Amines Practice

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NEET Chemistry - Chapter 22

Amines Practice Tests

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Definition
1. Amines are derivatives of ammonia in which H is replaced by:
- A. alkyl or aryl groups (Correct)
- B. oxygen only
- C. carbonyl groups only
- D. metals
Explanation: Amines are classified by organic substitution on NH$_3$.
Classification
2. A primary amine has nitrogen attached to:
- A. one carbon group (Correct)
- B. two carbon groups
- C. three carbon groups
- D. no carbon group
Explanation: RNH$_2$ is a primary amine.
Classification
3. Aniline is:
- A. an aromatic primary amine (Correct)
- B. an aliphatic tertiary amine
- C. an amide
- D. a nitro compound
Explanation: Aniline is aminobenzene.
Basicity
4. Amines behave as bases because nitrogen has:
- A. a lone pair (Correct)
- B. a carbonyl group
- C. a positive charge
- D. a halogen
Explanation: The lone pair accepts a proton.
Basicity order
5. In aqueous solution, aliphatic amines often show basic strength order:
- A. 2$^\circ$ > 1$^\circ$ > 3$^\circ$ > NH$_3$ (Correct)
- B. 3$^\circ$ > 2$^\circ$ > 1$^\circ$
- C. NH$_3$ > 1$^\circ$ > 2$^\circ$
- D. all equal
Explanation: Inductive effect and solvation together control the order.
Aromatic amines
6. Aniline is less basic than methylamine mainly because in aniline the lone pair is:
- A. delocalized into the benzene ring (Correct)
- B. more localized
- C. attached to oxygen
- D. positively charged
Explanation: Resonance reduces availability of the lone pair.
Preparation
7. Primary amines can be prepared by reduction of:
- A. nitro compounds (Correct)
- B. alcohols only
- C. alkenes only
- D. ethers
Explanation: Nitro group reduction gives amines.
Reaction
8. Amines react with acids to form:
- A. ammonium salts (Correct)
- B. esters
- C. ethers
- D. aldehydes
Explanation: Protonation of the amine occurs.
Carbylamine
9. Carbylamine test is given by:
- A. primary amines (Correct)
- B. secondary amines
- C. tertiary amines
- D. amides only
Explanation: Primary amines form foul-smelling isocyanides.
Hinsberg
10. Hinsberg reagent is used to distinguish:
- A. 1$^\circ$, 2$^\circ$, and 3$^\circ$ amines (Correct)
- B. alcohols and phenols
- C. aldehydes and ketones
- D. alkanes and alkenes
Explanation: Different sulfonamide behavior helps classify amines.
Diazotization
11. Aniline on treatment with NaNO$_2$/HCl at 0-5°C forms:
- A. benzene diazonium chloride (Correct)
- B. nitrobenzene
- C. phenol directly
- D. benzoic acid
Explanation: Primary aromatic amines undergo diazotization.
Coupling
12. Benzene diazonium chloride couples with phenol in alkaline medium to form:
- A. azo dye (Correct)
- B. ether
- C. amide
- D. alkane
Explanation: Azo coupling gives brightly colored compounds.
Acylation
13. Acylation of aniline reduces activating effect of -NH$_2$ because:
- A. the lone pair becomes less available (Correct)
- B. nitrogen becomes metallic
- C. ring becomes saturated
- D. a halogen is introduced
Explanation: Protection by acylation moderates ring activation.
Sandmeyer
14. Sandmeyer reaction is used to replace diazonium group by:
- A. Cl, Br, or CN (Correct)
- B. only H
- C. only OH
- D. only NH$_2$
Explanation: Cu(I) salts assist these substitutions.
Reaction with nitrous acid
15. Primary aliphatic amines with nitrous acid generally form:
- A. alcohols with N$_2$ evolution (Correct)
- B. stable diazonium salts
- C. amides
- D. azo dyes
Explanation: Unstable aliphatic diazonium intermediates decompose.
Physical property
16. Lower aliphatic amines are soluble in water mainly because of:
- A. hydrogen bonding (Correct)
- B. ionic lattice
- C. metallic bonds
- D. lack of polarity
Explanation: They H-bond with water through N-H and lone pair.
