JEE Physics · Easy

Capacitance: Series Combination MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Series CombinationEasyQuestion 31522

Question

Two capacitors 4 μF and 12 μF are connected in series. Equivalent capacitance is:
  1. A
    16 μF
  2. B
    3 μF
    Correct
  3. C
    8 μF
  4. D
    48 μF

Correct answer

3 μF

Explanation

1/C = 1/4 + 1/12 = 3/12 + 1/12 = 4/12, so C = 3 μF.