JEE Chemistry · Hard

Redox Reactions: Balancing complex MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Balancing complexHardQuestion 700013

Question

In the acidic permanganate-oxalate titration (KMnO₄ + H₂C₂O₄), the volume of 0.1 M KMnO₄ needed to react with 25 mL of 0.1 M H₂C₂O₄ is:
  1. A
    10 mL
    Correct
  2. B
    25 mL
  3. C
    5 mL
  4. D
    50 mL

Correct answer

10 mL

Explanation

n-factor of KMnO₄ = 5 (Mn: +7→+2). n-factor of H₂C₂O₄ = 2 (C: +3→+4). meq of oxalate = 25×0.1×2 = 5 meq. meq of KMnO₄ = V×0.1×5 = 5 → V = 10 mL.