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Question 750006
JEE Chemistry · Medium

Solutions and Colligative Properties: Boiling point elevation MCQ

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Boiling point elevationMediumQuestion 750006

Question

ΔTb = Kb × m. If Kb of water = 0.52 K kg mol⁻¹ and 1 mol glucose is dissolved in 1 kg water, ΔTb is:
  1. A
    0.52 K
    Correct
  2. B
    1.04 K
  3. C
    0.26 K
  4. D
    5.2 K

Correct answer

0.52 K

Explanation

ΔTb = Kb × m = 0.52 × 1 = 0.52 K. The new boiling point = 100 + 0.52 = 100.52°C.

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