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Question 700012
JEE Chemistry · Hard

Redox Reactions: JEE Main MCQ

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JEE MainHardQuestion 700012

Question

The oxidation state of Xe in XeO₄ is:
  1. A
    +8
    Correct
  2. B
    +6
  3. C
    +4
  4. D
    +2

Correct answer

+8

Explanation

XeO₄: x + 4(−2) = 0 → x = +8. Xenon in XeO₄ has the highest common oxidation state of +8.

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