Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Rigid Body Dynamics/
Question 30374
JEE Physics · Hard

Rigid Body Dynamics: Advanced — Inelastic Collision MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Advanced — Inelastic CollisionHardQuestion 30374

Question

A 0.1 kg bullet (v = 200 m/s) strikes tangentially and embeds in the rim of a disc (M = 2 kg, R = 0.5 m) at rest. The angular speed of the disc+bullet is:
  1. A
    36.4 rad/s
    Correct
  2. B
    19.6 rad/s
  3. C
    40 rad/s
  4. D
    4 rad/s

Correct answer

36.4 rad/s

Explanation

Angular momentum about the axle is mvR=10mvR=10 kg·m²/s. The final moment of inertia is MR2/2+mR2=0.25+0.025=0.275MR^2/2+mR^2=0.25+0.025=0.275 kg·m². Thus ω=10/0.275≈<strong>36.4 rad/s</strong>ω=10/0.275≈<strong>36.4\text{ rad/s}</strong>.

Review Rigid Body Dynamics notesStart timed chapter practice