Compound Interest Test 18
Bilingual timed test with proper DI visuals, clean Hindi and detailed solutions.
Compound Interest Test 18
25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.
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- Compound Interest — CI plus bonus
1. A fixed deposit of ₹33,000 compounds at 10% for 2 years and then gets a bonus of ₹750. Find final amount. / ₹33,000 की FD 10% पर 2 वर्ष चक्रवृद्धि से बढ़ती है और फिर ₹750 बोनस मिलता है। अंतिम राशि ज्ञात करें।
- A. ₹39,930
- B. ₹40,680 (Correct)
- C. ₹40,380
- D. ₹40,980
Explanation: Final amount = 33000×1.1^2 + 750 = ₹40,680. / अंतिम राशि = 33000×1.1^2 + 750 = ₹40,680।
- Compound Interest — CI after tax
2. A deposit of ₹42,000 earns 12% annual CI for 2 years. If 10% of interest is deducted as tax, what amount is received? / ₹42,000 जमा पर 12% वार्षिक CI 2 वर्ष के लिए मिलता है। यदि ब्याज का 10% कर कटता है, तो प्राप्त राशि कितनी होगी?
- A. ₹52,684.80
- B. ₹51,866.32
- C. ₹51,366.32
- D. ₹51,616.32 (Correct)
Explanation: CI = ₹10,684.80, tax = ₹1,068.48; received = amount − tax = ₹51,616.32. / CI = ₹10,684.80, कर = ₹1,068.48; प्राप्त राशि = राशि − कर = ₹51,616.32।
- Compound Interest — Reverse principal hard
3. If the compound amount after 3 years at 10% is ₹56,240, find the principal. (Set 343) / यदि 10% पर 3 वर्ष बाद चक्रवृद्धि राशि ₹56,240 है, तो मूलधन ज्ञात करें। (सेट 343)
- A. ₹41,253.94
- B. ₹42,253.94 (Correct)
- C. ₹43,261.54
- D. ₹43,253.94
Explanation: P = A/1.1^3 = ₹42,253.94. / P = A/1.1^3 = ₹42,253.94।
- Compound Interest — Half-yearly hard
4. A sum is compounded half-yearly at 18% p.a. for 3 years. Find CI on ₹40,000. / ₹40,000 राशि 18% वार्षिक दर से 3 वर्ष तक अर्धवार्षिक चक्रवृद्धि पर है। CI ज्ञात करें।
- A. ₹27,584.00
- B. ₹27,084.00 (Correct)
- C. ₹21,600
- D. ₹26,584.00
Explanation: Half-yearly rate = 9%, periods = 6. CI = 40000[(1.09)^6−1] = ₹27,084.00. / अर्धवार्षिक दर = 9%, अवधियाँ = 6। CI = 40000[(1.09)^6−1] = ₹27,084.00।
- Compound Interest — Successive CI rates
5. A PO-level scheme compounds ₹35,000 at 8%, 10% and 12% in three successive years. Find total CI. / PO-स्तर की योजना में ₹35,000 पर तीन क्रमिक वर्षों में 8%, 10% और 12% चक्रवृद्धि लगती है। कुल CI ज्ञात करें।
- A. ₹10,500
- B. ₹11,069.60
- C. ₹11,569.60 (Correct)
- D. ₹12,069.60
Explanation: CI = 35000×1.08×1.10×1.12 − 35000 = ₹11,569.60. / CI = 35000×1.08×1.10×1.12 − 35000 = ₹11,569.60।
- Compound Interest — CI-SI three years
6. For 3 years at 12% p.a., find CI−SI on ₹27,000. (Set 346) / ₹27,000 पर 12% वार्षिक दर से 3 वर्ष के लिए CI−SI ज्ञात करें। (सेट 346)
- A. ₹388.80
- B. ₹1,213.06 (Correct)
- C. ₹1,113.06
- D. ₹1,313.06
Explanation: CI−SI = ₹10,933.06−₹9,720 = ₹1,213.06. / CI−SI = ₹10,933.06−₹9,720 = ₹1,213.06।
- Compound Interest — Quarterly two years
7. Find CI on ₹24,000 for 2 years at 16% p.a. compounded quarterly. / ₹24,000 पर 16% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक हो।
- A. ₹8,845.66 (Correct)
- B. ₹7,680
- C. ₹8,545.66
- D. ₹9,145.66
Explanation: Quarterly rate = 4%, periods = 8. CI = 24000[(1.04)^8−1] = ₹8,845.66. / त्रैमासिक दर = 4%, अवधियाँ = 8। CI = 24000[(1.04)^8−1] = ₹8,845.66।
- Compound Interest — Compound growth and fall
8. A fund grows by 20% in each of first two years but falls by 10% in the third year. If initial value is ₹35,000, find net gain/loss. / एक फंड पहले दो वर्षों में प्रत्येक वर्ष 20% बढ़ता है लेकिन तीसरे वर्ष 10% घटता है। प्रारंभिक मूल्य ₹35,000 है। शुद्ध लाभ/हानि ज्ञात करें।
- A. ₹45,360
- B. ₹10,160
- C. ₹10,360 (Correct)
- D. ₹10,560
Explanation: Final value = 35000×1.2×1.2×0.9 = ₹45,360; net gain = ₹10,360. / अंतिम मूल्य = 35000×1.2×1.2×0.9 = ₹45,360; शुद्ध लाभ = ₹10,360।
- Compound Interest — CI plus bonus
9. A fixed deposit of ₹29,000 compounds at 10% for 2 years and then gets a bonus of ₹750. Find final amount. (Set 349) / ₹29,000 की FD 10% पर 2 वर्ष चक्रवृद्धि से बढ़ती है और फिर ₹750 बोनस मिलता है। अंतिम राशि ज्ञात करें। (सेट 349)
- A. ₹35,840 (Correct)
- B. ₹35,090
- C. ₹36,140
- D. ₹35,540
Explanation: Final amount = 29000×1.1^2 + 750 = ₹35,840. / अंतिम राशि = 29000×1.1^2 + 750 = ₹35,840।
- Compound Interest — CI after tax
10. A deposit of ₹40,000 earns 12% annual CI for 2 years. If 10% of interest is deducted as tax, what amount is received? / ₹40,000 जमा पर 12% वार्षिक CI 2 वर्ष के लिए मिलता है। यदि ब्याज का 10% कर कटता है, तो प्राप्त राशि कितनी होगी?
