Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Mole Concept and Stoichiometry/
Question 600069
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Mixture Stoichiometry MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Practice and revisionDetailed answer reviewMobile-friendly flow
Mixture StoichiometryHardQuestion 600069

Question

A mixture of FeO and Fe₂O₃ contains 72% Fe by mass. Mole ratio FeO:Fe₂O₃ is:
  1. A
    10:13
    Correct
  2. B
    1:1
  3. C
    2:1
  4. D
    1:2

Correct answer

10:13

Explanation

Let the amounts be x and y mol. Then 56x+112y=0.72(72x+160y)56x+112y=0.72(72x+160y), so 4.16x=3.2y4.16x=3.2y. Therefore x:y=3.2:4.16=<strong>10:13</strong>x:y=3.2:4.16=<strong>10:13</strong>.

Review Mole Concept and Stoichiometry notesStart timed chapter practice