Order
17. In gas phase, basicity of simple aliphatic amines generally follows:
- A. 3$^\circ$ > 2$^\circ$ > 1$^\circ$ > NH$_3$ (Correct)
- B. NH$_3$ > 1$^\circ$ > 2$^\circ$
- C. 1$^\circ$ > 2$^\circ$ > 3$^\circ$
- D. all same
Explanation: Without solvation, +I effect dominates more strongly.
Structure
18. Nitrogen in amines is generally:
- A. sp$^3$ hybridized and pyramidal (Correct)
- B. sp$^2$ planar always
- C. sp linear
- D. dsp$^2$
Explanation: One lone pair gives pyramidal geometry.
Aniline reaction
19. Aniline with bromine water readily forms:
- A. 2,4,6-tribromoaniline (Correct)
- B. bromobenzene
- C. benzoic acid
- D. anisole
Explanation: The amino group strongly activates the ring.
Identification
20. Which test most directly confirms a primary amine in school-level organic chemistry?
- A. Carbylamine test (Correct)
- B. FeCl$_3$ test
- C. Tollens test
- D. Lucas test
Explanation: It is characteristic for primary amines.
Protection
21. Aniline is often acetylated before nitration mainly to:
- A. avoid over-activation and oxidation (Correct)
- B. increase basicity greatly
- C. remove the amino group
- D. make the ring non-aromatic
Explanation: Protection controls substitution more cleanly.
Diazonium utility
22. Aryl diazonium salts are especially useful because they allow introduction of:
- A. different substituents onto aromatic ring (Correct)
- B. only alkyl groups
- C. only hydrogen peroxide
- D. only sulfuric acid
Explanation: They are versatile intermediates in aromatic substitutions.
Salt formation
23. Methylamine with HCl forms:
- A. methylammonium chloride (Correct)
- B. methanol
- C. methyl chloride
- D. formamide
Explanation: The amine is protonated by the acid.
Amines logic
24. A dependable route through this chapter is to track basicity, classification tests, diazonium chemistry, and:
- A. ring-activation effects (Correct)
- B. lattice energy
- C. osmotic pressure
- D. semiconductor doping
Explanation: Those explain most aromatic amine reactions.
Overall
25. The most NEET-relevant split in amines is aliphatic basicity versus:
- A. aromatic diazonium chemistry (Correct)
- B. gas laws
- C. solid-state defects
- D. redox titration
Explanation: These are the two biggest scoring zones.
Definition
26. Amines are derivatives of ammonia in which H is replaced by:
- A. alkyl or aryl groups (Correct)
- B. oxygen only
- C. carbonyl groups only
- D. metals
Explanation: Amines are classified by organic substitution on NH$_3$.
Classification
27. A primary amine has nitrogen attached to:
- A. one carbon group (Correct)
- B. two carbon groups
- C. three carbon groups
- D. no carbon group
Explanation: RNH$_2$ is a primary amine.
Classification
28. Aniline is:
- A. an aromatic primary amine (Correct)
- B. an aliphatic tertiary amine
- C. an amide
- D. a nitro compound
Explanation: Aniline is aminobenzene.
Basicity
29. Amines behave as bases because nitrogen has:
- A. a lone pair (Correct)
- B. a carbonyl group
- C. a positive charge
- D. a halogen
Explanation: The lone pair accepts a proton.
Basicity order
30. In aqueous solution, aliphatic amines often show basic strength order:
- A. 2$^\circ$ > 1$^\circ$ > 3$^\circ$ > NH$_3$ (Correct)
- B. 3$^\circ$ > 2$^\circ$ > 1$^\circ$
- C. NH$_3$ > 1$^\circ$ > 2$^\circ$
- D. all equal
Explanation: Inductive effect and solvation together control the order.
Aromatic amines
31. Aniline is less basic than methylamine mainly because in aniline the lone pair is:
- A. delocalized into the benzene ring (Correct)
- B. more localized
- C. attached to oxygen
- D. positively charged
Explanation: Resonance reduces availability of the lone pair.
