Chemical and Ionic Equilibrium: pH mixture MCQ

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pH mixtureHardQuestion 600424

Question

50 mL of 0.1 M HCl is added to 50 mL of 0.05 M NaOH. The pH of the resulting solution is:

1.3

Moles HCl = 5×10⁻³, moles NaOH = 2.5×10⁻³. Excess HCl = 2.5×10⁻³ mol in 100 mL → [H⁺] = 0.025 M. pH = −log(0.025) ≈ 1.6.