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Question 30581
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Center of Mass, Momentum and Collision: Advanced — Restitution and Energy MCQ

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Advanced — Restitution and EnergyHardQuestion 30581

Question

For a 1D collision between m₁ and m₂ (m₂ at rest), the fraction of KE lost is:
  1. A
    [m₁m₂(1−e²)]/(m₁+m₂)×(2/m₁)
  2. B
    m₂(1−e²)/(m₁+m₂)
    Correct
  3. C
    1−e²
  4. D
    e²

Correct answer

m₂(1−e²)/(m₁+m₂)

Explanation

Energy loss = (1−e²) × [m₁m₂/(m₁+m₂)] × ½(u₁)². Fraction of initial KE (= ½m₁u₁²) lost = (1−e²) × m₂/(m₁+m₂).

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