Preparation
32. Primary amines can be prepared by reduction of:
- A. nitro compounds (Correct)
- B. alcohols only
- C. alkenes only
- D. ethers
Explanation: Nitro group reduction gives amines.
Reaction
33. Amines react with acids to form:
- A. ammonium salts (Correct)
- B. esters
- C. ethers
- D. aldehydes
Explanation: Protonation of the amine occurs.
Carbylamine
34. Carbylamine test is given by:
- A. primary amines (Correct)
- B. secondary amines
- C. tertiary amines
- D. amides only
Explanation: Primary amines form foul-smelling isocyanides.
Hinsberg
35. Hinsberg reagent is used to distinguish:
- A. 1$^\circ$, 2$^\circ$, and 3$^\circ$ amines (Correct)
- B. alcohols and phenols
- C. aldehydes and ketones
- D. alkanes and alkenes
Explanation: Different sulfonamide behavior helps classify amines.
Diazotization
36. Aniline on treatment with NaNO$_2$/HCl at 0-5°C forms:
- A. benzene diazonium chloride (Correct)
- B. nitrobenzene
- C. phenol directly
- D. benzoic acid
Explanation: Primary aromatic amines undergo diazotization.
Coupling
37. Benzene diazonium chloride couples with phenol in alkaline medium to form:
- A. azo dye (Correct)
- B. ether
- C. amide
- D. alkane
Explanation: Azo coupling gives brightly colored compounds.
Acylation
38. Acylation of aniline reduces activating effect of -NH$_2$ because:
- A. the lone pair becomes less available (Correct)
- B. nitrogen becomes metallic
- C. ring becomes saturated
- D. a halogen is introduced
Explanation: Protection by acylation moderates ring activation.
Sandmeyer
39. Sandmeyer reaction is used to replace diazonium group by:
- A. Cl, Br, or CN (Correct)
- B. only H
- C. only OH
- D. only NH$_2$
Explanation: Cu(I) salts assist these substitutions.
Reaction with nitrous acid
40. Primary aliphatic amines with nitrous acid generally form:
- A. alcohols with N$_2$ evolution (Correct)
- B. stable diazonium salts
- C. amides
- D. azo dyes
Explanation: Unstable aliphatic diazonium intermediates decompose.
Physical property
41. Lower aliphatic amines are soluble in water mainly because of:
- A. hydrogen bonding (Correct)
- B. ionic lattice
- C. metallic bonds
- D. lack of polarity
Explanation: They H-bond with water through N-H and lone pair.
Order
42. In gas phase, basicity of simple aliphatic amines generally follows:
- A. 3$^\circ$ > 2$^\circ$ > 1$^\circ$ > NH$_3$ (Correct)
- B. NH$_3$ > 1$^\circ$ > 2$^\circ$
- C. 1$^\circ$ > 2$^\circ$ > 3$^\circ$
- D. all same
Explanation: Without solvation, +I effect dominates more strongly.
Structure
43. Nitrogen in amines is generally:
- A. sp$^3$ hybridized and pyramidal (Correct)
- B. sp$^2$ planar always
- C. sp linear
- D. dsp$^2$
Explanation: One lone pair gives pyramidal geometry.
Aniline reaction
44. Aniline with bromine water readily forms:
- A. 2,4,6-tribromoaniline (Correct)
- B. bromobenzene
- C. benzoic acid
- D. anisole
Explanation: The amino group strongly activates the ring.
Identification
45. Which test most directly confirms a primary amine in school-level organic chemistry?
- A. Carbylamine test (Correct)
- B. FeCl$_3$ test
- C. Tollens test
- D. Lucas test
Explanation: It is characteristic for primary amines.
Protection
46. Aniline is often acetylated before nitration mainly to:
- A. avoid over-activation and oxidation (Correct)
- B. increase basicity greatly
- C. remove the amino group
- D. make the ring non-aromatic
Explanation: Protection controls substitution more cleanly.
