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Kinetic Theory and Thermodynamics: Adiabatic Process MCQ

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Adiabatic ProcessHardQuestion 31070

Question

For adiabatic process, TV^(γ−1) = constant. If volume doubles adiabatically, temperature ratio T₂/T₁ for diatomic gas (γ = 1.4) is:
  1. A
    2^0.4
  2. B
    2^(−0.4)
    Correct
  3. C
    2^1.4
  4. D
    2^(−1.4)

Correct answer

2^(−0.4)

Explanation

T₁V₁^(γ−1) = T₂V₂^(γ−1). T₂/T₁ = (V₁/V₂)^(γ−1) = (1/2)^0.4 = 2^(−0.4).

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