JEE Chemistry · Hard

Mole Concept and Stoichiometry: Volume Stoichiometry MCQ

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Volume StoichiometryHardQuestion 600070

Question

At STP, 2.24 L of a gaseous hydrocarbon CₙH₂ₙ is completely burned. The CO₂ produced occupies 4.48 L at STP. n is:
  1. A
    1
  2. B
    2
    Correct
  3. C
    3
  4. D
    4

Correct answer

2

Explanation

n(hydrocarbon) = 2.24/22.4 = 0.1 mol. n(CO₂) = 4.48/22.4 = 0.2 mol. CO₂/hydrocarbon = 2 → each molecule has 2 C atoms → n = 2. Compound is C₂H₄ (ethylene).