Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Work, Power and Energy/
Question 30460
JEE Physics · Hard

Work, Power and Energy: JEE — Block on Wedge Energy MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
JEE — Block on Wedge EnergyHardQuestion 30460

Question

A block (mass m) slides off a smooth wedge (height H, angle θ, on frictionless floor). The block's speed when it leaves the wedge at the bottom is:
  1. A
    √(2gH)
    Correct
  2. B
    √(gH)
  3. C
    √(2gH sinθ)
  4. D
    √(gH/sinθ)

Correct answer

√(2gH)

Explanation

On a frictionless wedge on a frictionless floor, the system's total energy is conserved. The block's PE = mgh is converted to its KE. Hence v = √(2gH) regardless of wedge angle.

Review Work, Power and Energy notesStart timed chapter practice