Compound Interest Test 8
Bilingual timed test with proper DI visuals, clean Hindi and detailed solutions.
Compound Interest Test 8
25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.
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- Compound Interest — Variable rate CI
1. Indore branch invests ₹16,000 for two years at variable compound rates 10% and 6%. Find total CI. / Indore शाखा ने ₹16,000 को दो वर्षों के लिए 10% और 6% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹2,456
- B. ₹2,560
- C. ₹2,856
- D. ₹2,656 (Correct)
Explanation: Amount = P(1+10/100)(1+6/100). CI = ₹2,656. / राशि = P(1+10/100)(1+6/100)। CI = ₹2,656।
- Compound Interest — Excess CI
2. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹24,000. / ₹24,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें।
- A. ₹295.60
- B. ₹395.60
- C. ₹345.60 (Correct)
- D. ₹5,760
Explanation: Excess = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60. / अधिकता = P(r/100)^2 = 24000×(12/100)^2 = ₹345.60।
- Compound Interest — Quarterly compounding
3. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 143) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 143)
- A. ₹1,822.63
- B. ₹1,942.63
- C. ₹1,882.63 (Correct)
- D. ₹1,800
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
- Compound Interest — Three-year amount
4. The amount after 3 years on ₹10,000 at 10% annual compounding is: / ₹10,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी:
- A. ₹13,410
- B. ₹13,000
- C. ₹13,310 (Correct)
- D. ₹13,210
Explanation: Amount = 10000×1.1^3 = ₹13,310. / राशि = 10000×1.1^3 = ₹13,310।
- Compound Interest — Principal from CI amount
5. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 145) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 145)
- A. ₹20,500
- B. ₹20,000 (Correct)
- C. ₹19,500
- D. ₹20,166.67
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
- Compound Interest — Net CI
6. A deposit earns CI at 15% for 2 years on ₹22,000. If ₹150 service charge is deducted from interest, what net interest remains? / ₹22,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹150 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹7,045
- B. ₹6,845
- C. ₹6,945 (Correct)
- D. ₹7,095
Explanation: CI = ₹7,095. Net interest = ₹7,095−₹150 = ₹6,945. / CI = ₹7,095। शुद्ध ब्याज = ₹7,095−₹150 = ₹6,945।
- Compound Interest — Compound amount vs SI amount
7. For ₹28,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 147) / ₹28,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 147)
- A. ₹280 (Correct)
- B. ₹180
- C. ₹294
- D. ₹380
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹280. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹280।
- Compound Interest — Half-yearly two years
8. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 148) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 148)
- A. ₹8,400
- B. ₹9,746.10 (Correct)
- C. ₹9,946.10
- D. ₹9,546.10
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
- Compound Interest — Growth model
9. A savings balance of ₹27,000 grows by 15% compound rate each year. What is the balance after 2 years? / ₹27,000 की बचत राशि प्रति वर्ष 15% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी?
- A. ₹35,807.50
- B. ₹35,100
- C. ₹35,607.50
- D. ₹35,707.50 (Correct)
Explanation: Balance = 27000(1+15/100)^2 = ₹35,707.50. / शेष राशि = 27000(1+15/100)^2 = ₹35,707.50।
- Compound Interest — Three-year CI
10. Find the compound interest on ₹20,000 at 5% per annum for 3 years. / ₹20,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें।
- A. ₹3,002.50
- B. ₹3,152.50 (Correct)
- C. ₹3,000
- D. ₹3,302.50
Explanation: CI = P[(1+r/100)^3−1] = ₹3,152.50. / CI = P[(1+r/100)^3−1] = ₹3,152.50।
- Compound Interest — Variable rate CI
11. Agra branch invests ₹19,000 for two years at variable compound rates 11% and 8%. Find total CI. / Agra शाखा ने ₹19,000 को दो वर्षों के लिए 11% और 8% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹3,610
- B. ₹3,777.20 (Correct)
- C. ₹3,977.20
- D. ₹3,577.20
Explanation: Amount = P(1+11/100)(1+8/100). CI = ₹3,777.20. / राशि = P(1+11/100)(1+8/100)। CI = ₹3,777.20।
- Compound Interest — Excess CI
12. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹22,000. (Set 152) / ₹22,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें। (सेट 152)
- A. ₹366.80
- B. ₹316.80 (Correct)
- C. ₹266.80
- D. ₹5,280
