Mensuration 3D Test 9
Bilingual timed test with clean question text, preserved symbols and detailed solutions.
Mensuration 3D Test 9
25 bilingual MCQs from Mensuration 3D, including 5 fresh LearnAtMyPlace original supplemental questions with detailed solutions. Built for SSC, RRB and banking practice with preserved Hindi, ₹, ×, %, m², cm³ and reasoning symbols.
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Preview all 25 questions in Mensuration 3D Test 9 (no login required)
- Mensuration 3D — Cylinder
1. Using π=22/7, find the volume of a cylinder with radius 14 cm and height 31 cm. / π=22/7 मानकर 14 सेमी त्रिज्या और 31 सेमी ऊँचाई वाले बेलन का आयतन ज्ञात करें।
- A. 19096 (Correct)
- B. 2728
- C. 18942
- D. 19250
Explanation: Volume = πr²h = 22/7×14²×31 = 19096 cm³. / आयतन = πr²h = 22/7×14²×31 = 19096 घन सेमी।
- Mensuration 3D — Cone
2. Find the curved surface area of a cone with radius 13 cm and slant height 17 cm. Use π=22/7. / π=22/7 मानकर 13 सेमी त्रिज्या और 17 सेमी तिर्यक ऊँचाई वाले शंकु का वक्र पृष्ठीय क्षेत्रफल ज्ञात करें।
- A. 681.57
- B. 531.14
- C. 694.57 (Correct)
- D. 707.57
Explanation: CSA = πrl = 22/7×13×17 = 694.57 cm². / वक्र पृष्ठीय क्षेत्रफल = πrl = 22/7×13×17 = 694.57 वर्ग सेमी।
- Mensuration 3D — Cuboid tank
3. A cuboidal tank measures 14 m × 15 m × 16 m. If water costs ₹3 per m³, find the cost to fill it completely. / एक घनाभाकार टैंक 14 मीटर × 15 मीटर × 16 मीटर है। यदि पानी की लागत ₹3 प्रति घन मीटर है, तो इसे पूरा भरने की लागत ज्ञात करें।
- A. 3360
- B. 10077
- C. 10080 (Correct)
- D. 10083
Explanation: Volume = 14×15×16 = 3360 m³; cost = 3360×3 = ₹10080. / आयतन = 14×15×16 = 3360 घन मीटर; लागत = 3360×3 = ₹10080।
- Mensuration 3D — Cylinder capacity
4. A cylindrical vessel has radius 9 cm and height 25 cm. How many litres of water can it hold? Use π=22/7. / एक बेलनाकार पात्र की त्रिज्या 9 सेमी और ऊँचाई 25 सेमी है। यह कितने लीटर पानी रख सकता है? π=22/7 लें।
- A. 6.36 (Correct)
- B. 5.36
- C. 7.36
- D. 6364.29
Explanation: Volume = 6364.29 cm³; litres = 6364.29/1000 = 6.36 L. / आयतन = 6364.29 घन सेमी; लीटर = 6364.29/1000 = 6.36 L।
- Mensuration 3D — Cylinder
5. Using π=22/7, find the volume of a cylinder with radius 16 cm and height 22 cm. / π=22/7 मानकर 16 सेमी त्रिज्या और 22 सेमी ऊँचाई वाले बेलन का आयतन ज्ञात करें।
- A. 17546.57
- B. 2212.57
- C. 17700.57 (Correct)
- D. 17854.57
Explanation: Volume = πr²h = 22/7×16²×22 = 17700.57 cm³. / आयतन = πr²h = 22/7×16²×22 = 17700.57 घन सेमी।
- Mensuration 3D — Cone
6. Find the curved surface area of a cone with radius 8 cm and slant height 18 cm. Use π=22/7. / π=22/7 मानकर 8 सेमी त्रिज्या और 18 सेमी तिर्यक ऊँचाई वाले शंकु का वक्र पृष्ठीय क्षेत्रफल ज्ञात करें।
- A. 452.57 (Correct)
- B. 460.57
- C. 201.14
- D. 444.57
