SSC CGL Heights and Distances Practice Test 1

1. The value of cos 60° is:

• A. 0
• B. 1/2 (Correct)
• C. √3/2
• D. 1

Explanation: cos 60° is 1/2.

2. The value of tan 30° is:

• A. 1/√3 (Correct)
• B. 1
• C. √3
• D. 1/2

Explanation: tan 30° = 1/√3.

3. sin² A + cos² A is equal to:

• A. 0
• B. 1 (Correct)
• C. tan A
• D. sec A

Explanation: This is the basic trigonometric identity.

4. sin 35° is equal to:

• A. cos 35°
• B. cos 55° (Correct)
• C. tan 55°
• D. sec 35°

Explanation: sin θ = cos (90° - θ).

5. The value of sec 60° is:

• A. 1/2
• B. 1
• C. 2 (Correct)
• D. √3

Explanation: sec 60° = 1 / cos 60° = 2.

6. If tan A = 1, then A may be:

• A. 30°
• B. 45° (Correct)
• C. 60°
• D. 90°

Explanation: tan 45° = 1.

7. The value of cosec 30° is:

• A. 1
• B. 2 (Correct)
• C. √3
• D. 1/2

Explanation: cosec 30° = 1 / sin 30° = 2.

8. cos 20° is equal to:

• A. sin 20°
• B. sin 70° (Correct)
• C. tan 70°
• D. sec 20°

Explanation: cos θ = sin (90° - θ).

9. 1 + tan² A is equal to:

• A. sec² A (Correct)
• B. cosec² A
• C. cot² A
• D. sin² A

Explanation: 1 + tan² A = sec² A.

10. The value of cos 0° is:

• A. 0
• B. 1/2
• C. 1 (Correct)
• D. Undefined

Explanation: cos 0° = 1.

11. The value of tan 45° + sin 30° is:

• A. 1
• B. 3/2 (Correct)
• C. √3/2
• D. 2

Explanation: tan 45° = 1 and sin 30° = 1/2, so sum = 3/2.

12. If sin A = 3/5, then cos A is:

• A. 3/5
• B. 4/5 (Correct)
• C. 5/4
• D. 5/3

Explanation: Using a 3-4-5 triangle, cos A = adjacent/hypotenuse = 4/5.

13. If cos A = 12/13, then tan A is:

• A. 5/12 (Correct)
• B. 12/5
• C. 13/5
• D. 5/13

Explanation: Using a 5-12-13 triangle, tan A = perpendicular/base = 5/12.

14. The value of sin 90° is:

• A. 0
• B. 1/2
• C. 1 (Correct)
• D. √3/2

Explanation: sin 90° = 1.

15. If sec A = 5/4, then cos A is:

• A. 4/5 (Correct)
• B. 5/4
• C. 3/5
• D. 1/5

Explanation: cos A is the reciprocal of sec A.