Compound Interest Test 7

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Batch 3 | Visual DI

Compound Interest Test 7

25 bilingual MCQs from Compound Interest, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Graph questions render as proper visual charts with preserved Hindi, ₹, ×, %, ratios and equations.

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25 min

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+1 / -0.25

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Compound Interest | 25 questions

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Preview all 25 questions in Compound Interest Test 7 (no login required)

Compound Interest — Variable rate CI
1. Raipur branch invests ₹17,000 for two years at variable compound rates 11% and 6%. Find total CI. / Raipur शाखा ने ₹17,000 को दो वर्षों के लिए 11% और 6% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹3,202.20
- B. ₹2,890
- C. ₹2,802.20
- D. ₹3,002.20 (Correct)
Explanation: Amount = P(1+11/100)(1+6/100). CI = ₹3,002.20. / राशि = P(1+11/100)(1+6/100)। CI = ₹3,002.20।
Compound Interest — Excess CI
2. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹22,000. / ₹22,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें।
- A. ₹316.80 (Correct)
- B. ₹5,280
- C. ₹266.80
- D. ₹366.80
Explanation: Excess = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80. / अधिकता = P(r/100)^2 = 22000×(12/100)^2 = ₹316.80।
Compound Interest — Quarterly compounding
3. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो।
- A. ₹1,942.63
- B. ₹1,822.63
- C. ₹1,800
- D. ₹1,882.63 (Correct)
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
Compound Interest — Three-year amount
4. The amount after 3 years on ₹14,000 at 10% annual compounding is: / ₹14,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी:
- A. ₹18,200
- B. ₹18,634 (Correct)
- C. ₹18,534
- D. ₹18,734
Explanation: Amount = 14000×1.1^3 = ₹18,634. / राशि = 14000×1.1^3 = ₹18,634।
Compound Interest — Principal from CI amount
5. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें।
- A. ₹19,500
- B. ₹20,166.67
- C. ₹20,000 (Correct)
- D. ₹20,500
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
Compound Interest — Net CI
6. A deposit earns CI at 15% for 2 years on ₹16,000. If ₹250 service charge is deducted from interest, what net interest remains? / ₹16,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹250 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹4,810
- B. ₹5,160
- C. ₹5,010
- D. ₹4,910 (Correct)
Explanation: CI = ₹5,160. Net interest = ₹5,160−₹250 = ₹4,910. / CI = ₹5,160। शुद्ध ब्याज = ₹5,160−₹250 = ₹4,910।
Compound Interest — Compound amount vs SI amount
7. For ₹28,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? / ₹28,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है?
- A. ₹380
- B. ₹294
- C. ₹180
- D. ₹280 (Correct)
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹280. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹280।
Compound Interest — Half-yearly two years
8. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो।
- A. ₹9,746.10 (Correct)
- B. ₹9,946.10
- C. ₹9,546.10
- D. ₹8,400
