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Compound Interest Test 13
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Compound Interest Test 13

Bilingual timed test with proper DI visuals, clean Hindi and detailed solutions.

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Batch 3 | Visual DI

Compound Interest Test 13

25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.

Questions
25
Duration
25 min
Marking
+1 / -0.25
Sections
Compound Interest | 25 questions

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Preview all 25 questions in Compound Interest Test 13 (no login required)
  1. Compound Interest — Variable rate CI

    1. Ranchi branch invests ₹18,000 for two years at variable compound rates 11% and 6%. Find total CI. / Ranchi शाखा ने ₹18,000 को दो वर्षों के लिए 11% और 6% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।

    • A. ₹3,378.80
    • B. ₹2,978.80
    • C. ₹3,060
    • D. ₹3,178.80 (Correct)

    Explanation: Amount = P(1+11/100)(1+6/100). CI = ₹3,178.80. / राशि = P(1+11/100)(1+6/100)। CI = ₹3,178.80।

  2. Compound Interest — Excess CI

    2. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹22,000. (Set 242) / ₹22,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 242)

    • A. ₹5,280
    • B. ₹366.80
    • C. ₹316.80 (Correct)
    • D. ₹266.80

    Explanation: Excess = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80. / अधिकता = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80।

  3. Compound Interest — Quarterly compounding

    3. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 243) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 243)

    • A. ₹1,822.63
    • B. ₹1,882.63 (Correct)
    • C. ₹1,800
    • D. ₹1,942.63

    Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।

  4. Compound Interest — Three-year amount

    4. The amount after 3 years on ₹14,000 at 10% annual compounding is: (Set 244) / ₹14,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 244)

    • A. ₹18,634 (Correct)
    • B. ₹18,734
    • C. ₹18,200
    • D. ₹18,534

    Explanation: Amount = 14000×1.1^3 = ₹18,634. / राशि = 14000×1.1^3 = ₹18,634।

  5. Compound Interest — Principal from CI amount

    5. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 245) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 245)

    • A. ₹20,000 (Correct)
    • B. ₹19,500
    • C. ₹20,166.67
    • D. ₹20,500

    Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।

  6. Compound Interest — Net CI

    6. A deposit earns CI at 15% for 2 years on ₹17,000. If ₹250 service charge is deducted from interest, what net interest remains? / ₹17,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹250 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?

    • A. ₹5,132.50
    • B. ₹5,482.50
    • C. ₹5,332.50
    • D. ₹5,232.50 (Correct)

    Explanation: CI = ₹5,482.50. Net interest = ₹5,482.50−₹250 = ₹5,232.50. / CI = ₹5,482.50। शुद्ध ब्याज = ₹5,482.50−₹250 = ₹5,232.50।

  7. Compound Interest — Compound amount vs SI amount

    7. For ₹28,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 247) / ₹28,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 247)

    • A. ₹180
    • B. ₹280 (Correct)
    • C. ₹380
    • D. ₹294

    Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹280. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹280।

  8. Compound Interest — Half-yearly two years

    8. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 248) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 248)

    • A. ₹9,746.10 (Correct)
    • B. ₹8,400
    • C. ₹9,946.10
    • D. ₹9,546.10

    Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।

  9. Compound Interest — Growth model

    9. A savings balance of ₹25,000 grows by 13% compound rate each year. What is the balance after 2 years? (Set 249) / ₹25,000 की बचत राशि प्रति वर्ष 13% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 249)

    • A. ₹31,922.50 (Correct)
    • B. ₹31,500
    • C. ₹31,822.50
    • D. ₹32,022.50

    Explanation: Balance = 25000(1+13/100)^2 = ₹31,922.50. / शेष राशि = 25000(1+13/100)^2 = ₹31,922.50।

  10. Compound Interest — Three-year CI

    10. Find the compound interest on ₹21,000 at 5% per annum for 3 years. (Set 250) / ₹21,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें। (सेट 250)

    • A. ₹3,460.13
    • B. ₹3,310.13 (Correct)
    • C. ₹3,150
    • D. ₹3,160.13

    Explanation: CI = P[(1+r/100)^3−1] = ₹3,310.13. / CI = P[(1+r/100)^3−1] = ₹3,310.13।

  11. Compound Interest — Variable rate CI

    11. Pune branch invests ₹21,000 for two years at variable compound rates 12% and 8%. Find total CI. / Pune शाखा ने ₹21,000 को दो वर्षों के लिए 12% और 8% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।

    • A. ₹4,401.60 (Correct)
    • B. ₹4,200
    • C. ₹4,601.60
    • D. ₹4,201.60

    Explanation: Amount = P(1+12/100)(1+8/100). CI = ₹4,401.60. / राशि = P(1+12/100)(1+8/100)। CI = ₹4,401.60।

  12. Compound Interest — Excess CI

    12. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹20,000. (Set 252) / ₹20,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 252)

    • A. ₹4,800
    • B. ₹338
    • C. ₹238
    • D. ₹288 (Correct)

