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JEE Chemistry · Medium

Practical Organic Chemistry: Name reactions MCQ

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Name reactionsMediumQuestion 910003

Question

The Aldol condensation product of 2 mol acetaldehyde under dilute base is:
  1. A
    3-hydroxybutanal (then crotonic acid on aldol reaction)
    Correct
  2. B
    Butanoic acid
  3. C
    Propanediol
  4. D
    Methanol

Correct answer

3-hydroxybutanal (then crotonic acid on aldol reaction)

Explanation

Aldol reaction: 2CH₃CHO + NaOH(dilute) → CH₃CH(OH)CH₂CHO (3-hydroxybutanal). This is an aldol product. On heating (aldol condensation): −H₂O → CH₃CH=CHCHO (crotonaldehyde/but-2-enal).

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