Probability Test 9
Bilingual timed test for SSC, RRB and Banking quant with clean Hindi, preserved math symbols and detailed solutions.
Probability Test 9
25 bilingual MCQs from Probability, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Designed for cross-exam quantitative aptitude practice with preserved ₹, ×, %, ratios and Hindi wording.
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- Probability — Without replacement
1. A bag contains 5 red and 6 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 5 लाल और 6 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।
- A. 5/11
- B. 51/220
- C. 29/220
- D. 2/11 (Correct)
Explanation: Without replacement: P(two red) = 5/11 × 4/10 = 2/11. / बिना replacement: P(दोनों लाल) = 5/11 × 4/10 = 2/11.
- Probability — Without replacement
2. A bag contains 6 red and 7 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 6 लाल और 7 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।
- A. 6/13
- B. 5/26 (Correct)
- C. 63/260
- D. 37/260
Explanation: Without replacement: P(two red) = 6/13 × 5/12 = 5/26. / बिना replacement: P(दोनों लाल) = 6/13 × 5/12 = 5/26.
- Probability — Card combination probability
3. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।
- A. 1/221 (Correct)
- B. 3/221
- C. 2/221
- D. 1/13
Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.
- Probability — Card combination probability
4. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।
- A. 1/221 (Correct)
- B. 3/221
- C. 2/221
- D. 1/13
Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.
- Probability — Exactly one event
5. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।
- A. 3/4
- B. 1/8
- C. 1/2 (Correct)
- D. 1/4
Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.
- Probability — Exactly one event
6. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।
- A. 1/2 (Correct)
- B. 1/4
- C. 1/8
- D. 3/4
Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.
- Probability — Complement probability
7. A lot has 17 items including 4 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 17 वस्तुएँ हैं जिनमें 4 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।
- A. 4/17
- B. 29/68 (Correct)
- C. 32/85
- D. 81/170
Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 13C2/17C2 = 29/68. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 13C2/17C2 = 29/68.
- Probability — Complement probability
8. A lot has 10 items including 2 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 10 वस्तुएँ हैं जिनमें 2 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।
- A. 17/45 (Correct)
- B. 1/5
- C. 59/180
- D. 77/180
Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 8C2/10C2 = 17/45. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 8C2/10C2 = 17/45.
- Probability — Two dice sum
9. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।
- A. 1/6 (Correct)
- B. 1/4
- C. 1/12
- D. 1/9
Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.
- Probability — Two dice sum
10. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।
- A. 1/9
- B. 1/12
- C. 1/4
- D. 1/6 (Correct)
Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.
- Probability — Without replacement
11. A bag contains 5 red and 6 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 5 लाल और 6 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।
- A. 5/11
- B. 51/220
- C. 2/11 (Correct)
- D. 29/220
Explanation: Without replacement: P(two red) = 5/11 × 4/10 = 2/11. / बिना replacement: P(दोनों लाल) = 5/11 × 4/10 = 2/11.
- Probability — Without replacement
12. A bag contains 6 red and 7 blue balls. Two balls are drawn without replacement. Find probability both are red. / थैले में 6 लाल और 7 नीली गेंदें हैं। बिना replacement दो गेंदें निकाली गईं। दोनों लाल होने की probability ज्ञात करें।
- A. 5/26 (Correct)
- B. 63/260
- C. 37/260
- D. 6/13
Explanation: Without replacement: P(two red) = 6/13 × 5/12 = 5/26. / बिना replacement: P(दोनों लाल) = 6/13 × 5/12 = 5/26.
- Probability — Card combination probability
13. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।
- A. 3/221
- B. 1/221 (Correct)
- C. 2/221
- D. 1/13
Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.
- Probability — Card combination probability
14. Two cards are drawn from a deck of 52 cards. Find probability that both are aces. / 52 पत्तों की गड्डी से दो पत्ते निकाले गए। दोनों ace होने की probability ज्ञात करें।
- A. 1/13
- B. 3/221
- C. 1/221 (Correct)
- D. 2/221
Explanation: Two aces from 4 aces in 52 cards: probability = 4C2/52C2 = 1/221. / 52 पत्तों में 4 aces हैं। Probability = 4C2/52C2 = 1/221.
