JEE Physics · Hard

Laws of Motion and Friction: Advanced — Impulsive Force MCQ

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Advanced — Impulsive ForceHardQuestion 30286

Question

A ball (0.2 kg) hits a wall at 10 m/s and rebounds at 8 m/s. Contact time is 0.01 s. Average force exerted by ball on wall is:
  1. A
    20 N
  2. B
    36 N
  3. C
    360 N
    Correct
  4. D
    40 N

Correct answer

360 N

Explanation

Δp = m(v_f − v_i) for ball: 0.2×(−8−10) = −3.6 N·s (taking initial direction as positive). |Δp| = 3.6 N·s. Force on ball from wall = 3.6/0.01 = 360 N. By Newton's 3rd law, force on wall = 360 N.