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
Compound Interest — Growth model
9. A savings balance of ₹25,000 grows by 13% compound rate each year. What is the balance after 2 years? / ₹25,000 की बचत राशि प्रति वर्ष 13% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी?
- A. ₹31,822.50
- B. ₹31,500
- C. ₹31,922.50 (Correct)
- D. ₹32,022.50
Explanation: Balance = 25000(1+13/100)^2 = ₹31,922.50. / शेष राशि = 25000(1+13/100)^2 = ₹31,922.50।
Compound Interest — Three-year CI
10. Find the compound interest on ₹18,000 at 5% per annum for 3 years. / ₹18,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें।
- A. ₹2,837.25 (Correct)
- B. ₹2,987.25
- C. ₹2,700
- D. ₹2,687.25
Explanation: CI = P[(1+r/100)^3−1] = ₹2,837.25. / CI = P[(1+r/100)^3−1] = ₹2,837.25।
Compound Interest — Variable rate CI
11. Kanpur branch invests ₹20,000 for two years at variable compound rates 12% and 8%. Find total CI. / Kanpur शाखा ने ₹20,000 को दो वर्षों के लिए 12% और 8% की परिवर्तनीय चक्रवृद्धि दरों पर निवेश किया। कुल CI ज्ञात करें।
- A. ₹3,992
- B. ₹4,192 (Correct)
- C. ₹4,000
- D. ₹4,392
Explanation: Amount = P(1+12/100)(1+8/100). CI = ₹4,192. / राशि = P(1+12/100)(1+8/100)। CI = ₹4,192।
Compound Interest — Excess CI
12. At 12% p.a. for 2 years, find the excess of compound interest over simple interest on ₹20,000. / ₹20,000 पर 12% वार्षिक दर से 2 वर्ष में CI का SI से अधिक भाग ज्ञात करें।
- A. ₹238
- B. ₹338
- C. ₹288 (Correct)
- D. ₹4,800
Explanation: Excess = P(r/100)^2 = 20000×(12/100)^2 = ₹288. / अधिकता = P(r/100)^2 = 20000×(12/100)^2 = ₹288।
Compound Interest — Quarterly compounding
13. Find CI on ₹15,000 at 12% p.a. for one year compounded quarterly. (Set 133) / ₹15,000 पर 12% वार्षिक दर से 1 वर्ष का CI ज्ञात करें, जब ब्याज त्रैमासिक संयोजित हो। (सेट 133)
- A. ₹1,882.63 (Correct)
- B. ₹1,942.63
- C. ₹1,800
- D. ₹1,822.63
Explanation: Quarterly rate = 3%, periods = 4. CI = 15000[(1.03)^4−1] = ₹1,882.63. / त्रैमासिक दर = 3%, अवधियाँ = 4। CI = 15000[(1.03)^4−1] = ₹1,882.63।
Compound Interest — Three-year amount
14. The amount after 3 years on ₹16,000 at 10% annual compounding is: / ₹16,000 पर 10% वार्षिक चक्रवृद्धि से 3 वर्ष बाद राशि होगी:
- A. ₹20,800
- B. ₹21,296 (Correct)
- C. ₹21,396
- D. ₹21,196
Explanation: Amount = 16000×1.1^3 = ₹21,296. / राशि = 16000×1.1^3 = ₹21,296।
Compound Interest — Principal from CI amount
15. A sum amounts to ₹24,200 in 2 years at 10% compound interest. Find the principal. (Set 135) / एक राशि 10% चक्रवृद्धि ब्याज पर 2 वर्ष में ₹24,200 हो जाती है। मूलधन ज्ञात करें। (सेट 135)
- A. ₹20,000 (Correct)
- B. ₹20,500
- C. ₹20,166.67
- D. ₹19,500
Explanation: P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000. / P = A/(1.1)^2 = ₹24,200/1.21 = ₹20,000।
Compound Interest — Net CI
16. A deposit earns CI at 15% for 2 years on ₹19,000. If ₹100 service charge is deducted from interest, what net interest remains? / ₹19,000 जमा पर 15% से 2 वर्ष का CI मिलता है। यदि ब्याज से ₹100 सेवा शुल्क कटता है, तो शुद्ध ब्याज कितना बचेगा?
- A. ₹6,127.50
- B. ₹6,027.50 (Correct)
- C. ₹5,927.50
- D. ₹6,328.87
Explanation: CI = ₹6,127.50. Net interest = ₹6,127.50−₹100 = ₹6,027.50. / CI = ₹6,127.50। शुद्ध ब्याज = ₹6,127.50−₹100 = ₹6,027.50।