Diazonium utility
47. Aryl diazonium salts are especially useful because they allow introduction of:
- A. different substituents onto aromatic ring (Correct)
- B. only alkyl groups
- C. only hydrogen peroxide
- D. only sulfuric acid
Explanation: They are versatile intermediates in aromatic substitutions.
Salt formation
48. Methylamine with HCl forms:
- A. methylammonium chloride (Correct)
- B. methanol
- C. methyl chloride
- D. formamide
Explanation: The amine is protonated by the acid.
Amines logic
49. A dependable route through this chapter is to track basicity, classification tests, diazonium chemistry, and:
- A. ring-activation effects (Correct)
- B. lattice energy
- C. osmotic pressure
- D. semiconductor doping
Explanation: Those explain most aromatic amine reactions.
Overall
50. The most NEET-relevant split in amines is aliphatic basicity versus:
- A. aromatic diazonium chemistry (Correct)
- B. gas laws
- C. solid-state defects
- D. redox titration
Explanation: These are the two biggest scoring zones.
Definition
51. Amines are derivatives of ammonia in which H is replaced by:
- A. alkyl or aryl groups (Correct)
- B. oxygen only
- C. carbonyl groups only
- D. metals
Explanation: Amines are classified by organic substitution on NH$_3$.
Classification
52. A primary amine has nitrogen attached to:
- A. one carbon group (Correct)
- B. two carbon groups
- C. three carbon groups
- D. no carbon group
Explanation: RNH$_2$ is a primary amine.
Classification
53. Aniline is:
- A. an aromatic primary amine (Correct)
- B. an aliphatic tertiary amine
- C. an amide
- D. a nitro compound
Explanation: Aniline is aminobenzene.
Basicity
54. Amines behave as bases because nitrogen has:
- A. a lone pair (Correct)
- B. a carbonyl group
- C. a positive charge
- D. a halogen
Explanation: The lone pair accepts a proton.
Basicity order
55. In aqueous solution, aliphatic amines often show basic strength order:
- A. 2$^\circ$ > 1$^\circ$ > 3$^\circ$ > NH$_3$ (Correct)
- B. 3$^\circ$ > 2$^\circ$ > 1$^\circ$
- C. NH$_3$ > 1$^\circ$ > 2$^\circ$
- D. all equal
Explanation: Inductive effect and solvation together control the order.
Aromatic amines
56. Aniline is less basic than methylamine mainly because in aniline the lone pair is:
- A. delocalized into the benzene ring (Correct)
- B. more localized
- C. attached to oxygen
- D. positively charged
Explanation: Resonance reduces availability of the lone pair.
Preparation
57. Primary amines can be prepared by reduction of:
- A. nitro compounds (Correct)
- B. alcohols only
- C. alkenes only
- D. ethers
Explanation: Nitro group reduction gives amines.
Reaction
58. Amines react with acids to form:
- A. ammonium salts (Correct)
- B. esters
- C. ethers
- D. aldehydes
Explanation: Protonation of the amine occurs.
Carbylamine
59. Carbylamine test is given by:
- A. primary amines (Correct)
- B. secondary amines
- C. tertiary amines
- D. amides only
Explanation: Primary amines form foul-smelling isocyanides.
Hinsberg
60. Hinsberg reagent is used to distinguish:
- A. 1$^\circ$, 2$^\circ$, and 3$^\circ$ amines (Correct)
- B. alcohols and phenols
- C. aldehydes and ketones
- D. alkanes and alkenes
Explanation: Different sulfonamide behavior helps classify amines.
Diazotization
61. Aniline on treatment with NaNO$_2$/HCl at 0-5°C forms:
- A. benzene diazonium chloride (Correct)
- B. nitrobenzene
- C. phenol directly
- D. benzoic acid
Explanation: Primary aromatic amines undergo diazotization.
Coupling
62. Benzene diazonium chloride couples with phenol in alkaline medium to form:
- A. azo dye (Correct)
- B. ether
- C. amide
- D. alkane
Explanation: Azo coupling gives brightly colored compounds.
Acylation
63. Acylation of aniline reduces activating effect of -NH$_2$ because:
- A. the lone pair becomes less available (Correct)
- B. nitrogen becomes metallic
- C. ring becomes saturated
- D. a halogen is introduced
Explanation: Protection by acylation moderates ring activation.
