Spring PEHardQuestion 6034
Question
Two springs (k₁=200, k₂=300 N/m) in series, total stretch 0.3 m. PE stored:
- A5.4 JCorrect
- B10.8 J
- C2.7 J
- D7.2 J
Correct answer
5.4 J
Explanation
k_eq = k₁k₂/(k₁+k₂) = 120 N/m. PE = ½×120×0.09 = 5.4 J.
NEET Physics · Hard
Work, Energy & Power: Spring PE MCQ
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
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