹23,000 grows by 11% compound rate each year. What is the balance after 2 years? (Set 229) / ₹23,000 की बचत राशि प्रति वर्ष 11% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 229)

    • A. ₹28,438.30
    • B. ₹28,238.30
    • C. ₹28,338.30 (Correct)
    • D. ₹28,060

    Explanation: Balance = 23000(1+11/100)^2 = ₹28,338.30. / शेष राशि = 23000(1+11/100)^2 = ₹28,338.30।

  10. Compound Interest — Three-year CI

    10. Find the compound interest on ₹19,000 at 5% per annum for 3 years. (Set 230) / ₹19,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें। (सेट 230)

    • A. ₹3,144.88
    • B. ₹2,994.88 (Correct)
    • C. ₹2,844.88
    • D. ₹2,850

    Explanation: CI = P[(1+r/100)^3−1] = ₹2,994.88. / CI = P[(1+r/100)^3−1] = ₹2,994.88।

  11. Compound Interest — Variable rate CI

    11. Agra branch invests ₹15,000 for two years at variable compound rates 10% and 8%. Find total CI. / Agra शाखा ने ₹15,000 को दो वर्षों के लिए 10% और 8% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।

    • A. ₹3,020
    • B. ₹2,700
    • C. ₹2,620
    • D. ₹2,820 (Correct)

    Explanation: Amount = P(1+10/100)(1+8/100). CI = ₹2,820. / राशि = P(1+10/100)(1+8/100)। CI = ₹2,820।

  12. Compound Interest — Excess CI

    12. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹24,000. (Set 232) / ₹24,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 232)

    • A. ₹395.60
    • B. ₹5,760
    • C. ₹345.60 (Correct)
    • D. ₹295.60

    Explanation: Excess = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60. / अधिकता = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60।

  13. Compound Interest — Quarterly compounding

    13. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 233) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 233)

    • A. ₹1,822.63
    • B. ₹1,882.63 (Correct)
    • C. ₹1,942.63
    • D. ₹1,800

    Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।

  14. Compound Interest — Three-year amount

    14. The amount after 3 years on ₹12,000 at 10% annual compounding is: (Set 234) / ₹12,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 234)

    • A. ₹15,872
    • B. ₹15,972 (Correct)
    • C. ₹15,600
    • D. ₹16,072

    Explanation: Amount = 12000×1.1^3 = ₹15,972. / राशि = 12000×1.1^3 = ₹15,972।

  15. Compound Interest — Principal from CI amount

    15. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 235) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 235)

    • A. ₹20,500
    • B. ₹20,000 (Correct)
    • C. ₹20,166.67
    • D. ₹19,500

    Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।

  16. Compound Interest — Net CI

    16. A deposit earns CI at 15% for 2 years on ₹21,000. If ₹200 service charge is deducted from interest, what net interest remains? / ₹21,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹200 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?

    • A. ₹6,572.50 (Correct)
    • B. ₹6,472.50
    • C. ₹6,772.50
    • D. ₹6,672.50

    Explanation: CI = ₹6,772.50. Net interest = ₹6,772.50−₹200 = ₹6,572.50. / CI = ₹6,772.50। शुद्ध ब्याज = ₹6,772.50−₹200 = ₹6,572.50।

  17. Compound Interest — Compound amount vs SI amount

    17. For ₹26,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 237) / ₹26,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 237)

    • A. ₹360
    • B. ₹160
    • C. ₹260 (Correct)
    • D. ₹273

    Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹260. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹260।

  18. Compound Interest — Half-yearly two years

    18. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 238) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 238)

    • A. ₹9,546.10
    • B. ₹8,400
    • C. ₹9,746.10 (Correct)
    • D. ₹9,946.10

    Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।

  19. Compound Interest — Growth model

    19. A savings balance of ₹27,000 grows by 15% compound rate each year. What is the balance after 2 years? (Set 239) / ₹27,000 की बचत राशि प्रति वर्ष 15% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 239)

    • A. ₹35,100
    • B. ₹35,807.50
    • C. ₹35,607.50
    • D. ₹35,707.50 (Correct)

    Explanation: Balance = 27000(1+15/100)^2 = ₹35,707.50. / शेष राशि = 27000(1+15/100)^2 = ₹35,707.50।

  20. Compound Interest — Three-year CI

    20. Find the compound interest on ₹20,000 at 5% per annum for 3 years. (Set 240) / ₹20,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें। (सेट 240)

    • A. ₹3,302.50
    • B. ₹3,000
    • C. ₹3,002.50
    • D. ₹3,152.50 (Correct)

    Explanation: CI = P[(1+r/100)^3−1] = ₹3,152.50. / CI = P[(1+r/100)^3−1] = ₹3,152.50।

  21. Compound Interest — Percentage / प्रतिशत

    21. 15% of 450 is: / 450 का 15% कितना है?

    • A. 57.5
    • B. 67.5 (Correct)
    • C. 77.5
    • D. 87.5

    Explanation: 15% = 15/100, so answer = 67.5. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।

  22. Compound Interest — Profit-Loss / लाभ-हानि

    22. An article bought for Rs 1050 is sold at 12.5% profit. Find SP. / Rs 1050 में खरीदी वस्तु 12.5% लाभ पर बेची गई। SP ज्ञात करें।

    • A. Rs 1141
    • B. Rs 1181 (Correct)
    • C. Rs 1221
    • D. Rs 1261

    Explanation: SP = CP x (100 + profit%)/100 = 1050 x 112.5/100 = Rs 1181. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।

  23. Compound Interest — Time & Work / समय और कार्य

    23. A finishes a work in 21 days and B in 27 days. Together they finish in: / A 21 दिन और B 27 दिन में काम पूरा करते हैं। साथ में समय?

    • A. 10.8 days
    • B. 11.8 days (Correct)
    • C. 12.8 days
    • D. 13.8 days

    Explanation: Combined time = ab/(a+b) = 21 x 27 / 48 = 11.8 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।

  24. Compound Interest — Speed Conversion / चाल परिवर्तन

    24. 108 km/h equals: / 108 किमी/घंटा बराबर है:

    • A. 27 m/s
    • B. 30 m/s (Correct)
    • C. 33 m/s
    • D. 35 m/s

    Explanation: km/h to m/s conversion uses x 5/18. 108 x 5/18 = 30. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।

  25. Compound Interest — Simplification / सरलीकरण

    25. Simplify: 19 x 16 + 19 - 16. / सरल करें: 19 x 16 + 19 - 16.

    • A. 299
    • B. 307 (Correct)
    • C. 315
    • D. 323

    Explanation: Apply BODMAS: 304 + 19 - 16 = 307. / पहले गुणा, फिर जोड़-घटाव करें।