Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Mole Concept and Stoichiometry/
Question 600054
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Stoichiometry MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
StoichiometryHardQuestion 600054

Question

In the Haber process: N₂ + 3H₂ ⇌ 2NH₃. If 28 kg N₂ and 12 kg H₂ are fed with 30% conversion, kg of NH₃ produced is:
  1. A
    10.2 kg
    Correct
  2. B
    5.1 kg
  3. C
    15.3 kg
  4. D
    20.4 kg

Correct answer

10.2 kg

Explanation

n(N₂) = 1000 mol, n(H₂) = 6000 mol. Limiting: need 3000 mol H₂ per 1000 N₂ → H₂ has 6000 mol vs needed 3000 → N₂ limits. Max NH₃ = 2000 mol = 34 kg. At 30% conversion: 0.3 × 34 = 10.2 kg.

Review Mole Concept and Stoichiometry notesStart timed chapter practice