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Practice Test 7
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SSC CGL Divisibility and Remainders Practice Test 7

15 SSC CGL divisibility and remainders questions with chapter-wise explanations and exam-style options.

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SSC CGL Practice Session

SSC CGL Divisibility and Remainders Practice Test 7

15 SSC CGL divisibility and remainders questions with chapter-wise explanations and exam-style options.

Questions
14
Marking
+2 correct, -0.5 wrong
Format
15-question ad-supported session
Preview all 14 questions in SSC CGL Divisibility and Remainders Practice Test 7 (no login required)
  1. Divisibility and Remainders

    1. LCM of 12, 18 and 24 is:

    • A. 48
    • B. 60
    • C. 72 (Correct)
    • D. 96

    Explanation: LCM(12,18,24) = 72.

  2. Divisibility and Remainders

    2. HCF of 36, 54 and 90 is:

    • A. 6
    • B. 9
    • C. 12
    • D. 18 (Correct)

    Explanation: 18 divides all three numbers exactly.

  3. Divisibility and Remainders

    3. Which of the following is divisible by 11?

    • A. 121
    • B. 132
    • C. 143
    • D. All of these (Correct)

    Explanation: 121=11×11, 132=11×12, 143=11×13.

  4. Divisibility and Remainders

    4. Unit digit of 7^52 is:

    • A. 1 (Correct)
    • B. 3
    • C. 7
    • D. 9

    Explanation: Powers of 7 cycle: 7,9,3,1 (period 4). 52÷4=13 remainder 0, so unit digit is 1.

  5. Divisibility and Remainders

    5. What is the remainder when 2^10 is divided by 7?

    • A. 1
    • B. 2 (Correct)
    • C. 3
    • D. 4

    Explanation: 2^3=8≡1(mod7), so 2^9≡1(mod7), then 2^10≡2(mod7).

  6. Divisibility and Remainders

    6. How many factors does 72 have?

    • A. 9
    • B. 12 (Correct)
    • C. 15
    • D. 18

    Explanation: 72=2^3×3^2, factors=(3+1)(2+1)=12.

  7. Divisibility and Remainders

    7. Product of two numbers is 1080 and their HCF is 6. Their LCM is:

    • A. 180 (Correct)
    • B. 200
    • C. 210
    • D. 220

    Explanation: LCM = Product/HCF = 1080/6 = 180.

  8. Divisibility and Remainders

    8. The largest 4-digit number divisible by 18 is:

    • A. 9990 (Correct)
    • B. 9972
    • C. 9981
    • D. 9999

    Explanation: 9990 ÷ 18 = 555 exactly.

  9. Divisibility and Remainders

    9. Find the remainder when 99! is divided by 100.

    • A. 0 (Correct)
    • B. 1
    • C. 25
    • D. 50

    Explanation: Since 99! contains both 4 and 25 as factors, it is divisible by 100.

  10. Divisibility and Remainders

    10. Unit digit of 3^47 is:

    • A. 1
    • B. 3
    • C. 7 (Correct)
    • D. 9

    Explanation: Powers of 3 cycle as 3, 9, 7, 1. Since 47 leaves remainder 3 when divided by 4, the unit digit is 7.

  11. Divisibility and Remainders

    11. Three bells ring at intervals of 6, 8, and 12 minutes. If they ring together at 8:00 AM, when will they ring together again?

    • A. 8:24 AM (Correct)
    • B. 8:30 AM
    • C. 8:36 AM
    • D. 8:48 AM

    Explanation: LCM(6,8,12)=24 minutes. They ring together at 8:24 AM.

  12. Divisibility and Remainders

    12. A number when divided by 5 gives remainder 3 and divided by 7 gives remainder 4. Which of these fits?

    • A. 18
    • B. 28
    • C. 53 (Correct)
    • D. 39

    Explanation: 53÷5=10 rem 3, 53÷7=7 rem 4. Both conditions satisfied.

  13. Divisibility and Remainders

    13. Find the number of zeros at the end of 50!.

    • A. 10
    • B. 12 (Correct)
    • C. 13
    • D. 15

    Explanation: Zeros = ⌊50/5⌋+⌊50/25⌋ = 10+2 = 12.

  14. Divisibility and Remainders

    14. Which is the smallest number divisible by both 8 and 12?

    • A. 16
    • B. 24 (Correct)
    • C. 36
    • D. 48

    Explanation: LCM(8,12) = 24.