Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Kinetic Theory and Thermodynamics/
Question 31071
JEE Physics · Hard

Kinetic Theory and Thermodynamics: Carnot Engine MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Carnot EngineHardQuestion 31071

Question

Two identical bodies at temperatures T₁ and T₂ (T₁ > T₂) are used as source and sink. After Carnot engine runs until both reach same temperature T_f, maximum work output is:
  1. A
    nCv(T₁+T₂−2T_f)
    Correct
  2. B
    nCv(T₁−T₂)
  3. C
    nCv(T₁+T₂)
  4. D
    nCp(T₁−T₂)

Correct answer

nCv(T₁+T₂−2T_f)

Explanation

T_f = √(T₁T₂) for maximum work. W = nCv(T₁ + T₂ − 2T_f) = nCv(T₁ + T₂ − 2√(T₁T₂)).

Review Kinetic Theory and Thermodynamics notesStart timed chapter practice