Home/
Competitive Exams/
NEET/
Physics/
Mechanical Properties of Solids/
Question 6387
NEET Physics · Hard

Mechanical Properties of Solids: Advanced Solids Mixed MCQ

Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Advanced Solids MixedHardQuestion 6387

Question

A 10 m steel wire (Y=2×10¹¹, r=1 mm) hangs vertically. Extension due to its own weight (ρ=8000 kg/m³, g=10):
  1. A
    0.2 mm
  2. B
    0.1 mm
  3. C
    0.05 mm
  4. D
    0.02 mm
    Correct

Correct answer

0.02 mm

Explanation

For a uniform vertical wire, ΔL=ρgL2/(2Y)ΔL=ρgL^2/(2Y). Substitution gives 8000×10×100/(4×1011)=2×10−58000×10×100/(4×10^{11})=2×10^{-5} m = 0.02 mm.

Review Mechanical Properties of Solids notesStart timed chapter practice