Explanation: CSA = πrl = 22/7×8×18 = 452.57 cm². / वक्र पृष्ठीय क्षेत्रफल = πrl = 22/7×8×18 = 452.57 वर्ग सेमी।
- Mensuration 3D — Cuboid tank
7. A cuboidal tank measures 12 m × 16 m × 8 m. If water costs ₹4 per m³, find the cost to fill it completely. / एक घनाभाकार टैंक 12 मीटर × 16 मीटर × 8 मीटर है। यदि पानी की लागत ₹4 प्रति घन मीटर है, तो इसे पूरा भरने की लागत ज्ञात करें।
- A. 1536
- B. 6148
- C. 6140
- D. 6144 (Correct)
Explanation: Volume = 12×16×8 = 1536 m³; cost = 1536×4 = ₹6144. / आयतन = 12×16×8 = 1536 घन मीटर; लागत = 1536×4 = ₹6144।
- Mensuration 3D — Cylinder capacity
8. A cylindrical vessel has radius 15 cm and height 27 cm. How many litres of water can it hold? Use π=22/7. / एक बेलनाकार पात्र की त्रिज्या 15 सेमी और ऊँचाई 27 सेमी है। यह कितने लीटर पानी रख सकता है? π=22/7 लें।
- A. 19092.86
- B. 20.09
- C. 19.09 (Correct)
- D. 18.09
Explanation: Volume = 19092.86 cm³; litres = 19092.86/1000 = 19.09 L. / आयतन = 19092.86 घन सेमी; लीटर = 19092.86/1000 = 19.09 L।
- Mensuration 3D — Mensuration 3D
9. Set 40169: Find the volume of a cuboid of length 10 cm, breadth 13 cm and height 4 cm. / ??? 40169: 10 , 13 ?? 4 ??
- A. 520 cm^3 (Correct)
- B. 510 cm^3
- C. 533 cm^3
- D. 524 cm^3
Explanation: Volume = l x b x h = 520 cm^3.
- Mensuration 3D — Mensuration 3D
10. Set 40170: Find the volume of a cuboid of length 11 cm, breadth 4 cm and height 5 cm. / ??? 40170: 11 , 4 ?? 5 ??
- A. 220 cm^3 (Correct)
- B. 209 cm^3
- C. 224 cm^3
- D. 225 cm^3
Explanation: Volume = l x b x h = 220 cm^3.
- Mensuration 3D — Mensuration 3D
11. Set 40171: Find the volume of a cuboid of length 12 cm, breadth 5 cm and height 6 cm. / ??? 40171: 12 , 5 ?? 6 ??
- A. 360 cm^3 (Correct)
- B. 348 cm^3
- C. 365 cm^3
- D. 366 cm^3
Explanation: Volume = l x b x h = 360 cm^3.
- Mensuration 3D — Mensuration 3D
12. Set 40172: Find the volume of a cuboid of length 13 cm, breadth 6 cm and height 7 cm. / ??? 40172: 13 , 6 ?? 7 ??
- A. 546 cm^3 (Correct)
- B. 533 cm^3
- C. 552 cm^3
- D. 553 cm^3
Explanation: Volume = l x b x h = 546 cm^3.
- Mensuration 3D — Mensuration 3D
13. Set 40173: Find the volume of a cuboid of length 14 cm, breadth 7 cm and height 8 cm. / ??? 40173: 14 , 7 ?? 8 ??
- A. 784 cm^3 (Correct)
- B. 770 cm^3
- C. 791 cm^3
- D. 792 cm^3
Explanation: Volume = l x b x h = 784 cm^3.
- Mensuration 3D — Mensuration 3D
14. Set 40174: Find the volume of a cuboid of length 15 cm, breadth 8 cm and height 9 cm. / ??? 40174: 15 , 8 ?? 9 ??
- A. 1080 cm^3 (Correct)
- B. 1065 cm^3
- C. 1088 cm^3
- D. 1089 cm^3
Explanation: Volume = l x b x h = 1080 cm^3.
- Mensuration 3D — Mensuration 3D
15. Set 40175: Find the volume of a cuboid of length 16 cm, breadth 9 cm and height 10 cm. / ??? 40175: 16 , 9 ?? 10 ??
- A. 1440 cm^3 (Correct)
- B. 1424 cm^3
- C. 1449 cm^3
- D. 1450 cm^3
Explanation: Volume = l x b x h = 1440 cm^3.
