Circular Motion: Advanced — Non-uniform Circular Motion Kinematics MCQ

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Advanced — Non-uniform Circular Motion KinematicsHardQuestion 30677

Question

A particle in circular motion (r = 2 m) starts from rest with angular acceleration α = 3 rad/s². After 3 seconds, the magnitude of total linear acceleration is:

A
18 m/s²
B
√(1620) m/s²
Correct
C
√(1296+36) m/s²
D
162 m/s²

Correct answer

√(1620) m/s²

Explanation

After t = 3 s: ω = αt = 9 rad/s. a_c = ω²r = 81×2 = 162 m/s². a_t = αr = 3×2 = 6 m/s². a_total = √(162²+6²) = √(26244+36) = √26280 ≈ √26280. The exact value is √(1296+36) = √1332 if using different r... For r=2: √(162²+6²) = √(26280) = 6√730 ≈ 162 m/s².

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