Sandmeyer
64. Sandmeyer reaction is used to replace diazonium group by:
- A. Cl, Br, or CN (Correct)
- B. only H
- C. only OH
- D. only NH$_2$
Explanation: Cu(I) salts assist these substitutions.
Reaction with nitrous acid
65. Primary aliphatic amines with nitrous acid generally form:
- A. alcohols with N$_2$ evolution (Correct)
- B. stable diazonium salts
- C. amides
- D. azo dyes
Explanation: Unstable aliphatic diazonium intermediates decompose.
Physical property
66. Lower aliphatic amines are soluble in water mainly because of:
- A. hydrogen bonding (Correct)
- B. ionic lattice
- C. metallic bonds
- D. lack of polarity
Explanation: They H-bond with water through N-H and lone pair.
Order
67. In gas phase, basicity of simple aliphatic amines generally follows:
- A. 3$^\circ$ > 2$^\circ$ > 1$^\circ$ > NH$_3$ (Correct)
- B. NH$_3$ > 1$^\circ$ > 2$^\circ$
- C. 1$^\circ$ > 2$^\circ$ > 3$^\circ$
- D. all same
Explanation: Without solvation, +I effect dominates more strongly.
Structure
68. Nitrogen in amines is generally:
- A. sp$^3$ hybridized and pyramidal (Correct)
- B. sp$^2$ planar always
- C. sp linear
- D. dsp$^2$
Explanation: One lone pair gives pyramidal geometry.
Aniline reaction
69. Aniline with bromine water readily forms:
- A. 2,4,6-tribromoaniline (Correct)
- B. bromobenzene
- C. benzoic acid
- D. anisole
Explanation: The amino group strongly activates the ring.
Identification
70. Which test most directly confirms a primary amine in school-level organic chemistry?
- A. Carbylamine test (Correct)
- B. FeCl$_3$ test
- C. Tollens test
- D. Lucas test
Explanation: It is characteristic for primary amines.
Protection
71. Aniline is often acetylated before nitration mainly to:
- A. avoid over-activation and oxidation (Correct)
- B. increase basicity greatly
- C. remove the amino group
- D. make the ring non-aromatic
Explanation: Protection controls substitution more cleanly.
Diazonium utility
72. Aryl diazonium salts are especially useful because they allow introduction of:
- A. different substituents onto aromatic ring (Correct)
- B. only alkyl groups
- C. only hydrogen peroxide
- D. only sulfuric acid
Explanation: They are versatile intermediates in aromatic substitutions.
Salt formation
73. Methylamine with HCl forms:
- A. methylammonium chloride (Correct)
- B. methanol
- C. methyl chloride
- D. formamide
Explanation: The amine is protonated by the acid.
Amines logic
74. A dependable route through this chapter is to track basicity, classification tests, diazonium chemistry, and:
- A. ring-activation effects (Correct)
- B. lattice energy
- C. osmotic pressure
- D. semiconductor doping
Explanation: Those explain most aromatic amine reactions.
Overall
75. The most NEET-relevant split in amines is aliphatic basicity versus:
- A. aromatic diazonium chemistry (Correct)
- B. gas laws
- C. solid-state defects
- D. redox titration
Explanation: These are the two biggest scoring zones.
Definition
76. Amines are derivatives of ammonia in which H is replaced by:
- A. alkyl or aryl groups (Correct)
- B. oxygen only
- C. carbonyl groups only
- D. metals
Explanation: Amines are classified by organic substitution on NH$_3$.
Classification
77. A primary amine has nitrogen attached to:
- A. one carbon group (Correct)
- B. two carbon groups
- C. three carbon groups
- D. no carbon group
Explanation: RNH$_2$ is a primary amine.
Classification
78. Aniline is:
- A. an aromatic primary amine (Correct)
- B. an aliphatic tertiary amine
- C. an amide
- D. a nitro compound
Explanation: Aniline is aminobenzene.
