System of Particles & Rotational Motion: Centre of Mass MCQ

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Centre of MassHardQuestion 6103

Question

A uniform rod (length L, mass M) has a small ball (mass m) at one end. COM from rod end (ball side):

A
ML/[2(M+m)]
Correct
B
ML/(M+m)
C
mL/M
D
L/2

Correct answer

ML/[2(M+m)]

Explanation

Taking the ball end as the origin, the ball is at $x=0$ and the rod's centre is at $x=L/2$ . Hence $x_{cm}=[m(0)+M(L/2)]/(M+m)=<strong>ML/[2(M+m)]</strong>$ .

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