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Compound Interest Test 14
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Compound Interest Test 14

Bilingual timed test with proper DI visuals, clean Hindi and detailed solutions.

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Batch 3 | Visual DI

Compound Interest Test 14

25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.

Questions
25
Duration
25 min
Marking
+1 / -0.25
Sections
Compound Interest | 25 questions

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Preview all 25 questions in Compound Interest Test 14 (no login required)
  1. Compound Interest — Variable rate CI

    1. Kochi branch invests ₹17,000 for two years at variable compound rates 10% and 6%. Find total CI. / Kochi शाखा ने ₹17,000 को दो वर्षों के लिए 10% और 6% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।

    • A. ₹2,720
    • B. ₹3,022
    • C. ₹2,822 (Correct)
    • D. ₹2,622

    Explanation: Amount = P(1+10/100)(1+6/100). CI = ₹2,822. / राशि = P(1+10/100)(1+6/100)। CI = ₹2,822।

  2. Compound Interest — Excess CI

    2. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹24,000. (Set 262) / ₹24,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 262)

    • A. ₹345.60 (Correct)
    • B. ₹395.60
    • C. ₹5,760
    • D. ₹295.60

    Explanation: Excess = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60. / अधिकता = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60।

  3. Compound Interest — Quarterly compounding

    3. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 263) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 263)

    • A. ₹1,882.63 (Correct)
    • B. ₹1,942.63
    • C. ₹1,800
    • D. ₹1,822.63

    Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।

  4. Compound Interest — Three-year amount

    4. The amount after 3 years on ₹10,000 at 10% annual compounding is: (Set 264) / ₹10,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 264)

    • A. ₹13,000
    • B. ₹13,310 (Correct)
    • C. ₹13,210
    • D. ₹13,410

    Explanation: Amount = 10000×1.1^3 = ₹13,310. / राशि = 10000×1.1^3 = ₹13,310।

  5. Compound Interest — Principal from CI amount

    5. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 265) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 265)

    • A. ₹20,000 (Correct)
    • B. ₹19,500
    • C. ₹20,500
    • D. ₹20,166.67

    Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।

  6. Compound Interest — Net CI

    6. A deposit earns CI at 15% for 2 years on ₹16,000. If ₹150 service charge is deducted from interest, what net interest remains? / ₹16,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹150 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?

    • A. ₹5,160
    • B. ₹4,910
    • C. ₹5,110
    • D. ₹5,010 (Correct)

    Explanation: CI = ₹5,160. Net interest = ₹5,160−₹150 = ₹5,010. / CI = ₹5,160। शुद्ध ब्याज = ₹5,160−₹150 = ₹5,010।

  7. Compound Interest — Compound amount vs SI amount

    7. For ₹28,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 267) / ₹28,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 267)

    • A. ₹180
    • B. ₹294
    • C. ₹280 (Correct)
    • D. ₹380

    Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹280. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹280।

  8. Compound Interest — Half-yearly two years

    8. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 268) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 268)

    • A. ₹9,546.10
    • B. ₹8,400
    • C. ₹9,746.10 (Correct)
    • D. ₹9,946.10

    Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।

  9. Compound Interest — Growth model

    9. A savings balance of ₹27,000 grows by 15% compound rate each year. What is the balance after 2 years? (Set 269) / ₹27,000 की बचत राशि प्रति वर्ष 15% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 269)

    • A. ₹35,100
    • B. ₹35,807.50
    • C. ₹35,607.50
    • D. ₹35,707.50 (Correct)

    Explanation: Balance = 27000(1+15/100)^2 = ₹35,707.50. / शेष राशि = 27000(1+15/100)^2 = ₹35,707.50।

  10. Compound Interest — Three-year CI

    10. Find the compound interest on ₹14,000 at 5% per annum for 3 years. (Set 270) / ₹14,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें। (सेट 270)

    • A. ₹2,356.75
    • B. ₹2,206.75 (Correct)
    • C. ₹2,056.75
    • D. ₹2,100

    Explanation: CI = P[(1+r/100)^3−1] = ₹2,206.75. / CI = P[(1+r/100)^3−1] = ₹2,206.75।

  11. Compound Interest — Variable rate CI

    11. Lucknow branch invests ₹20,000 for two years at variable compound rates 11% and 8%. Find total CI. / Lucknow शाखा ने ₹20,000 को दो वर्षों के लिए 11% और 8% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।

    • A. ₹3,976 (Correct)
    • B. ₹3,800
    • C. ₹4,176
    • D. ₹3,776

    Explanation: Amount = P(1+11/100)(1+8/100). CI = ₹3,976. / राशि = P(1+11/100)(1+8/100)। CI = ₹3,976।

  12. Compound Interest — Excess CI

    12. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹22,000. (Set 272) / ₹22,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 272)

    • A. ₹266.80
    • B. ₹316.80 (Correct)
    • C. ₹366.80
    • D. ₹5,280

    Explanation: Excess = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80. / अधिकता = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80।