- Probability — Exactly one event
15. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।
- A. 1/8
- B. 1/2 (Correct)
- C. 3/4
- D. 1/4
Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.
- Probability — Exactly one event
16. Two coins are tossed. Find probability of getting exactly one head. / दो सिक्के उछाले गए। ठीक एक head आने की probability ज्ञात करें।
- A. 1/8
- B. 3/4
- C. 1/2 (Correct)
- D. 1/4
Explanation: Outcomes: HH, HT, TH, TT. Exactly one head: HT, TH = 2 outcomes. Probability=2/4=1/2. / परिणाम: HH, HT, TH, TT. ठीक एक head: HT, TH = 2 परिणाम। Probability=2/4=1/2.
- Probability — Complement probability
17. A lot has 11 items including 2 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 11 वस्तुएँ हैं जिनमें 2 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।
- A. 19/55 (Correct)
- B. 2/11
- C. 87/220
- D. 13/44
Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 9C2/11C2 = 19/55. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 9C2/11C2 = 19/55.
- Probability — Complement probability
18. A lot has 12 items including 3 defective items. Two are selected. Find probability that at least one is defective. / एक lot में 12 वस्तुएँ हैं जिनमें 3 defective हैं। दो चुनी जाती हैं। कम से कम एक defective होने की probability ज्ञात करें।
- A. 5/11 (Correct)
- B. 89/220
- C. 1/4
- D. 111/220
Explanation: P(at least one defective) = 1 − P(no defective) = 1 − 9C2/12C2 = 5/11. / P(कम से कम एक defective) = 1 − P(कोई defective नहीं) = 1 − 9C2/12C2 = 5/11.
- Probability — Two dice sum
19. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।
- A. 1/9
- B. 1/4
- C. 1/12
- D. 1/6 (Correct)
Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.
- Probability — Two dice sum
20. Two dice are thrown. Find probability that the sum is 7. / दो पासे फेंके गए। योग 7 आने की probability ज्ञात करें।
- A. 1/6 (Correct)
- B. 1/9
- C. 1/4
- D. 1/12
Explanation: Sum 7 outcomes: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6. Probability=6/36=1/6. / योग 7 के परिणाम: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)=6. Probability=6/36=1/6.
- Probability — Percentage / प्रतिशत
21. 20% of 800 is: / 800 का 20% कितना है?
- A. 150
- B. 160 (Correct)
- C. 170
- D. 180
Explanation: 20% = 20/100, so answer = 160. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।
- Probability — Profit-Loss / लाभ-हानि
22. An article bought for Rs 850 is sold at 12.5% profit. Find SP. / Rs 850 में खरीदी वस्तु 12.5% लाभ पर बेची गई। SP ज्ञात करें।
- A. Rs 916
- B. Rs 956 (Correct)
- C. Rs 996
- D. Rs 1036
Explanation: SP = CP x (100 + profit%)/100 = 850 x 112.5/100 = Rs 956. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।
- Probability — Time & Work / समय और कार्य
23. A finishes a work in 12 days and B in 18 days. Together they finish in: / A 12 दिन और B 18 दिन में काम पूरा करते हैं। साथ में समय?
- A. 6.2 days
- B. 7.2 days (Correct)
- C. 8.2 days
- D. 9.2 days
Explanation: Combined time = ab/(a+b) = 12 x 18 / 30 = 7.2 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।
- Probability — Speed Conversion / चाल परिवर्तन
24. 108 km/h equals: / 108 किमी/घंटा बराबर है:
- A. 27 m/s
- B. 30 m/s (Correct)
- C. 33 m/s
- D. 35 m/s
Explanation: km/h to m/s conversion uses x 5/18. 108 x 5/18 = 30. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।
- Probability — Simplification / सरलीकरण
25. Simplify: 24 x 15 + 24 - 15. / सरल करें: 24 x 15 + 24 - 15.
- A. 361
- B. 369 (Correct)
- C. 377
- D. 385
Explanation: Apply BODMAS: 360 + 24 - 15 = 369. / पहले गुणा, फिर जोड़-घटाव करें।