Explanation: Excess = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80. / अधिकता = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80।
- Compound Interest — Quarterly compounding
13. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 153) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 153)
- A. ₹1,800
- B. ₹1,942.63
- C. ₹1,882.63 (Correct)
- D. ₹1,822.63
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
- Compound Interest — Three-year amount
14. The amount after 3 years on ₹12,000 at 10% annual compounding is: / ₹12,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी:
- A. ₹15,972 (Correct)
- B. ₹16,072
- C. ₹15,872
- D. ₹15,600
Explanation: Amount = 12000×1.1^3 = ₹15,972. / राशि = 12000×1.1^3 = ₹15,972।
- Compound Interest — Principal from CI amount
15. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 155) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 155)
- A. ₹20,000 (Correct)
- B. ₹20,500
- C. ₹20,166.67
- D. ₹19,500
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
- Compound Interest — Net CI
16. A deposit earns CI at 15% for 2 years on ₹18,000. If ₹200 service charge is deducted from interest, what net interest remains? / ₹18,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹200 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹5,705
- B. ₹5,605 (Correct)
- C. ₹5,805
- D. ₹5,505
Explanation: CI = ₹5,805. Net interest = ₹5,805−₹200 = ₹5,605. / CI = ₹5,805। शुद्ध ब्याज = ₹5,805−₹200 = ₹5,605।
- Compound Interest — Compound amount vs SI amount
17. For ₹26,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? (Set 157) / ₹26,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है? (सेट 157)
- A. ₹360
- B. ₹160
- C. ₹260 (Correct)
- D. ₹273
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹260. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹260।
- Compound Interest — Half-yearly two years
18. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 158) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 158)
- A. ₹9,546.10
- B. ₹9,946.10
- C. ₹9,746.10 (Correct)
- D. ₹8,400
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
- Compound Interest — Growth model
19. A savings balance of ₹25,000 grows by 13% compound rate each year. What is the balance after 2 years? (Set 159) / ₹25,000 की बचत राशि प्रति वर्ष 13% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी? (सेट 159)
- A. ₹32,022.50
- B. ₹31,500
- C. ₹31,922.50 (Correct)
- D. ₹31,822.50
Explanation: Balance = 25000(1+13/100)^2 = ₹31,922.50. / शेष राशि = 25000(1+13/100)^2 = ₹31,922.50।
- Compound Interest — Three-year CI
20. Find the compound interest on ₹21,000 at 5% per annum for 3 years. / ₹21,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें।
- A. ₹3,160.13
- B. ₹3,150
- C. ₹3,460.13
- D. ₹3,310.13 (Correct)
Explanation: CI = P[(1+r/100)^3−1] = ₹3,310.13. / CI = P[(1+r/100)^3−1] = ₹3,310.13।
- Compound Interest — Percentage / प्रतिशत
21. 20% of 550 is: / 550 का 20% कितना है?
- A. 100
- B. 110 (Correct)
- C. 120
- D. 130
Explanation: 20% = 20/100, so answer = 110. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।
- Compound Interest — Profit-Loss / लाभ-हानि
22. An article bought for Rs 850 is sold at 12.5% profit. Find SP. / Rs 850 में खरीदी वस्तु 12.5% लाभ पर बेची गई। SP ज्ञात करें।
- A. Rs 916
- B. Rs 956 (Correct)
- C. Rs 996
- D. Rs 1036
Explanation: SP = CP x (100 + profit%)/100 = 850 x 112.5/100 = Rs 956. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।
- Compound Interest — Time & Work / समय और कार्य
23. A finishes a work in 12 days and B in 18 days. Together they finish in: / A 12 दिन और B 18 दिन में काम पूरा करते हैं। साथ में समय?
- A. 6.2 days
- B. 7.2 days (Correct)
- C. 8.2 days
- D. 9.2 days
Explanation: Combined time = ab/(a+b) = 12 x 18 / 30 = 7.2 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।
- Compound Interest — Speed Conversion / चाल परिवर्तन
24. 108 km/h equals: / 108 किमी/घंटा बराबर है:
- A. 27 m/s
- B. 30 m/s (Correct)
- C. 33 m/s
- D. 35 m/s
Explanation: km/h to m/s conversion uses x 5/18. 108 x 5/18 = 30. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।
- Compound Interest — Simplification / सरलीकरण
25. Simplify: 23 x 18 + 23 - 18. / सरल करें: 23 x 18 + 23 - 18.
- A. 411
- B. 419 (Correct)
- C. 427
- D. 435
Explanation: Apply BODMAS: 414 + 23 - 18 = 419. / पहले गुणा, फिर जोड़-घटाव करें।