  13. Compound Interest — Quarterly compounding

    13. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 273) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 273)

    • A. ₹1,822.63
    • B. ₹1,882.63 (Correct)
    • C. ₹1,942.63
    • D. ₹1,800

    Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।

  14. Compound Interest — Three-year amount

    14. The amount after 3 years on ₹12,000 at 10% annual compounding is: (Set 274) / ₹12,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी: (सेट 274)

    • A. ₹15,972 (Correct)
    • B. ₹16,072
    • C. ₹15,872
    • D. ₹15,600

    Explanation: Amount = 12000×1.1^3 = ₹15,972. / राशि = 12000×1.1^3 = ₹15,972।

  15. Compound Interest — Principal from CI amount

    15. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 275) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 275)

    • A. ₹20,166.67
    • B. ₹20,500
    • C. ₹19,500
    • D. ₹20,000 (Correct)

    Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।

  16. Compound Interest — Net CI

    16. A deposit earns CI at 15% for 2 years on ₹19,000. If ₹200 service charge is deducted from interest, what net interest remains? / ₹19,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹200 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?

    • A. ₹6,127.50
    • B. ₹5,827.50
    • C. ₹5,927.50 (Correct)
    • D. ₹6,027.50

    Explanation: CI = ₹6,127.50. Net interest = ₹6,127.50−₹200 = ₹5,927.50. / CI = ₹6,127.50। शुद्ध ब्याज = ₹6,127.50−₹200 = ₹5,927.50।

  17. Compound Interest — Compound amount vs SI amount

    17. For ₹26,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 277) / ₹26,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 277)

    • A. ₹360
    • B. ₹160
    • C. ₹273
    • D. ₹260 (Correct)

    Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹260. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹260।

  18. Compound Interest — Half-yearly two years

    18. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 278) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 278)

    • A. ₹9,746.10 (Correct)
    • B. ₹9,546.10
    • C. ₹8,400
    • D. ₹9,946.10

    Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।

  19. Compound Interest — Growth model

    19. A savings balance of ₹25,000 grows by 13% compound rate each year. What is the balance after 2 years? (Set 279) / ₹25,000 की बचत राशि प्रति वर्ष 13% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 279)

    • A. ₹32,022.50
    • B. ₹31,922.50 (Correct)
    • C. ₹31,500
    • D. ₹31,822.50

    Explanation: Balance = 25000(1+13/100)^2 = ₹31,922.50. / शेष राशि = 25000(1+13/100)^2 = ₹31,922.50।

  20. Compound Interest — Three-year CI

    20. Find the compound interest on ₹15,000 at 5% per annum for 3 years. (Set 280) / ₹15,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें। (सेट 280)

    • A. ₹2,214.38
    • B. ₹2,364.38 (Correct)
    • C. ₹2,250
    • D. ₹2,514.38

    Explanation: CI = P[(1+r/100)^3−1] = ₹2,364.38. / CI = P[(1+r/100)^3−1] = ₹2,364.38।

  21. Compound Interest — Percentage / प्रतिशत

    21. 12% of 400 is: / 400 का 12% कितना है?

    • A. 38
    • B. 48 (Correct)
    • C. 58
    • D. 68

    Explanation: 12% = 12/100, so answer = 48. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।

  22. Compound Interest — Profit-Loss / लाभ-हानि

    22. An article bought for Rs 1150 is sold at 20% profit. Find SP. / Rs 1150 में खरीदी वस्तु 20% लाभ पर बेची गई। SP ज्ञात करें।

    • A. Rs 1340
    • B. Rs 1380 (Correct)
    • C. Rs 1420
    • D. Rs 1460

    Explanation: SP = CP x (100 + profit%)/100 = 1150 x 120/100 = Rs 1380. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।

  23. Compound Interest — Time & Work / समय और कार्य

    23. A finishes a work in 18 days and B in 24 days. Together they finish in: / A 18 दिन और B 24 दिन में काम पूरा करते हैं। साथ में समय?

    • A. 9.3 days
    • B. 10.3 days (Correct)
    • C. 11.3 days
    • D. 12.3 days

    Explanation: Combined time = ab/(a+b) = 18 x 24 / 42 = 10.3 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।

  24. Compound Interest — Speed Conversion / चाल परिवर्तन

    24. 72 km/h equals: / 72 किमी/घंटा बराबर है:

    • A. 17 m/s
    • B. 20 m/s (Correct)
    • C. 23 m/s
    • D. 25 m/s

    Explanation: km/h to m/s conversion uses x 5/18. 72 x 5/18 = 20. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।

  25. Compound Interest — Simplification / सरलीकरण

    25. Simplify: 26 x 15 + 26 - 15. / सरल करें: 26 x 15 + 26 - 15.

    • A. 393
    • B. 401 (Correct)
    • C. 409
    • D. 417

    Explanation: Apply BODMAS: 390 + 26 - 15 = 401. / पहले गुणा, फिर जोड़-घटाव करें।