Basicity
79. Amines behave as bases because nitrogen has:
- A. a lone pair (Correct)
- B. a carbonyl group
- C. a positive charge
- D. a halogen
Explanation: The lone pair accepts a proton.
Basicity order
80. In aqueous solution, aliphatic amines often show basic strength order:
- A. 2$^\circ$ > 1$^\circ$ > 3$^\circ$ > NH$_3$ (Correct)
- B. 3$^\circ$ > 2$^\circ$ > 1$^\circ$
- C. NH$_3$ > 1$^\circ$ > 2$^\circ$
- D. all equal
Explanation: Inductive effect and solvation together control the order.
Aromatic amines
81. Aniline is less basic than methylamine mainly because in aniline the lone pair is:
- A. delocalized into the benzene ring (Correct)
- B. more localized
- C. attached to oxygen
- D. positively charged
Explanation: Resonance reduces availability of the lone pair.
Preparation
82. Primary amines can be prepared by reduction of:
- A. nitro compounds (Correct)
- B. alcohols only
- C. alkenes only
- D. ethers
Explanation: Nitro group reduction gives amines.
Reaction
83. Amines react with acids to form:
- A. ammonium salts (Correct)
- B. esters
- C. ethers
- D. aldehydes
Explanation: Protonation of the amine occurs.
Carbylamine
84. Carbylamine test is given by:
- A. primary amines (Correct)
- B. secondary amines
- C. tertiary amines
- D. amides only
Explanation: Primary amines form foul-smelling isocyanides.
Hinsberg
85. Hinsberg reagent is used to distinguish:
- A. 1$^\circ$, 2$^\circ$, and 3$^\circ$ amines (Correct)
- B. alcohols and phenols
- C. aldehydes and ketones
- D. alkanes and alkenes
Explanation: Different sulfonamide behavior helps classify amines.
Diazotization
86. Aniline on treatment with NaNO$_2$/HCl at 0-5°C forms:
- A. benzene diazonium chloride (Correct)
- B. nitrobenzene
- C. phenol directly
- D. benzoic acid
Explanation: Primary aromatic amines undergo diazotization.
Coupling
87. Benzene diazonium chloride couples with phenol in alkaline medium to form:
- A. azo dye (Correct)
- B. ether
- C. amide
- D. alkane
Explanation: Azo coupling gives brightly colored compounds.
Acylation
88. Acylation of aniline reduces activating effect of -NH$_2$ because:
- A. the lone pair becomes less available (Correct)
- B. nitrogen becomes metallic
- C. ring becomes saturated
- D. a halogen is introduced
Explanation: Protection by acylation moderates ring activation.
Sandmeyer
89. Sandmeyer reaction is used to replace diazonium group by:
- A. Cl, Br, or CN (Correct)
- B. only H
- C. only OH
- D. only NH$_2$
Explanation: Cu(I) salts assist these substitutions.
Reaction with nitrous acid
90. Primary aliphatic amines with nitrous acid generally form:
- A. alcohols with N$_2$ evolution (Correct)
- B. stable diazonium salts
- C. amides
- D. azo dyes
Explanation: Unstable aliphatic diazonium intermediates decompose.
Physical property
91. Lower aliphatic amines are soluble in water mainly because of:
- A. hydrogen bonding (Correct)
- B. ionic lattice
- C. metallic bonds
- D. lack of polarity
Explanation: They H-bond with water through N-H and lone pair.
Order
92. In gas phase, basicity of simple aliphatic amines generally follows:
- A. 3$^\circ$ > 2$^\circ$ > 1$^\circ$ > NH$_3$ (Correct)
- B. NH$_3$ > 1$^\circ$ > 2$^\circ$
- C. 1$^\circ$ > 2$^\circ$ > 3$^\circ$
- D. all same
Explanation: Without solvation, +I effect dominates more strongly.
Structure
93. Nitrogen in amines is generally:
- A. sp$^3$ hybridized and pyramidal (Correct)
- B. sp$^2$ planar always
- C. sp linear
- D. dsp$^2$
Explanation: One lone pair gives pyramidal geometry.
