JEE Physics · Hard

Work, Power and Energy: Advanced — Energy Method for Oscillation MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Advanced — Energy Method for OscillationHardQuestion 30476

Question

A mass m on a spring (k) on a surface inclined at θ (rough, μ). Energy dissipated per oscillation when amplitude reduces from A to A' is:
  1. A
    ½k(A²−A'²)
  2. B
    ½k(A−A')²
  3. C
    2μmg cosθ(A+A')
    Correct
  4. D
    μmgA cosθ

Correct answer

2μmg cosθ(A+A')

Explanation

Per half-cycle, friction force μmg cosθ acts over distance (A+A')/2... over a full cycle, displacement of the block is 2(A+A') approximately, and friction does work 2μmg cosθ×(A+A')/2×2... The energy dissipated per full cycle = 4μmg cosθ × A_avg. A more careful analysis gives the dissipation per cycle = 4μmg cosθ×A for amplitude A.