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Question 30285
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Laws of Motion and Friction: Advanced — Friction Work MCQ

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Advanced — Friction WorkHardQuestion 30285

Question

Block A (4 kg) slides over block B (6 kg) for 2 m relative displacement. μ between blocks = 0.3. Energy dissipated as heat is: (g = 10)
  1. A
    12 J
  2. B
    24 J
    Correct
  3. C
    36 J
  4. D
    6 J

Correct answer

24 J

Explanation

Friction force between blocks = μ × m_A × g = 0.3×4×10 = 12 N. Energy dissipated = friction force × relative displacement = 12×2 = 24 J.

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