Chemical and Ionic Equilibrium: Solubility from Ksp MCQ

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Solubility from KspHardQuestion 600425

Question

Ksp of Ag₂CrO₄ = 1.1×10⁻¹². Its molar solubility is:

A
6.5×10⁻⁵ M
Correct
B
1.05×10⁻⁴ M
C
1.1×10⁻⁶ M
D
3.3×10⁻⁵ M

Correct answer

6.5×10⁻⁵ M

Explanation

Ag₂CrO₄ ⇌ 2Ag⁺ + CrO₄²⁻. If s = solubility: [Ag⁺] = 2s, [CrO₄²⁻] = s. Ksp = (2s)²(s) = 4s³ = 1.1×10⁻¹². s³ = 2.75×10⁻¹³. s = (2.75×10⁻¹³)^(1/3) ≈ 6.5×10⁻⁵ M.

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