- Mensuration 3D — Mensuration 3D
16. Set 40176: Find the volume of a cuboid of length 17 cm, breadth 10 cm and height 3 cm. / ??? 40176: 17 , 10 ?? 3 ??
- A. 510 cm^3 (Correct)
- B. 493 cm^3
- C. 520 cm^3
- D. 513 cm^3
Explanation: Volume = l x b x h = 510 cm^3.
- Mensuration 3D — Mensuration 3D
17. Set 40177: Find the volume of a cuboid of length 18 cm, breadth 11 cm and height 4 cm. / ??? 40177: 18 , 11 ?? 4 ??
- A. 792 cm^3 (Correct)
- B. 774 cm^3
- C. 803 cm^3
- D. 796 cm^3
Explanation: Volume = l x b x h = 792 cm^3.
- Mensuration 3D — Mensuration 3D
18. Set 40178: Find the volume of a cuboid of length 19 cm, breadth 12 cm and height 5 cm. / ??? 40178: 19 , 12 ?? 5 ??
- A. 1140 cm^3 (Correct)
- B. 1121 cm^3
- C. 1152 cm^3
- D. 1145 cm^3
Explanation: Volume = l x b x h = 1140 cm^3.
- Mensuration 3D — Mensuration 3D
19. Set 40179: Find the volume of a cuboid of length 20 cm, breadth 13 cm and height 6 cm. / ??? 40179: 20 , 13 ?? 6 ??
- A. 1560 cm^3 (Correct)
- B. 1540 cm^3
- C. 1573 cm^3
- D. 1566 cm^3
Explanation: Volume = l x b x h = 1560 cm^3.
- Mensuration 3D — Mensuration 3D
20. Set 40180: Find the volume of a cuboid of length 6 cm, breadth 4 cm and height 7 cm. / ??? 40180: 6 , 4 ?? 7 ??
- A. 168 cm^3 (Correct)
- B. 162 cm^3
- C. 172 cm^3
- D. 175 cm^3
Explanation: Volume = l x b x h = 168 cm^3.
- Mensuration 3D — Percentage / प्रतिशत
21. 18% of 700 is: / 700 का 18% कितना है?
- A. 116
- B. 126 (Correct)
- C. 136
- D. 146
Explanation: 18% = 18/100, so answer = 126. / प्रतिशत को 100 से भाग देकर मूल संख्या से गुणा करें।
- Mensuration 3D — Profit-Loss / लाभ-हानि
22. An article bought for Rs 950 is sold at 20% profit. Find SP. / Rs 950 में खरीदी वस्तु 20% लाभ पर बेची गई। SP ज्ञात करें।
- A. Rs 1100
- B. Rs 1140 (Correct)
- C. Rs 1180
- D. Rs 1220
Explanation: SP = CP x (100 + profit%)/100 = 950 x 120/100 = Rs 1140. / लाभ प्रतिशत जोड़कर विक्रय मूल्य निकालें।
- Mensuration 3D — Time & Work / समय और कार्य
23. A finishes a work in 24 days and B in 30 days. Together they finish in: / A 24 दिन और B 30 दिन में काम पूरा करते हैं। साथ में समय?
- A. 12.3 days
- B. 13.3 days (Correct)
- C. 14.3 days
- D. 15.3 days
Explanation: Combined time = ab/(a+b) = 24 x 30 / 54 = 13.3 days. / संयुक्त कार्य में दरें जोड़ी जाती हैं।
- Mensuration 3D — Speed Conversion / चाल परिवर्तन
24. 72 km/h equals: / 72 किमी/घंटा बराबर है:
- A. 17 m/s
- B. 20 m/s (Correct)
- C. 23 m/s
- D. 25 m/s
Explanation: km/h to m/s conversion uses x 5/18. 72 x 5/18 = 20. / किमी/घंटा को मी/से में बदलने के लिए 5/18 से गुणा करें।
- Mensuration 3D — Simplification / सरलीकरण
25. Simplify: 20 x 13 + 20 - 13. / सरल करें: 20 x 13 + 20 - 13.
- A. 259
- B. 267 (Correct)
- C. 275
- D. 283
Explanation: Apply BODMAS: 260 + 20 - 13 = 267. / पहले गुणा, फिर जोड़-घटाव करें।