Principles of Communication: Digital Communication MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Digital CommunicationHardQuestion 20259

Question

A voice signal with maximum frequency 4 kHz is to be digitised using PCM with 8-bit encoding. The minimum bit rate required is:

A
4 kbps
B
32 kbps
C
64 kbps
Correct
D
128 kbps

Correct answer

64 kbps

Explanation

Nyquist sampling rate = 2 × 4000 = 8000 samples/s. Each sample is encoded in 8 bits. Bit rate = 8000 × 8 = 64,000 bps = 64 kbps. This is the standard G.711 telephony rate.

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