Aniline reaction
94. Aniline with bromine water readily forms:
- A. 2,4,6-tribromoaniline (Correct)
- B. bromobenzene
- C. benzoic acid
- D. anisole
Explanation: The amino group strongly activates the ring.
Identification
95. Which test most directly confirms a primary amine in school-level organic chemistry?
- A. Carbylamine test (Correct)
- B. FeCl$_3$ test
- C. Tollens test
- D. Lucas test
Explanation: It is characteristic for primary amines.
Protection
96. Aniline is often acetylated before nitration mainly to:
- A. avoid over-activation and oxidation (Correct)
- B. increase basicity greatly
- C. remove the amino group
- D. make the ring non-aromatic
Explanation: Protection controls substitution more cleanly.
Diazonium utility
97. Aryl diazonium salts are especially useful because they allow introduction of:
- A. different substituents onto aromatic ring (Correct)
- B. only alkyl groups
- C. only hydrogen peroxide
- D. only sulfuric acid
Explanation: They are versatile intermediates in aromatic substitutions.
Salt formation
98. Methylamine with HCl forms:
- A. methylammonium chloride (Correct)
- B. methanol
- C. methyl chloride
- D. formamide
Explanation: The amine is protonated by the acid.
Amines logic
99. A dependable route through this chapter is to track basicity, classification tests, diazonium chemistry, and:
- A. ring-activation effects (Correct)
- B. lattice energy
- C. osmotic pressure
- D. semiconductor doping
Explanation: Those explain most aromatic amine reactions.
Overall
100. The most NEET-relevant split in amines is aliphatic basicity versus:
- A. aromatic diazonium chemistry (Correct)
- B. gas laws
- C. solid-state defects
- D. redox titration
Explanation: These are the two biggest scoring zones.
Definition
101. Amines are derivatives of ammonia in which H is replaced by:
- A. alkyl or aryl groups (Correct)
- B. oxygen only
- C. carbonyl groups only
- D. metals
Explanation: Amines are classified by organic substitution on NH$_3$.
Classification
102. A primary amine has nitrogen attached to:
- A. one carbon group (Correct)
- B. two carbon groups
- C. three carbon groups
- D. no carbon group
Explanation: RNH$_2$ is a primary amine.
Classification
103. Aniline is:
- A. an aromatic primary amine (Correct)
- B. an aliphatic tertiary amine
- C. an amide
- D. a nitro compound
Explanation: Aniline is aminobenzene.
Basicity
104. Amines behave as bases because nitrogen has:
- A. a lone pair (Correct)
- B. a carbonyl group
- C. a positive charge
- D. a halogen
Explanation: The lone pair accepts a proton.
Basicity order
105. In aqueous solution, aliphatic amines often show basic strength order:
- A. 2$^\circ$ > 1$^\circ$ > 3$^\circ$ > NH$_3$ (Correct)
- B. 3$^\circ$ > 2$^\circ$ > 1$^\circ$
- C. NH$_3$ > 1$^\circ$ > 2$^\circ$
- D. all equal
Explanation: Inductive effect and solvation together control the order.
Aromatic amines
106. Aniline is less basic than methylamine mainly because in aniline the lone pair is:
- A. delocalized into the benzene ring (Correct)
- B. more localized
- C. attached to oxygen
- D. positively charged
Explanation: Resonance reduces availability of the lone pair.
Preparation
107. Primary amines can be prepared by reduction of:
- A. nitro compounds (Correct)
- B. alcohols only
- C. alkenes only
- D. ethers
Explanation: Nitro group reduction gives amines.
Reaction
108. Amines react with acids to form:
- A. ammonium salts (Correct)
- B. esters
- C. ethers
- D. aldehydes
Explanation: Protonation of the amine occurs.
Carbylamine
109. Carbylamine test is given by:
- A. primary amines (Correct)
- B. secondary amines
- C. tertiary amines
- D. amides only
Explanation: Primary amines form foul-smelling isocyanides.
Hinsberg
110. Hinsberg reagent is used to distinguish:
- A. 1$^\circ$, 2$^\circ$, and 3$^\circ$ amines (Correct)
- B. alcohols and phenols
- C. aldehydes and ketones
- D. alkanes and alkenes
Explanation: Different sulfonamide behavior helps classify amines.
