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Question 700014
JEE Chemistry · Hard

Redox Reactions: JEE Advanced MCQ

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JEE AdvancedHardQuestion 700014

Question

In the reaction: 3Br₂ + 6NaOH → 5NaBr + NaBrO₃ + 3H₂O, the fraction of Br₂ acting as reducing agent is:
  1. A
    1/3
  2. B
    2/3
  3. C
    1/6
    Correct
  4. D
    5/6

Correct answer

1/6

Explanation

Of the six Br atoms supplied by 3Br₂, one is oxidised from 0 to +5 and therefore acts as the reducing agent. That atom represents 0.5 mol Br₂, so the required fraction is 0.5/3=<strong>1/6</strong>0.5/3=<strong>1/6</strong>.

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