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Question 310007
JEE Mathematics · Medium

Application of Derivatives: Approximation MCQ

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ApproximationMediumQuestion 310007

Question

Using differentials, √25.1 ≈:
  1. A
    5.01
    Correct
  2. B
    5.02
  3. C
    5.1
  4. D
    5.005

Correct answer

5.01

Explanation

Let f(x) = √x, f'(x) = 1/(2√x). Δy ≈ f'(25)×Δx = (1/10)(0.1) = 0.01. √25.1 ≈ 5 + 0.01 = 5.01.

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