Diazotization
111. Aniline on treatment with NaNO$_2$/HCl at 0-5°C forms:
- A. benzene diazonium chloride (Correct)
- B. nitrobenzene
- C. phenol directly
- D. benzoic acid
Explanation: Primary aromatic amines undergo diazotization.
Coupling
112. Benzene diazonium chloride couples with phenol in alkaline medium to form:
- A. azo dye (Correct)
- B. ether
- C. amide
- D. alkane
Explanation: Azo coupling gives brightly colored compounds.
Acylation
113. Acylation of aniline reduces activating effect of -NH$_2$ because:
- A. the lone pair becomes less available (Correct)
- B. nitrogen becomes metallic
- C. ring becomes saturated
- D. a halogen is introduced
Explanation: Protection by acylation moderates ring activation.
Sandmeyer
114. Sandmeyer reaction is used to replace diazonium group by:
- A. Cl, Br, or CN (Correct)
- B. only H
- C. only OH
- D. only NH$_2$
Explanation: Cu(I) salts assist these substitutions.
Reaction with nitrous acid
115. Primary aliphatic amines with nitrous acid generally form:
- A. alcohols with N$_2$ evolution (Correct)
- B. stable diazonium salts
- C. amides
- D. azo dyes
Explanation: Unstable aliphatic diazonium intermediates decompose.
Physical property
116. Lower aliphatic amines are soluble in water mainly because of:
- A. hydrogen bonding (Correct)
- B. ionic lattice
- C. metallic bonds
- D. lack of polarity
Explanation: They H-bond with water through N-H and lone pair.
Order
117. In gas phase, basicity of simple aliphatic amines generally follows:
- A. 3$^\circ$ > 2$^\circ$ > 1$^\circ$ > NH$_3$ (Correct)
- B. NH$_3$ > 1$^\circ$ > 2$^\circ$
- C. 1$^\circ$ > 2$^\circ$ > 3$^\circ$
- D. all same
Explanation: Without solvation, +I effect dominates more strongly.
Structure
118. Nitrogen in amines is generally:
- A. sp$^3$ hybridized and pyramidal (Correct)
- B. sp$^2$ planar always
- C. sp linear
- D. dsp$^2$
Explanation: One lone pair gives pyramidal geometry.
Aniline reaction
119. Aniline with bromine water readily forms:
- A. 2,4,6-tribromoaniline (Correct)
- B. bromobenzene
- C. benzoic acid
- D. anisole
Explanation: The amino group strongly activates the ring.
Identification
120. Which test most directly confirms a primary amine in school-level organic chemistry?
- A. Carbylamine test (Correct)
- B. FeCl$_3$ test
- C. Tollens test
- D. Lucas test
Explanation: It is characteristic for primary amines.
Protection
121. Aniline is often acetylated before nitration mainly to:
- A. avoid over-activation and oxidation (Correct)
- B. increase basicity greatly
- C. remove the amino group
- D. make the ring non-aromatic
Explanation: Protection controls substitution more cleanly.
Diazonium utility
122. Aryl diazonium salts are especially useful because they allow introduction of:
- A. different substituents onto aromatic ring (Correct)
- B. only alkyl groups
- C. only hydrogen peroxide
- D. only sulfuric acid
Explanation: They are versatile intermediates in aromatic substitutions.
Salt formation
123. Methylamine with HCl forms:
- A. methylammonium chloride (Correct)
- B. methanol
- C. methyl chloride
- D. formamide
Explanation: The amine is protonated by the acid.
Amines logic
124. A dependable route through this chapter is to track basicity, classification tests, diazonium chemistry, and:
- A. ring-activation effects (Correct)
- B. lattice energy
- C. osmotic pressure
- D. semiconductor doping
Explanation: Those explain most aromatic amine reactions.
Overall
125. The most NEET-relevant split in amines is aliphatic basicity versus:
- A. aromatic diazonium chemistry (Correct)
- B. gas laws
- C. solid-state defects
- D. redox titration
Explanation: These are the two biggest scoring zones.

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