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Question 6333
NEET Physics · Hard

Mechanical Properties of Solids: Shear Modulus MCQ

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Shear ModulusHardQuestion 6333

Question

A rubber block (G=0.4 MPa, area=1 cm², height=1 cm) is sheared by 1 N force. Lateral displacement:
  1. A
    0.025 mm
  2. B
    0.25 mm
    Correct
  3. C
    2.5 mm
  4. D
    0.0025 mm

Correct answer

0.25 mm

Explanation

The shear stress is 1/10−4=1041/10^{-4}=10^4 Pa, so the shear strain is 104/(4×105)=0.02510^4/(4×10^5)=0.025. Hence Δx=0.025×0.01=2.5×10−4Δx=0.025×0.01=2.5×10^{-4} m = 0.25 mm.

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