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Question 6116
NEET Physics · Hard

System of Particles & Rotational Motion: Moment of Inertia MCQ

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Moment of InertiaHardQuestion 6116

Question

MI of a thin ring (mass M, radius R) about diameter:
  1. A
    MR²
  2. B
    MR²/2
    Correct
  3. C
    2MR²
  4. D
    MR²/4

Correct answer

MR²/2

Explanation

I_ring (diameter) = MR²/2 (by perpendicular axis theorem: MR² = 2I_d). I_d = MR²/2.

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