Binomial Theorem: Mixed MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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MixedMediumQuestion 280014

Question

The term containing x¹⁰ in (x² + 1/x)¹⁴ is:

T₇ = ¹⁴C₆ x¹⁰

The general term is $T_{r+1}=\binom{14}{r}x^{28-3r}$ . Setting $28-3r=10$ gives $r=6$ , so the required term is $T_7=\binom{14}{6}x^{10}$ .