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Question 600053
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Equivalent Concept MCQ

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Equivalent ConceptHardQuestion 600053

Question

0.53 g of Na₂CO₃ (M=106) is dissolved and titrated with 0.1 N HCl. Volume of HCl consumed is:
  1. A
    50 mL
  2. B
    100 mL
    Correct
  3. C
    25 mL
  4. D
    10 mL

Correct answer

100 mL

Explanation

Equivalents of Na₂CO₃ = (0.53/106) × 2 = 0.01 equiv. N×V = equiv → 0.1 × V = 0.01 → V = 0.1 L = 100 mL.

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