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Probability Test 10
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Probability Test 10

Bilingual timed test for SSC, RRB and Banking quant with clean Hindi, preserved math symbols and detailed solutions.

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Batch 2 | SSC RRB Banking

Probability Test 10

25 bilingual MCQs from Probability, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Designed for cross-exam quantitative aptitude practice with preserved ₹, ×, %, ratios and Hindi wording.

Questions
25
Duration
25 min
Marking
+1 / -0.25
Sections
Probability | 25 questions

Question Palette Legend

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Preview all 25 questions in Probability Test 10 (no login required)
  1. Probability — Without replacement

    1. A bag contains 5 red and 6 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 5 लाल और 6 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।

    • A. 29/220
    • B. 2/11 (Correct)
    • C. 51/220
    • D. 5/11

    Explanation: Without replacement: P(two red) = 5/11 × 4/10 = 2/11. / बिना replacement: P(दोनों लाल) = 5/11 × 4/10 = 2/11.

  2. Probability — Without replacement

    2. A bag contains 6 red and 7 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 6 लाल और 7 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।

    • A. 37/260
    • B. 6/13
    • C. 63/260
    • D. 5/26 (Correct)

    Explanation: Without replacement: P(two red) = 6/13 × 5/12 = 5/26. / बिना replacement: P(दोनों लाल) = 6/13 × 5/12 = 5/26.

  3. Probability — Card combination probability

    3. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।

    • A. 1/221 (Correct)
    • B. 2/221
    • C. 3/221
    • D. 1/13

    Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.

  4. Probability — Card combination probability

    4. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।

    • A. 1/13
    • B. 1/221 (Correct)
    • C. 3/221
    • D. 2/221

    Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.

  5. Probability — Exactly one event

    5. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।

    • A. 3/4
    • B. 1/8
    • C. 1/2 (Correct)
    • D. 1/4

    Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.

  6. Probability — Exactly one event

    6. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।

    • A. 1/2 (Correct)
    • B. 3/4
    • C. 1/4
    • D. 1/8

    Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.

  7. Probability — Complement probability

    7. A lot has 13 items including 3 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 13 वस्तुएँ हैं जिनमें 3 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।

    • A. 97/260
    • B. 123/260
    • C. 11/26 (Correct)
    • D. 3/13

    Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 10C2/13C2 = 11/26. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 10C2/13C2 = 11/26.

  8. Probability — Complement probability

    8. A lot has 14 items including 4 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 14 वस्तुएँ हैं जिनमें 4 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।

    • A. 1011/1820
    • B. 46/91 (Correct)
    • C. 2/7
    • D. 829/1820

    Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 10C2/14C2 = 46/91. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 10C2/14C2 = 46/91.

  9. Probability — Two dice sum

    9. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।

    • A. 1/9
    • B. 1/6 (Correct)
    • C. 1/12
    • D. 1/4

    Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.

  10. Probability — Two dice sum

    10. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।

    • A. 1/4
    • B. 1/9
    • C. 1/6 (Correct)
    • D. 1/12

    Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.

  11. Probability — Without replacement

    11. A bag contains 5 red and 6 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 5 लाल और 6 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।

    • A. 29/220
    • B. 51/220
    • C. 5/11
    • D. 2/11 (Correct)

    Explanation: Without replacement: P(two red) = 5/11 × 4/10 = 2/11. / बिना replacement: P(दोनों लाल) = 5/11 × 4/10 = 2/11.

  12. Probability — Without replacement

    12. A bag contains 6 red and 7 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 6 लाल और 7 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।

    • A. 37/260
    • B. 5/26 (Correct)
    • C. 63/260
    • D. 6/13

    Explanation: Without replacement: P(two red) = 6/13 × 5/12 = 5/26. / बिना replacement: P(दोनों लाल) = 6/13 × 5/12 = 5/26.

  13. Probability — Card combination probability

    13. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।

    • A. 3/221
    • B. 2/221
    • C. 1/13
    • D. 1/221 (Correct)

    Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.

  14. Probability — Card combination probability

    14. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।

    • A. 3/221
    • B. 2/221
    • C. 1/13
    • D. 1/221 (Correct)

    Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.

  15. Probability — Exactly one event

    15. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।

    • A. 1/8
    • B. 1/4
    • C. 1/2 (Correct)
    • D. 3/4

    Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.

  16. Probability — Exactly one event

    16. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।

    • A. 3/4
    • B. 1/8
    • C. 1/4
    • D. 1/2 (Correct)

    Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.

  17. Probability — Complement probability

    17. A lot has 15 items including 4 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 15 वस्तुएँ हैं जिनमें 4 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।

    • A. 4/15
    • B. 221/420
    • C. 10/21 (Correct)
    • D. 179/420

    Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 11C2/15C2 = 10/21. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 11C2/15C2 = 10/21.

  18. Probability — Complement probability

    18. A lot has 16 items including 2 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 16 वस्तुएँ हैं जिनमें 2 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।

    • A. 29/120 (Correct)
    • B. 1/8
    • C. 23/120
    • D. 7/24

    Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 14C2/16C2 = 29/120. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 14C2/16C2 = 29/120.

  19. Probability — Two dice sum

    19. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।

    • A. 1/12
    • B. 1/6 (Correct)
    • C. 1/4
    • D. 1/9

    Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.

  20. Probability — Two dice sum

    20. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।

    • A. 1/4
    • B. 1/9
    • C. 1/12
    • D. 1/6 (Correct)

    Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.

  21. Probability — Percentage / प्रतिशत

    21. 12% of 775 is: / 775 का 12% कितना है?

    • A. 83
    • B. 93 (Correct)
    • C. 103
    • D. 113

    Explanation: 12% = 12/100, so answer = 93. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।

  22. Probability — Profit-Loss / लाभ-हानि

    22. An article bought for Rs 900 is sold at 15% profit. Find SP. / Rs 900 में खरीदी वस्तु 15% लाभ पर बेची गई। SP ज्ञात करें।

    • A. Rs 995
    • B. Rs 1035 (Correct)
    • C. Rs 1075
    • D. Rs 1115

    Explanation: SP = CP x (100 + profit%)/100 = 900 x 115/100 = Rs 1035. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।

  23. Probability — Time & Work / समय और कार्य

    23. A finishes a work in 18 days and B in 24 days. Together they finish in: / A 18 दिन और B 24 दिन में काम पूरा करते हैं। साथ में समय?

    • A. 9.3 days
    • B. 10.3 days (Correct)
    • C. 11.3 days
    • D. 12.3 days

    Explanation: Combined time = ab/(a+b) = 18 x 24 / 42 = 10.3 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।

  24. Probability — Speed Conversion / चाल परिवर्तन

    24. 54 km/h equals: / 54 किमी/घंटा बराबर है:

    • A. 12 m/s
    • B. 15 m/s (Correct)
    • C. 18 m/s
    • D. 20 m/s

    Explanation: km/h to m/s conversion uses x 5/18. 54 x 5/18 = 15. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।

  25. Probability — Simplification / सरलीकरण

    25. Simplify: 23 x 18 + 23 - 18. / सरल करें: 23 x 18 + 23 - 18.

    • A. 411
    • B. 419 (Correct)
    • C. 427
    • D. 435

    Explanation: Apply BODMAS: 414 + 23 - 18 = 419. / पहले गुणा, फिर जोड़-घटाव करें।