JEE Chemistry · Hard

Chemical and Ionic Equilibrium: Salt hydrolysis MCQ

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Salt hydrolysisHardQuestion 600428

Question

Equal volumes of 0.2 M CH₃COOH (pKa = 4.74) and 0.2 M NaOH are mixed. The pH of the resulting solution is:
  1. A
    4.74
  2. B
    7
  3. C
    8.87
    Correct
  4. D
    9.25

Correct answer

8.87

Explanation

Equal moles react completely, leaving 0.1 M CH₃COONa. For a salt of a weak acid and strong base, pH=(pKw+pKa+log⁡C)/2=(14+4.74−1)/2=<strong>8.87</strong>pH=(pK_w+pK_a+\log C)/2=(14+4.74-1)/2=<strong>8.87</strong>.