- A. ₹48,908.40
- B. ₹50,176
- C. ₹49,158.40 (Correct)
- D. ₹49,408.40
Explanation: CI = ₹10,176, tax = ₹1,017.60; received = amount − tax = ₹49,158.40. / CI = ₹10,176, कर = ₹1,017.60; प्राप्त राशि = राशि − कर = ₹49,158.40।
- Compound Interest — Reverse principal hard
11. If the compound amount after 3 years at 10% is ₹56,240, find the principal. (Set 351) / यदि 10% पर 3 वर्ष बाद चक्रवृद्धि राशि ₹56,240 है, तो मूलधन ज्ञात करें। (सेट 351)
- A. ₹42,253.94 (Correct)
- B. ₹43,261.54
- C. ₹43,253.94
- D. ₹41,253.94
Explanation: P = A/1.1^3 = ₹42,253.94. / P = A/1.1^3 = ₹42,253.94।
- Compound Interest — Half-yearly hard
12. A sum is compounded half-yearly at 18% p.a. for 3 years. Find CI on ₹38,000. / ₹38,000 राशि 18% वार्षिक दर से 3 वर्ष तक अर्धवार्षिक चक्रवृद्धि पर है। CI ज्ञात करें।
- A. ₹20,520
- B. ₹25,229.80
- C. ₹25,729.80 (Correct)
- D. ₹26,229.80
Explanation: Half-yearly rate = 9%, periods = 6. CI = 38000[(1.09)^6−1] = ₹25,729.80. / अर्धवार्षिक दर = 9%, अवधियाँ = 6। CI = 38000[(1.09)^6−1] = ₹25,729.80।
- Compound Interest — Successive CI rates
13. A PO-level scheme compounds ₹33,000 at 8%, 10% and 12% in three successive years. Find total CI. / PO-स्तर की योजना में ₹33,000 पर तीन क्रमिक वर्षों में 8%, 10% और 12% चक्रवृद्धि लगती है। कुल CI ज्ञात करें।
- A. ₹11,408.48
- B. ₹9,900
- C. ₹10,408.48
- D. ₹10,908.48 (Correct)
Explanation: CI = 33000×1.08×1.10×1.12 − 33000 = ₹10,908.48. / CI = 33000×1.08×1.10×1.12 − 33000 = ₹10,908.48।
- Compound Interest — CI-SI three years
14. For 3 years at 12% p.a., find CI−SI on ₹27,000. (Set 354) / ₹27,000 पर 12% वार्षिक दर से 3 वर्ष के लिए CI−SI ज्ञात करें। (सेट 354)
- A. ₹388.80
- B. ₹1,113.06
- C. ₹1,213.06 (Correct)
- D. ₹1,313.06
Explanation: CI−SI = ₹10,933.06−₹9,720 = ₹1,213.06. / CI−SI = ₹10,933.06−₹9,720 = ₹1,213.06।
- Compound Interest — Quarterly two years
15. Find CI on ₹25,000 for 2 years at 16% p.a. compounded quarterly. / ₹25,000 पर 16% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक हो।
- A. ₹9,514.23
- B. ₹8,914.23
- C. ₹9,214.23 (Correct)
- D. ₹8,000
Explanation: Quarterly rate = 4%, periods = 8. CI = 25000[(1.04)^8−1] = ₹9,214.23. / त्रैमासिक दर = 4%, अवधियाँ = 8। CI = 25000[(1.04)^8−1] = ₹9,214.23।
- Compound Interest — Compound growth and fall
16. A fund grows by 20% in each of first two years but falls by 10% in the third year. If initial value is ₹33,000, find net gain/loss. / एक फंड पहले दो वर्षों में प्रत्येक वर्ष 20% बढ़ता है लेकिन तीसरे वर्ष 10% घटता है। प्रारंभिक मूल्य ₹33,000 है। शुद्ध लाभ/हानि ज्ञात करें।
- A. ₹9,568
- B. ₹9,968
- C. ₹42,768
- D. ₹9,768 (Correct)
Explanation: Final value = 33000×1.2×1.2×0.9 = ₹42,768; net gain = ₹9,768. / अंतिम मूल्य = 33000×1.2×1.2×0.9 = ₹42,768; शुद्ध लाभ = ₹9,768।
- Compound Interest — CI plus bonus
17. A fixed deposit of ₹31,000 compounds at 10% for 2 years and then gets a bonus of ₹750. Find final amount. (Set 357) / ₹31,000 की FD 10% पर 2 वर्ष चक्रवृद्धि से बढ़ती है और फिर ₹750 बोनस मिलता है। अंतिम राशि ज्ञात करें। (सेट 357)
