Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Alcohols, Phenols and Ethers/
Question 780007
JEE Chemistry · Medium

Alcohols, Phenols and Ethers: Kolbe reaction MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Kolbe reactionMediumQuestion 780007

Question

Sodium phenoxide + CO₂ at 125°C and pressure gives (Kolbe reaction):
  1. A
    Sodium salicylate (2-hydroxybenzoate)
    Correct
  2. B
    Sodium benzoate
  3. C
    Phenol only
  4. D
    Carbon

Correct answer

Sodium salicylate (2-hydroxybenzoate)

Explanation

Kolbe reaction: C₆H₅ONa + CO₂ → (125°C, 5 atm) → sodium 2-hydroxybenzoate (salicylate). Acidification gives salicylic acid, precursor to aspirin (acetylsalicylic acid).

Review Alcohols, Phenols and Ethers notesStart timed chapter practice