Advanced — Impulsive ForceHardQuestion 30286
Question
A ball (0.2 kg) hits a wall at 10 m/s and rebounds at 8 m/s. Contact time is 0.01 s. Average force exerted by ball on wall is:
- A20 N
- B36 N
- C360 NCorrect
- D40 N
Correct answer
360 N
Explanation
Δp = m(v_f − v_i) for ball: 0.2×(−8−10) = −3.6 N·s (taking initial direction as positive). |Δp| = 3.6 N·s. Force on ball from wall = 3.6/0.01 = 360 N. By Newton's 3rd law, force on wall = 360 N.