- A. ₹38,560
- B. ₹38,260 (Correct)
- C. ₹37,960
- D. ₹37,510
Explanation: Final amount = 31000×1.1^2 + 750 = ₹38,260. / अंतिम राशि = 31000×1.1^2 + 750 = ₹38,260।
- Compound Interest — CI after tax
18. A deposit of ₹43,000 earns 12% annual CI for 2 years. If 10% of interest is deducted as tax, what amount is received? / ₹43,000 जमा पर 12% वार्षिक CI 2 वर्ष के लिए मिलता है। यदि ब्याज का 10% कर कटता है, तो प्राप्त राशि कितनी होगी?
- A. ₹53,095.28
- B. ₹52,595.28
- C. ₹52,845.28 (Correct)
- D. ₹53,939.20
Explanation: CI = ₹10,939.20, tax = ₹1,093.92; received = amount − tax = ₹52,845.28. / CI = ₹10,939.20, कर = ₹1,093.92; प्राप्त राशि = राशि − कर = ₹52,845.28।
- Compound Interest — Reverse principal hard
19. If the compound amount after 3 years at 10% is ₹56,240, find the principal. (Set 359) / यदि 10% पर 3 वर्ष बाद चक्रवृद्धि राशि ₹56,240 है, तो मूलधन ज्ञात करें। (सेट 359)
- A. ₹43,261.54
- B. ₹43,253.94
- C. ₹41,253.94
- D. ₹42,253.94 (Correct)
Explanation: P = A/1.1^3 = ₹42,253.94. / P = A/1.1^3 = ₹42,253.94।
- Compound Interest — Half-yearly hard
20. A sum is compounded half-yearly at 18% p.a. for 3 years. Find CI on ₹36,000. / ₹36,000 राशि 18% वार्षिक दर से 3 वर्ष तक अर्धवार्षिक चक्रवृद्धि पर है। CI ज्ञात करें।
- A. ₹24,875.60
- B. ₹24,375.60 (Correct)
- C. ₹23,875.60
- D. ₹19,440
Explanation: Half-yearly rate = 9%, periods = 6. CI = 36000[(1.09)^6−1] = ₹24,375.60. / अर्धवार्षिक दर = 9%, अवधियाँ = 6। CI = 36000[(1.09)^6−1] = ₹24,375.60।
- Compound Interest — Percentage / प्रतिशत
21. 20% of 750 is: / 750 का 20% कितना है?
- A. 140
- B. 150 (Correct)
- C. 160
- D. 170
Explanation: 20% = 20/100, so answer = 150. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।
- Compound Interest — Profit-Loss / लाभ-हानि
22. An article bought for Rs 950 is sold at 20% profit. Find SP. / Rs 950 में खरीदी वस्तु 20% लाभ पर बेची गई। SP ज्ञात करें।
- A. Rs 1100
- B. Rs 1140 (Correct)
- C. Rs 1180
- D. Rs 1220
Explanation: SP = CP x (100 + profit%)/100 = 950 x 120/100 = Rs 1140. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।
- Compound Interest — Time & Work / समय और कार्य
23. A finishes a work in 12 days and B in 18 days. Together they finish in: / A 12 दिन और B 18 दिन में काम पूरा करते हैं। साथ में समय?
- A. 6.2 days
- B. 7.2 days (Correct)
- C. 8.2 days
- D. 9.2 days
Explanation: Combined time = ab/(a+b) = 12 x 18 / 30 = 7.2 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।
- Compound Interest — Speed Conversion / चाल परिवर्तन
24. 72 km/h equals: / 72 किमी/घंटा बराबर है:
- A. 17 m/s
- B. 20 m/s (Correct)
- C. 23 m/s
- D. 25 m/s
Explanation: km/h to m/s conversion uses x 5/18. 72 x 5/18 = 20. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।
- Compound Interest — Simplification / सरलीकरण
25. Simplify: 22 x 13 + 22 - 13. / सरल करें: 22 x 13 + 22 - 13.
- A. 287
- B. 295 (Correct)
- C. 303
- D. 311
Explanation: Apply BODMAS: 286 + 22 - 13 = 295. / पहले गुणा, फिर जोड़-घटाव करें।