Compound Interest — Compound amount vs SI amount
17. For ₹26,000 at 10% for 2 years, by how much is compound amount greater than simple interest amount? / ₹26,000 पर 10% से 2 वर्ष के लिए चक्रवृद्धि राशि साधारण ब्याज राशि से कितनी अधिक है?
- A. ₹160
- B. ₹360
- C. ₹273
- D. ₹260 (Correct)
Explanation: Compound amount − Simple amount = CI − SI = P(r/100)^2 = ₹260. / चक्रवृद्धि राशि − साधारण राशि = CI − SI = P(r/100)^2 = ₹260।
Compound Interest — Half-yearly two years
18. Calculate CI on ₹21,000 for 2 years at 20% p.a. compounded half-yearly. (Set 138) / ₹21,000 पर 20% वार्षिक दर से 2 वर्ष का CI ज्ञात करें, जब ब्याज अर्धवार्षिक संयोजित हो। (सेट 138)
- A. ₹9,746.10 (Correct)
- B. ₹9,946.10
- C. ₹9,546.10
- D. ₹8,400
Explanation: Half-yearly rate = 10%, periods = 4. CI = 21000[(1.10)^4−1] = ₹9,746.10. / अर्धवार्षिक दर = 10%, अवधियाँ = 4। CI = 21000[(1.10)^4−1] = ₹9,746.10।
Compound Interest — Growth model
19. A savings balance of ₹23,000 grows by 11% compound rate each year. What is the balance after 2 years? / ₹23,000 की बचत राशि प्रति वर्ष 11% चक्रवृद्धि दर से बढ़ती है। 2 वर्ष बाद शेष राशि कितनी होगी?
- A. ₹28,238.30
- B. ₹28,060
- C. ₹28,438.30
- D. ₹28,338.30 (Correct)
Explanation: Balance = 23000(1+11/100)^2 = ₹28,338.30. / शेष राशि = 23000(1+11/100)^2 = ₹28,338.30।
Compound Interest — Three-year CI
20. Find the compound interest on ₹19,000 at 5% per annum for 3 years. / ₹19,000 पर 5% वार्षिक दर से 3 वर्ष का चक्रवृद्धि ब्याज ज्ञात करें।
- A. ₹3,144.88
- B. ₹2,850
- C. ₹2,844.88
- D. ₹2,994.88 (Correct)
Explanation: CI = P[(1+r/100)^3−1] = ₹2,994.88. / CI = P[(1+r/100)^3−1] = ₹2,994.88।
Compound Interest — Percentage / प्रतिशत
21. 15% of 575 is: / 575 का 15% कितना है?
- A. 76.25
- B. 86.25 (Correct)
- C. 96.25
- D. 106.25
Explanation: 15% = 15/100, so answer = 86.25. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।
Compound Interest — Profit-Loss / लाभ-हानि
22. An article bought for Rs 800 is sold at 10% profit. Find SP. / Rs 800 में खरीदी वस्तु 10% लाभ पर बेची गई। SP ज्ञात करें।
- A. Rs 840
- B. Rs 880 (Correct)
- C. Rs 920
- D. Rs 960
Explanation: SP = CP x (100 + profit%)/100 = 800 x 110/100 = Rs 880. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।
Compound Interest — Time & Work / समय और कार्य
23. A finishes a work in 21 days and B in 27 days. Together they finish in: / A 21 दिन और B 27 दिन में काम पूरा करते हैं। साथ में समय?
- A. 10.8 days
- B. 11.8 days (Correct)
- C. 12.8 days
- D. 13.8 days
Explanation: Combined time = ab/(a+b) = 21 x 27 / 48 = 11.8 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।
Compound Interest — Speed Conversion / चाल परिवर्तन
24. 90 km/h equals: / 90 किमी/घंटा बराबर है:
- A. 22 m/s
- B. 25 m/s (Correct)
- C. 28 m/s
- D. 30 m/s
Explanation: km/h to m/s conversion uses x 5/18. 90 x 5/18 = 25. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।
Compound Interest — Simplification / सरलीकरण
25. Simplify: 24 x 15 + 24 - 15. / सरल करें: 24 x 15 + 24 - 15.
- A. 361
- B. 369 (Correct)
- C. 377
- D. 385
Explanation: Apply BODMAS: 360 + 24 - 15 = 369. / पहले गुणा, फिर जोड़-घटाव करें।