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Question 30851
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Calorimetry Principle MCQ

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Calorimetry PrincipleHardQuestion 30851

Question

10 g of ice at 0°C is mixed with 10 g of water at 100°C. Final state is (L_ice = 336 J/g, c_water = 4.2 J/g·°C):
  1. A
    All water at 0°C
  2. B
    All water at about 62°C
    Correct
  3. C
    Ice and water at 0°C
  4. D
    Steam and water

Correct answer

All water at about 62°C

Explanation

Heat available from water cooling: 10 × 4.2 × 100 = 4200 J. Heat to melt ice: 10 × 336 = 3360 J. Remaining: 840 J heats 20 g water: ΔT = 840/(20 × 4.2) = 10°C. Final T = 10°C. Recalculate: after melting, 20g water at 0°C. Water originally at 100°C gave 4200 J: 3360 to melt ice, 840 to heat 20g → 10°C. So final ≈ 10°C.

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