SSC CGL Number System Practice Test 4
15 fresh SSC CGL number system questions on divisibility, remainders, factors, and digit logic.
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SSC CGL Number System Practice Test 4
15 fresh SSC CGL number system questions on divisibility, remainders, factors, and digit logic.
Preview all 12 questions in SSC CGL Number System Practice Test 4 (no login required)
- Divisibility
1. Which of the following numbers is divisible by 9?
- A. 234 (Correct)
- B. 245
- C. 256
- D. 268
Explanation: The digit sum of 234 is 9, so it is divisible by 9.
- Remainder
2. What is the remainder when 97 is divided by 8?
- A. 1 (Correct)
- B. 2
- C. 3
- D. 4
Explanation: 97 = 8 x 12 + 1.
- Prime Numbers
3. Which of these is a prime number?
- A. 39
- B. 51
- C. 53 (Correct)
- D. 57
Explanation: 53 has no divisor other than 1 and itself.
- LCM
4. LCM of 12 and 18 is:
- A. 24
- B. 30
- C. 36 (Correct)
- D. 48
Explanation: Prime factorization gives LCM = 2^2 x 3^2 = 36.
- HCF
5. HCF of 24 and 54 is:
- A. 4
- B. 6 (Correct)
- C. 8
- D. 12
Explanation: The greatest common divisor of 24 and 54 is 6.
- Remainder
6. If a number leaves remainder 5 when divided by 11, what remainder will it leave when 22 is added to it and divided by 11?
- A. 0
- B. 3
- C. 5 (Correct)
- D. 7
Explanation: Adding 22 adds two full multiples of 11, so the remainder stays 5.
- Digit Sum
7. The sum of digits of the number 58739 is:
- A. 30
- B. 31
- C. 32 (Correct)
- D. 33
Explanation: 5 + 8 + 7 + 3 + 9 = 32.
- Consecutive Numbers
8. The sum of three consecutive even numbers is 54. The middle number is:
- A. 16
- B. 18 (Correct)
- C. 20
- D. 22
Explanation: Let them be x-2, x, x+2. Their sum is 3x = 54, so x = 18.
- Divisibility
9. A number divisible by both 3 and 4 must be divisible by:
- A. 6
- B. 7
- C. 8
- D. 12 (Correct)
Explanation: LCM of 3 and 4 is 12.
- Fractions to Number System
10. Which fraction is the greatest?
- A. 3/5
- B. 5/8 (Correct)
- C. 7/12
- D. 11/20
Explanation: 3/5 = 0.6, 5/8 = 0.625, 7/12 is about 0.583, and 11/20 = 0.55.
- Natural Numbers
11. The smallest natural number is generally taken as:
- A. 0
- B. 1 (Correct)
- C. -1
- D. 2
Explanation: In standard school arithmetic, natural numbers begin at 1.
- Base Value
12. If the base of a numeral system increases, the number of symbols needed for one place value becomes:
- A. Less
- B. More (Correct)
- C. Zero
- D. Fixed at 10
Explanation: A larger base uses more distinct symbols before the next place value is needed.