    Explanation: Excess = P(r/100)^2 = 20000×(12/100)^2 = ₹288. / अधिकता = P(r/100)^2 = 20000×(12/100)^2 = ₹288।

  13. Compound Interest — Quarterly compounding

    13. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 253) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 253)

    • A. ₹1,942.63
    • B. ₹1,882.63 (Correct)
    • C. ₹1,800
    • D. ₹1,822.63

    Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।

  14. Compound Interest — Three-year amount

    14. The amount after 3 years on ₹16,000 at 10% annual compounding is: (Set 254) / ₹16,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 254)

    • A. ₹21,296 (Correct)
    • B. ₹20,800
    • C. ₹21,196
    • D. ₹21,396

    Explanation: Amount = 16000×1.1^3 = ₹21,296. / राशि = 16000×1.1^3 = ₹21,296।

  15. Compound Interest — Principal from CI amount

    15. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 255) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 255)

    • A. ₹19,500
    • B. ₹20,166.67
    • C. ₹20,500
    • D. ₹20,000 (Correct)

    Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।

  16. Compound Interest — Net CI

    16. A deposit earns CI at 15% for 2 years on ₹20,000. If ₹100 service charge is deducted from interest, what net interest remains? / ₹20,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹100 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?

    • A. ₹6,350 (Correct)
    • B. ₹6,250
    • C. ₹6,450
    • D. ₹6,667.50

    Explanation: CI = ₹6,450. Net interest = ₹6,450−₹100 = ₹6,350. / CI = ₹6,450। शुद्ध ब्याज = ₹6,450−₹100 = ₹6,350।

  17. Compound Interest — Compound amount vs SI amount

    17. For ₹26,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 257) / ₹26,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 257)

    • A. ₹273
    • B. ₹260 (Correct)
    • C. ₹360
    • D. ₹160

    Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹260. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹260।

  18. Compound Interest — Half-yearly two years

    18. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 258) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 258)

    • A. ₹9,946.10
    • B. ₹8,400
    • C. ₹9,546.10
    • D. ₹9,746.10 (Correct)

    Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।

  19. Compound Interest — Growth model

    19. A savings balance of ₹23,000 grows by 11% compound rate each year. What is the balance after 2 years? (Set 259) / ₹23,000 की बचत राशि प्रति वर्ष 11% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 259)

    • A. ₹28,060
    • B. ₹28,238.30
    • C. ₹28,438.30
    • D. ₹28,338.30 (Correct)

    Explanation: Balance = 23000(1+11/100)^2 = ₹28,338.30. / शेष राशि = 23000(1+11/100)^2 = ₹28,338.30।

  20. Compound Interest — Three-year CI

    20. Find the compound interest on ₹22,000 at 5% per annum for 3 years. (Set 260) / ₹22,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें। (सेट 260)

    • A. ₹3,617.75
    • B. ₹3,317.75
    • C. ₹3,467.75 (Correct)
    • D. ₹3,300

    Explanation: CI = P[(1+r/100)^3−1] = ₹3,467.75. / CI = P[(1+r/100)^3−1] = ₹3,467.75।

  21. Compound Interest — Percentage / प्रतिशत

    21. 20% of 425 is: / 425 का 20% कितना है?

    • A. 75
    • B. 85 (Correct)
    • C. 95
    • D. 105

    Explanation: 20% = 20/100, so answer = 85. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।

  22. Compound Interest — Profit-Loss / लाभ-हानि

    22. An article bought for Rs 1100 is sold at 15% profit. Find SP. / Rs 1100 में खरीदी वस्तु 15% लाभ पर बेची गई। SP ज्ञात करें।

    • A. Rs 1225
    • B. Rs 1265 (Correct)
    • C. Rs 1305
    • D. Rs 1345

    Explanation: SP = CP x (100 + profit%)/100 = 1100 x 115/100 = Rs 1265. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।

  23. Compound Interest — Time & Work / समय और कार्य

    23. A finishes a work in 12 days and B in 18 days. Together they finish in: / A 12 दिन और B 18 दिन में काम पूरा करते हैं। साथ में समय?

    • A. 6.2 days
    • B. 7.2 days (Correct)
    • C. 8.2 days
    • D. 9.2 days

    Explanation: Combined time = ab/(a+b) = 12 x 18 / 30 = 7.2 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।

  24. Compound Interest — Speed Conversion / चाल परिवर्तन

    24. 54 km/h equals: / 54 किमी/घंटा बराबर है:

    • A. 12 m/s
    • B. 15 m/s (Correct)
    • C. 18 m/s
    • D. 20 m/s

    Explanation: km/h to m/s conversion uses x 5/18. 54 x 5/18 = 15. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।

  25. Compound Interest — Simplification / सरलीकरण

    25. Simplify: 18 x 12 + 18 - 12. / सरल करें: 18 x 12 + 18 - 12.

    • A. 214
    • B. 222 (Correct)
    • C. 230
    • D. 238

    Explanation: Apply BODMAS: 216 + 18 - 12 = 222. / पहले गुणा, फिर जोड़-घटाव करें।